We have been struggling for a long time with the homework close reason. There are shortcomings to all approaches we have tried so far to change it. I believe one of the problems with this is that actually enacting a different strategy comes with the worry that it'll drastically change the dynamic...
@SirCumference "“Light thinks it travels faster than anything but it is wrong. No matter how fast light travels, it finds the darkness has always got there first, and is waiting for it.” " ~ Terry Pratchett, Reaper Man
According to Wikipedia, the definition of the spherical harmonics in quantum mechanics and one in seismology are different:
Why, in quantum mechanics, is $(-1)^m$ multiplied? The reason is explained in the picture above, but I don't think the explanation is correct because probability is ...
Is it just me or is every other new question these days a blatant Ctrl-C Ctrl-V homework question? Is there any realistic way this is being dealt with? (other than closing them, of course)
For about five years we've been having chat sessions every two weeks - they started as a way to build up activity in the chat room, but it's also been a nice way to engender a sense of community between chat and the main site and to discuss issues of general interest. But for quite a while we've ...
@Mithrandir24601 Hey, if we consider a combined system of systems $A$ and $B$ with probability density $\rho^{C} = \rho^{A} \otimes \rho^{B}$. If we measure system $A$ to be in state $|a_0⟩$. Then the state of the joint system would be $$\tilde{\rho} = |a_0\rangle\langle a_0| \otimes \rho^B =\frac{(|a_0 \rangle \langle a_0 |)\rho^C(|a_0 \rangle \langle a_0 |)}{\mathcal{N}},$$ do you maybe know what the normalization $\mathcal{N}$ would be in this case?