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12:05 AM
@Danu Ho boy.
I've been sick too.
Sicker than I can remember being pretty much... ever.
Except for that one time with the risotto, but that was different because I spent the whole 48 hours asleep mostly unaware of my body's trial.
 
@DanielSank the...risotto?
Did you eat bad rice or something?
 
12:29 AM
@0celo7 He might be trying the train you to ask questions more carefully. You know, basic Skinner reinforcement therapy.
 
@dmckee I'm not a pigeon!
 
::puts away pigeon seed bag::
2
 
@ACuriousMind I'm getting an AC2 vibe from FC3
rich pretty boy turned mass murderer?
 
Well, it is also made by Ubisoft, and they never change a working formula :P
 
12:45 AM
@ACuriousMind Help, there's a snek!
 
@0celo7 On the internet no one know you're a dog.
So sometimes they treat you like Henry Kissinger.
And other times like a pigeon.
 
@ACuriousMind If that were true I'd have a hidden blade in every Ubisoft game
there's really no excuse for not giving me a hidden blade in every game
@ACuriousMind Name one game that isn't made better by the hidden blade.
 
Tetris.
 
:P
Game with combat!
 
Space invaders.
 
12:58 AM
Never played it
Game with infantry combat then
 
Age of Empires.
 
Wrong
imagine having swarms of assassins
fighting with hidden blades
 
They'd die to a bunch of handcannoneers all the same :P
 
@0celo7 Ogre.
 
@dmckee never heard of it
 
1:01 AM
Not a huge loss. It was pretty good for it's time, but the AI was painfully limited.
 
user54412
1:18 AM
@FenderLesPaul Wait really?! How is a pre-print of mine showing up in a feed of yours? Or anyone's feed for that matter?
 
1:41 AM
@ACuriousMind Who is this Daisy and should I care about her
 
2:32 AM
@ACuriousMind Why did no one tell me there's an open world game where I can sneak around shooting pirates with a suppressed pistol
THIS IS AWESOME
 
 
3 hours later…
5:16 AM
@ACuriousMind @Obliv In particular, I am very very VERY bad at physical thinking, which is why I often end up doing a lot of unnecessary algebra crunching while a problem can actually be solved via a clever trick
 
: 28517217 I also have a weird attitude to mathematics and physics, in that I often found myself solving physics problems like a mathematician, and mathematics problems like a physicist
For example one reason why I can remember the Exchange Lemma of linear algebra is because the way it is proved reminds me of phagocytosis

http://i.stack.imgur.com/ViTf9.png
 
6:14 AM
--
http://physics.stackexchange.com/questions/237860/what-does-it-mean-not-to-have-a-definite-trajectory

Quantum fields are weird. You cannot even think of them as something similar to orbitals because even orbitals have some definite shape.

They are not like chaos either because they don't generally have a fractal like structure nor resemble a strange attractor

As the answer said, all you can really said is that in some region, the field take nonzero values, and these nonzero values don't generally distribute like a lump because fields cannot be localised in general
QUOTE:
And what I have said above is only an approximation because in general you can't localise a field so that it only has a non-zero value in some bounded region. The best you can do is change the field so that you will have a higher probability of seeing a photon in some region.

The above discussion alone would mean that a photon doesn't have a trajectory, but in general the situation is even less trajectory friendly than that. Different photons with the same energy aren't distinguishable: all you can say is "there are so many lumps in the field in this region".
 
6:42 AM
@DanielSank I hope you feel better. Have you gone to a doctor?
 
 
1 hour later…
7:49 AM
Should we consider reopening:
1
Q: SU(2) Rotation Matrices Problem from Halzen and Martin

Matt Steinberg What I’ve gotten so far looks like this (I’m going to present everything as neatly as possible): for part a) : $d_{m’m}^{j}{(\theta)} = <jm’|e^{-i{\theta}J_{2}}|jm>$ now, I saw that Euler’s Equation is $e^{-ix} = cos(x) - isin(x)$. I went through, and did as follows: $e^{{-i{\theta}}/2}|jm>...

It seems an honest question, just (initially) rather badly phrased and it did look like homework.
 
8:11 AM
@DanielSank That sounds... weird :P
 
My current emotion
To start with, it seems everywhere is so quiet, no club activities, chatroom is empty, not much major news, not much change in a day's routine

It's as if time has stood still, and the world is not really changing
The only place where time seemed to be still flowing, is that there is slow progress in the research project
 
 
1 hour later…
9:42 AM
0
Q: Literatur recommendations for QCD Self study

Christian VöglIm a Computer Science Student with String physisch background, nur vety wrack formal Math Education In physisch the most advanced Theorie coursr I Tool was Quantum statistics, nur I have absolutely no knowledge about Quantum Field theorys. What Books Wolf you recomend for me?

Is this... some kind of joke about Germans speaking English?
 
10:08 AM
Why reason why this is should remain open?
1
Q: Puzzled by a new result on neutrino speeds

Rob JeffriesIn a paper appearing today on arXiv, Wie et al. have used the close coincidence of the time of arrival of gamma rays from GRBs and the detection of single 3-30 TeV neutrinos at the IceCube observatory, to say that the velocity difference between neutrinos and photons is no bigger than $$ | v-c | <...

 
Is there a similar notion to a transition state in particle physics, given how people working at accelerators often talked about how there are various channels that a particle can decay into, and we often talked about branching ratios and whether the energy momentum is sufficient to produce some particles with a certain rest mass?
 
