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12:19 AM
anyone played with quantum frames of reference here?
 
12:47 AM
Happen to have any good references? I've never even thought of reference frames in qm, but am intrigued
 
1:00 AM
Good morning/evening/night for everyone!

I would like to know when the very first concept of "warpdrive" was born (the first metric in GR literature that shows this concept).

Thank you.
I would like to know when the concept of "warpdrive" was born (the very first metric in GR literature that shows this concept).
**
 
1:19 AM
Try Googling.
 
1:57 AM
Is an operator just a map $A: \mathcal{H} \to \mathcal{H}$?
 
 
1 hour later…
3:13 AM
@bolbteppa yes indeed it was quite hardcore. I had to do it on the board too. In retrospect it was a bit funny. I don't exactly recall the details of the question but he said something along the lines of he could do it while drunk on vodka. hehehehe . Yes, I will be getting the degree really fast. I also yes, I think a good internship will take me very far.
 
3:56 AM
@JohnRennie Please, how old are you?
 
A warp drive is a fictitious faster-than-light (FTL) spacecraft propulsion system in many science fiction works, most notably Star Trek. A spacecraft equipped with a warp drive may travel at speeds greater than that of light by many orders of magnitude. In contrast to some other fictitious FTL technologies such as a jump drive or hyperdrive, the warp drive does not permit instantaneous travel between two points, but rather involves a measurable passage of time which is pertinent to the concept. Spacecraft at warp velocity would continue to interact with objects in "normal space". The general concept...
 
Cool
 
@JackClerk Old
 
@JohnRennie Sorry, for the question. I've read your profile and I didn't expected the phrase "my PhD is listed on the web even though the World Wide Web didn't exist at the time!"
Anyway...
 
Well I finished my PhD in 1986
 
4:09 AM
hmmm
I'm a undergradute (2 year) yet...
As you said that you're from cambridge.... have you ever crossroads with Hawking?
 
I used to see him occasionally (he was already in a wheelchair by then) but I wasn't in his department so I never had any interaction with him.
 
I see...
 
 
2 hours later…
6:22 AM
Why is the shape of the crankshafts (the black rotating things under the pistons) so weird? Can't they just be circular? Maybe the shape is like that to produce rotating motion?
Maybe there is some weight spreading or something to do with the weights and center of mass?
Also what pushes the piston upwards when the exhaust gasses have to be taken out? The pistons go up, but what makes them? Maybe the crankshafts push them up?
 
 
1 hour later…
7:53 AM
To be checked: machine learning that crawl through literature and identify for gaps. Requires being able to predict unknown unknown questions
A crankshaft—related to crank—is a mechanical part able to perform a conversion between reciprocating motion and rotational motion. In a reciprocating engine, it translates reciprocating motion of the piston into rotational motion; whereas in a reciprocating compressor, it converts the rotational motion into reciprocating motion. In order to do the conversion between two motions, the crankshaft has "crank throws" or "crankpins", additional bearing surfaces whose axis is offset from that of the crank, to which the "big ends" of the connecting rods from each cylinder attach. It is typically connected...
Crankshafts concert up down motion into rotational motion, thus those extra bearings provide the geometry to do so
 
8:24 AM
@Secret Ok thanks, I'll give it a look.
 
Anonymous
8:44 AM
@lılostafa Apparently it's easy make those cylinder 3D bar plots using MATLAB. See bar3, Color 3-D Bars by Height and cylinder
 
Anonymous
The colour variation also depends on the individual heights (in the graph you posted). For that, see the second link.
 
Anonymous
9:28 AM
@lılostafa A bit of add-on. The bar3 doesn't have any direct option to change the style to cylinder. So probably you'd have to create your own cylindrical_bar3_fucntion(). Maybe start with creating individual cylinders of your required height and X,Y location and then overlap them using hold on. For colour variation, see: in.mathworks.com/matlabcentral/answers/…
 
Anonymous
And ffs change the first symbol of your name. It seems impossible to ping you directly. XD
 
10:55 AM
it's like tonight the moon will be in its full phase, but as I saw the moon last night, it had been quite round.
 
11:43 AM
@Blue Thanks for looking into it; Last night I did this using cylinder but two problems remained: first, since my array of cylinders isn't necessarily square-shaped, the cylinders are shown as elliptical cylinders and I have to scale them manually in every case to compensate for that, which becomes very annoying. 2nd, apparently Matlab cannot export its 3D plots in true vector format. Even when you export as svg, it's actually rasterized. (since version 2014b)
 
12:40 PM
some newspaper say that a shift of the earth's magnetic poles will be somewhen near in the future.

But they don't shift instantly - many even say it takes up to 3000 year, so how does it makes sense to say "a shift is about to happen in near future"?
 
1:39 PM
@watchme I read on web it may shift within 100 years.
 
Thats a bit more realistic yeah, since the poles are now shifting with a velocity of around 55-60km/year
(which I have not measured myself of course)
 
2:34 PM
@watchme I suspect you mean a reversal rather than a shift i.e. the north and south magnetic fields will swap places.
 
@watchme I don't know that speed; even if I have read about it, I have forgotten because I can't remember a number for long.
@watchme I just summoned what I have read on Apr. 12, 2015, which said a full reversal of earth's magnetic field usually takes millennia to finish, but there is evidence showing some reversals in history took less than a millennium to occur and such a case may occurr due to the reversal is incomplete; such a reversal is called the Laschamp event, after the area in France where evidence of it was first discoveredin the 1960s.
 
Hi all, I'm a high schooler, and I just wanted to clarify what I know about the double-slit experiment. First, I'm thinking of particles & waves. If we have a single slit experiment w/ waves, they do not interfere, so they create one bright spot on the screen. But if we have a double slit w/ waves, the waves diffract and interfere constructively and destructively to create a band of dark and bright spots on the screen.
On the other hand, if we have one slit w/particles (i.e. electrons), there's just a single bright spot on the screen. And if we have a double slit w/particle, there's two bright spots on the screen. And light has a wave-particle duality, so if we have a one slit w/light, it interferes with itself (? I don't understand this), and if we have a double-slit it also interferes with itself? This is one of the parts I don't understand. First, how can a wave OR a particle interfere with itself?
If anyone could provide some resources, or clarity for these questions, that would be great. Thanks.
 
Anonymous
-1
Q: Is quantum computing just pie in the sky?

John DuffieldI have a computer science degree. I work in IT, and have done so for many years. In that period "classical" computers have advanced by leaps and bounds. I now have a terabyte disk drive in my bedroom drawer amongst my socks, my phone has phenomenal processing power, and computers have revolutioni...

 
Anonymous
Aaaaaaaaaaaaaaaaaaah
 
Anonymous
The JD is here :P
 
2:49 PM
If anyone can help me with my questoin, that would be great
 
Anonymous
@DarkRunner It's not possible to explain that without quantum mechanics
 
@DarkRunner Maybe you can resort to Huygens' principle.
 
Anonymous
@CaptainBohemian Not sufficient to explain the double slit experiment
 
@CaptainBohemian OK
@JohnRennie Sorry to ping, but can you please help me with my question?
 
@Blue but in quantum mechanics what I learnt is about matter, not photons. If you want to resort to quantum theory for that experiment, you may need quantum electrodynamics, which is not what I have learnt. In graduate school, we only had classical electrodynamics.
 
Anonymous
3:00 PM
> in quantum mechanics what I learnt is about matter, not photons
 
Anonymous
That's pretty weird....
 
not weird because our course is about nonrelativistic quantum mechanics.
though I was taught about the idea of photons since high school, I have never learnt how an electromagnetic field is quantized in a textbook.
 
@DarkRunner Hi
The problem with your original question is that it's based on some fairly comprehensive misunderstandings.
I was reluctant to try and answer it because we'd have to go back to basics.
And that's quite a long discussion.
 
Anonymous
@CaptainBohemian I don't really see why you'd need relativistic quantum mechanics for photons
 
@Blue because the properties of photons and special relativity are intimately connected
 
Anonymous
3:16 PM
@JohnRennie While, of course, that is true (I don't know RQM though), I'm a bit surprised why Captain mentions that their course didn't cover photons. Polarization of photons , double slit experiment, etc are pretty much covered at the undergraduate level without any notion of relativity being introduced
 
Anonymous
Oh, wait
 
Polarisation and Young's slits are not particle properties
 
Anonymous
YDSE using photons would involve RQM
 
Anonymous
probably
 
@JohnRennie I see, thanks. Are there any links I can read up to investigate the idea further?
 
3:17 PM
I have a question.
Although current flow is not dependent on the surface through which you're measuring it (i.e it's same irrespective of you take the surface to be slanted w.r.t to the direction the electrons are flowing or directly perpendicular to the direction the electrons are flowing), does't current density changes on which surface you're measuring it ?
(i.e high when measured w.r.t a surface perpendicular to the flow of electrons but low w.r.t a surface slanted to the flow of electrons ?) Then how is the current density in a hollow sphere or conical frustum or objects like that defined ?
 
Anonymous
@JohnRennie Yes, I agree. But neither is YDSE explainable using waves (afaik)
 
Anonymous
So perhaps my question is this:
 
Anonymous
1) How is RQM relevant to YDSE?
 
@DarkRunner Light and electrons are neither particles nor waves. They are states of quantum fields. The behaviour of those states gives rise to wave like behaviour in some circumstances and particle like behaviour in other circumstances.
 
(Related with my above question) How do you define resistance for a object which is not like a rod (say antipodal points in a hollow sphere or two ends of a conical frustum) ? The formula $R = \frac{V}{I}$ (or $R = \frac{\rho L}{A}$) don't work for the things I mentioned, because although $V$ is constant, $I$ is not constant through various slices of the objects right ?
 
3:20 PM
Light diffracting through double slits and electrons diffracting through double slits is an example of wavelike behaviour, and both light and electrons behave the same way and are described by the same equations.
 
4
Q: Calculating the resistance of a 3D shape between two points

LucasIf I have an arbitrarily shaped object made of a uniform material of some specified resistivity, how would I go about calculating the resistance between two measurement points with known contact geometry? Is there a general formula for this? (other than just Maxwell's equations) If so, where wou...

 
0
Q: Can moderators take down comments that are not breaking any rules just because they don't like the comment?

user3408085Do mods have to follow a hard set of rules, or can they take down anything that they consider inappropriate? Can they take down questions or comments that are relevant to the community just because they don't like them?

 
I think photons are derived from the quantization of the U(1) group, but I have never learnt how to quantize a Lie group.
 
Anonymous
@JohnRennie But that (Huygens' wave theory) doesn't explain phenomenon like delayed choice (?)
 
@Blue I wouldn't describe that as the YSDE. That's a very different experiment.
By the YDSE I mean the development of an interference pattern after propagation through the slits.
 
Anonymous
3:33 PM
@JohnRennie Ah, okay, if you define it like that :P
 
@Blue Great title though
 
Anonymous
Anyhow, I wonder how RQM deals with photons in generality
 
Anonymous
@BalarkaSen lol
 
Anonymous
37
Q: What equation describes the wavefunction of a single photon?

nibotThe Schrödinger equation describes the quantum mechanics of a single massive non-relativistic particle. The Dirac equation governs a single massive relativistic spin-½ particle. The photon is a massless, relativistic spin-1 particle. What is the equivalent equation giving the quantum mechanics o...

 
Anonymous
You can also say that the wavefunction of a photon is defined as long as the photon is not emitted or absorbed. The wavefunction of a single photons is used in single-photon interferometry, for example. In a sense, it is not much different from the electron, where the wave-function start to be problematic when electrons start to be created or annihilated... — Frédéric Grosshans Nov 17 '10 at 10:19
 
Anonymous
3:35 PM
Ah, this makes sense now ^
 
3:48 PM
whewt
the analysis actually completed...took 18 hours lol
probably 4 or 5 hours of that was uploading the final table to the database tho...
 
Anonymous
@BalarkaSen 173 views in 1 hour. Fastest question on the site, to reach HNQ :P
 
Given the caliber of the person who asked, not surprised
 
Anonymous
lolol
 
Hi @Eric
 
4:26 PM
and now...LSTM training starts!
muahahahaha
 
4:40 PM
@NovaliumCompany Partially. It is also about torques. See physics.stackexchange.com/questions/79294/… and other questions for discussion.
The basic problem should be covered briefly in any intro mechanics class at the university level and in much more detail in a junior level classical mechanics class.
 
@enumaris nice!!! what library are you using for this? Are you writing it from scratch?
I think I am going to resume coding today myself
hehee
 
hello @BalarkaSen how's college admission going on ?
2 hours ago, by Alex K Chen
Although current flow is not dependent on the surface through which you're measuring it (i.e it's same irrespective of you take the surface to be slanted w.r.t to the direction the electrons are flowing or directly perpendicular to the direction the electrons are flowing), does't current density changes on which surface you're measuring it ?
2 hours ago, by Alex K Chen
(i.e high when measured w.r.t a surface perpendicular to the flow of electrons but low w.r.t a surface slanted to the flow of electrons ?) Then how is the current density in a hollow sphere or conical frustum or objects like that defined ?
2 hours ago, by Alex K Chen
(Related with my above question) How do you define resistance for a object which is not like a rod (say antipodal points in a hollow sphere or two ends of a conical frustum) ? The formula $R = \frac{V}{I}$ (or $R = \frac{\rho L}{A}$) don't work for the things I mentioned, because although $V$ is constant, $I$ is not constant through various slices of the objects right ?
Anybody ^^ ?
 
@Cows for NLP I use spacy, for deep learning I use Keras
 
4:56 PM
nice!
 
@AlexKChen It's a'right. ISI results haven't come out yet.
By result I mean the merit list post-interview
 
I'm sure you'll make it :)
 
Thanks. I hope so.
But if I don't whatever
 
@BalarkaSen cmi ?
 
I didn't get in CMI
 
4:59 PM
ooops sorry sorry i shouldn't have asked you
 
Why? I'm fine with it
 
You're planning to read stats or maths in ISI ?
and any backup college (incase...) ?
 
It's just an elimination test. If I didn't make it it's not the end of the world
I applied for B-Math.
Naw. There's also no god-given talisman that I need to study math :P
 
@AlexKChen You can define an overall resistance by measuring the total I through the whole object and the total V across the whole object. But if you are interested in the current flow within the object itself, then obviously the overall resistance is not going to help you there.
 
@BalarkaSen yes, you can also read physics (you know shitload of stuff in both physics and maths)
 
5:02 PM
Or non-science as well.
 
history :P or geo :P
@enumaris What do you mean by total $I$ ? Can you please explain ?
 
Literature is pretty cool
 
Sid
@BalarkaSen so is history.
If you want to read about cool arcane world War 2 stuff..
 
@AlexKChen connect the object to (idealized) wires that connect to some voltage source. Measure the I in the wires - that's the "total I".
 
To each his own! I don't like the way history is studied. There are yet to be discovered scientific approaches to history
 
5:04 PM
don't try to measure I on the object itself, just measure the I in the wires. By charge conservation though you know the I's must be equal since there's nowhere else for the charge to go.
 
@enumaris So suppose you have a hollow sphere and I wish to measure the resistance in two antipodal points $A$ and $B$. So after connecting a wire to $A$ and another wire to $B$ and applying potential difference $\Delta V$ I should measure the current flow in the wire in point $B$ ? (which is same as in point $A$ since no charge is piling up inside the sphere),
 
yup
assuming steady state that works - i.e. you assume your weird object is a resistance-type object and not like a capacitor or inductor or something.
 
For my other question, isn't current density different for different surfaces ?
@enumaris It's a conductor which I'm trying to measure. What do you mean by "steady state" ?
 
like that the current is constant
you don't have a capacitor which is charging up for example
 
oh yes, then the values at $A$ and $B$ would be different.
 
5:15 PM
I'm not sure about that...
 
@enumaris which one ? the current density questoin ?
 
that the values at A and B would be different for non-steady state
 
ok what about the current density question ?
 
I'm not sure what you mean by that question
 
OK sure, I'm explaining. Like if there's a rod and current is flowing through the rod, and you take two surfaces (one is perpendicular and one is slanted), wouldn't the current density be different through these two surfaces ?
 
5:20 PM
Yes
 
ok thanks a lot for your help :) bye
 
no problem :)
 
5:42 PM
Evening guys, two questions:
What exactly is going on here, does the resistor cause any effect?
Also can the same circuit be written like this?
 
can't view images heh
 
Try to click on them?
 
blocked heh
 
Sid
@NovaliumCompany if that's an ideal LED, all the current flows through there. But, since, everything's not ideal in this world, the Resistor helps to lower the amount of current flowing
(Basically, to reduce heat loss)
 
@Sid How can all the current flow through the LED, I mean, doesn't it split between the resistor and led?
 
Sid
5:51 PM
@NovaliumCompany that is true, only if it's an ideal LED. Which would mean that, its forward resistance is very very very small(or practically zero). Since, Current goes through the path that has the least resistance, it goes through the LED.
However, in the real world, it's not ideal. It has some forward resistance and so, the Current gets divided between the resistor and diode
 
Sid is saying the LED creates a short circuit if it's ideal
 
So current tends to go to where there is less resistance?
 
Sid
@NovaliumCompany Higher amount of Current, yes.
 
U ever get a short circuit And bam, stuff shuts down? It's like that because all the current is flowing through the "short circuit" which has almost 0 resistance.
 
That's cool!
So in an ideal situation, all of the current will go through the led and none through the resistor (if the led has 0 Ohms resistance?)
 
Sid
5:54 PM
Yup.
 
Cool, thanks.
 
Sid
(Also, because it's forward biased)
 
You'd get infinite current tho, so ideal situation isn't really plausible heh
 
Why infinite? (in ideal)
 
I=V/R
if R->0 I increases without bound
in an ideal situation I'm also assuming V stays constant
 
5:56 PM
Can we describe it with a limit :D?
Like as R approaches 0, I approaches +inf?
 
The limit does not exist strictly speaking.
I approaches +inf is a more sloppy way to say it I guess
 
Ok, if Voltage was a function of resistance, we could find the instantaneous current? (if current wasn't constant of course)?
Wait, that makes no sense :D
I = Q/t. If current wasn't constant and Q was a function of t, we could find the instantaneous current?
Is that true?
$I = \frac{dQ}{dt}$
 
yes
in general $I(t)=\frac{dQ}{dt}$
just like $v(t)=\frac{dr}{dt}$
 
Yep, thanks for the help. I'll see you later :)
 
np
 
6:46 PM
welp, I hope a 5.9 million word corpus is good enough for my deep speller to work...otherwise I'm gonna have to go find bigger corpora
 
7:35 PM
Evening. What is the point of the ground in this circuit? Why can't the electrons return to the battery and that's it?
Nevermind, please ignore my question, I just understood it.
Nevermind, please ignore my stupid question, I understand it now. (A video helped)
 
ok so given some group $G$
the maps to $GL(V)$ are the representations
fine
let me just confirm something . . . notational and what not
so $(\frac{1}{2},\frac{1}{2})$
is more physics way . . . of
encoding $\sigma$ ? no other esoteric thing . . . no?
And one can use the irreducible vodoo to do standard splitting . . . .
 
7:54 PM
wut
 
hehe
 
couldn't follow that sorry
 
ok let me try
so we know what representations of a group are
say $\rho :G \rightarrow GL(V)$
ok now let us keep that on the back burner for now
Let us look for example at
3
Q: Proof that (1/2,1/2) Lorentz group representation is a 4-vector

WatwTaken from Quantum Field Theory in a Nutshell by Zee, problem II.3.1: Show by explicit computation that $(\frac{1}{2},\frac{1}{2})$ is indeed the Lorentz vector. This has been asked here: How do I construct the $SU(2)$ representation of the Lorentz Group using $SU(2)\times SU(2)\sim SO(3,1)$ ?...

$(\frac{1}{2},\frac{1}{2})$
the above is somewhat strange notation (actually common in physics) . I want to understand what it means
so I think $\frac{1}{2}$
here
is a way of capturing the matrices that contain $\sigma$
?
 
no?
what is $(\frac{1}{2},\frac{1}{2})$
 
8:00 PM
It's just a list of numbers that uniquely characterize an irrep of the Lorentz algebra
 
I don't think any general group can be mapped to the general-linear group...only matrix groups can be mapped this way, no?
 
It turns out each (finite dimensional) irrep is uniquely characterized by two numbers, so there's two of them
 
well not every group
 
But the numbers themselves do not have any direct relation to "matrices" or some such.
 
I see
 
8:02 PM
@enumaris There is a difference between a "mapping"/representation and a faithful ( = injective) mapping. There are groups that have no injective mapping to a matrix group but they still have representations.
 
ah right
cus you can trivially map all objects to the identity or something
 
The trivial representation, correct.
 
ah
 
8:17 PM
looking at this now
41
Q: How do I construct the $SU(2)$ representation of the Lorentz Group using $SU(2)\times SU(2)\sim SO(3,1)$ ?

MadScientistThis question is based on problem II.3.1 in Anthony Zee's book Quantum Field Theory in a Nutshell Show, by explicit calculation, that $(1/2,1/2)$ is the Lorentz Vector. I see that the generators of SU(2) are the Pauli Matrices and the generators of SO(3,1)is a matrix composed of two Paul...

Very interesting
Let me just eat some food first, will resume in 20 mins
 
::sigh::
4
Q: Neutrinos passing through black hole

Árpád SzendreiI have read this: https://en.wikipedia.org/wiki/Neutrino The weak force has a very short range, gravity is extremely weak on the subatomic scale, and neutrinos, as leptons, do not participate in the strong interaction. Thus, neutrinos typically pass through normal matter unimpeded and undete...

Is on the HNQ.
Really?!?
 
@dmckee glad to see HNQ shaming is not limited to the periodic table
 
8:33 PM
The HNQ perverts all the usual measures of question quality.
 
6
A: Are 19.6 pounds of CO2 produced from burning a gallon of gasoline?

Sklivvz This answer provides an example on how to address this question by citing calculations performed by competent authorities. Please ignore any voting on it. The calculation is somewhat involved because it requires estimating a number of factors. Fortunately the EPA has done this for us G...

One of my favorites
 
8:48 PM
hmm
so $su(2) + isu(2) = sl(2,C)$ the algebra vs . . let me think
 
@Cows No, that is explicitly not the case.
See Qmechanic's first sentence in II) in the post you linked.
 
ok let me look
ah
 
9:11 PM
lol, I got 12 upvotes on that answer and earned a nice answer badge
why is that question featured though
how's that work...
 
it's featured on stack exchange's front page
loool
 
@enumaris It works like this
 
what's the Q-score in that formula?
 
@enumaris Simply the net score, I believe, i.e. upvotes - downvotes.
 
9:17 PM
I see...
that question only has 4
that doesn't seem like a big multiplier...
 
I've long desired for downvotes to be more heavily featured in that score - a question at +10/-0 is far more likely to be unambiguously good than one at +20/-10
 
is physics just so devoid of upvoted questions that this one got featured...lol
 
@enumaris Note that 4 upvotes and 2 answers are better than 7 upvotes and 1 answer by that formula.
 
hmm
 
So getting 2 answers quickly increases the chances of a question hitting HNQ by rather much
 
9:20 PM
so because I decided to post my answer...I got it to HNQ
ahahahahaha
I have so much POWER
 
Also note that the answer score is weighted more than the question score as long as there are less than 5 answers
So your answer getting 12 upvotes is probably the larger factor in keeping it hot
 
POWER OVERWHELMING
 
9:37 PM
now I just need to get 270 more upvotes so I can look at close votes
 
Let me do some reading/thinking
 
Anonymous
@enumaris You'll hit the daily rep cap (200 per day) before that :P
 
John Duffield (this guy: chat.stackexchange.com/transcript/71?m=44043159#44043159) is back on the Quantum Computing SE
 
Anonymous
Unless of course the 270 upvotes are on separate days (~20 per day)
 
Anonymous
@probably_someone Everyone here already knows :P
 
9:54 PM
Let's not talk about people suspended from chat too much here where they can't respond, please.
 
Anonymous
Technically we shouldn't really bother unless he starts spamming that site. Although, tbh I'm not very happy with the HNQ question today.
 
Anonymous
@ACuriousMind Agreed
 
@ACuriousMind Yeah, sorry. Shouldn't have done that.
 
@Blue No one's ever happy with HNQs :P
 
Anonymous
@ACuriousMind Except the OP ;) They're having a gala time with the upvotes
 
9:58 PM
@Blue True, true
 
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