10:35 AM
@0celo7 I don't remember, can't be that important.
@Danu If so, I don't get it
 
@ACuriousMind a *symmetric monoidal category, mind you.
I am sure you can add more adjectives but I can't remember good ones off the top of my head.
 
10:55 AM
And here I thought 12262 was alone this weird insistence to try and formulate SR and GR in terms of axioms that mostly only use set-theory. Turns out they can cite books on that.
Like...why would anyone waste their time formulating and working with strange axioms for Minkowski space if all you end up with at the end is just something that's equivalent to $\mathbb{R}^{1,3}$, anyway?
 
Maybe some things are easier to prove in it?
Maybe he just wanted to write a paper and had no better idea
 
This "John W. Schutz" is not the only one, he cites earlier attempts by other mathematicians such as one "Walker".
Who is apparently the Walker from FLRW.
 
Well IIRC there's an old paper that tries to define SR using only causal relations
I think that's where the notation for causal relations come from?
 
11:12 AM
I wonder what other model people used for SR because Einstein was widely accepted
I know there's the Lorentz ether theory
But what else
Also Lorentz ether theory was basically SR, except for some extra bits
 
11:37 AM
God, you two
Every morning!
 
11:58 AM
Can't have a good morning without axiomatization
I can't wait until I can actually understand AQFT axiomatization
Then I try to read it and it's like "First define 4 topologies that we won't tell you what they are for"
 
12:10 PM
Bonjour mon amigos :D
 
Be glad they're not defining 5 topologies!
 
Well 4 topologies is just for the $A^*$ algebra category
That's not even mentionning whatever topology they do with light cones
 
Oh fuck all the eating places on campus are closed
Damn you Pilate
 
Do you still have same roommate?
 
I have a difficult assignment question, any tips on what to do?
 
12:15 PM
Poncius Pilate?
 
Reduce problem down to simpler problems?
Identify clear aim?
What else?
 
@JesterTran Solve it
 
@Slereah How?
 
Well maybe tell us what the problem actually is
 
What are the fundamentals of problem solving?
It's an assignment question, so I prefer to do it myself but I'm asking for problem solving techniques
It's about finding boundary and interior of a set of sequences under a specified metric
 
12:17 PM
@Sᴋᴜʟʟᴘᴇᴛʀᴏʟ Yes, what kind of question is that
 
They don't randomly switch
 
Any problem solving tips?!
 
@Sᴋᴜʟʟᴘᴇᴛʀᴏʟ Cbb
@Sᴋᴜʟʟᴘᴇᴛʀᴏʟ I'm on here to get a quick answer
 
12:21 PM
A quick answer for the most general problem ever
 
@0celo7 A quicker answer on what to do when stuck on an impossible problem
 
Your question can literally go from "math problem" to "ask a girl out"
VTC as way too broad
 
@0celo7 Trying to find a hilarious joke solution that would apply to both
Errr... Use the root?
Find a sequence of balls
 
Hah
 
Use the Wiener measure
Apply hairy ball
 
12:22 PM
Why are we finding sequence of balls?
Assume I'm studying basic topology
 
To ask a girl out
 
Why are we asking a girl out?
 
She's probably better at topology than you
 
Ask your sex ed teacher
 
@0celo7 Why?
 
12:23 PM
Use the Feynman method
 
sigh...
 
@JesterTran you won't even tell us the problem lol
And what makes you think physics people can do topology
 
@0celo7 I have made a request about problem solving and added in the question to clarify and you don't even understand it
 
Lol
 
Define what you mean by "understand."
 
12:27 PM
No one here knows topology @JesterTran
What is that even
The thing with maps
 
O M G, nice head band!
 
Better face this time, @0celo7.
 
Ya, the other one was ready to pop a vein on the temple.
 
Today, I'm spending time finding anagrams :3
 
12:37 PM
Systematic way to waste your time, Danu?
 
@BalarkaSen Possibly. Also Connes challenges us to find some good ones---he had a really nice one in French.
Funny example: Astronomers = Moon starers
 
I just realized an anagram of anagram is granmaa.
 
@BalarkaSen used my real one this time
 
@Danu Connes is onto anagrams, now?
 
@BalarkaSen He's slowly converting to linguistics, via theoretical physics :)
 
12:39 PM
Cruds.
 
@Sᴋᴜʟʟᴘᴇᴛʀᴏʟ Yep
Typical Raiders fan
 
Welcome to the nation
 
Microsoft deletes 'teen girl' AI after it became a Hitler-loving sex robot = Female bot goes loco at once; the girlie is evil extremist firebrand tart.
 
There are some really long anagrams out there.
 
@Sᴋᴜʟʟᴘᴇᴛʀᴏʟ Obnoxious fans?
At least no one bandwagons the Raiders
 
12:49 PM
You got that right.
 
@Danu That happened a long time ago
@Sᴋᴜʟʟᴘᴇᴛʀᴏʟ More people bandwagon ISIS than the Raiders
Maybe they should start rolling through Cali in armored trucks with mounted HMGs
I'm sure the gangs would respect them more...
 
The raiders have never been a bandwagon type of team. Either you with us or against us.
 
Because no one wants to be a Raiders fan :P
 
1:09 PM
Can you please make the k in your name normal
 
I can't @ you on mobile
 
And adding a k just gives me your alter ego
 
What a strange coincidence
Display name may only be changed once every 30 days; you may change again in 1 hour
 
1:19 PM
hahaha
 
Wow
 
@0celo7 you can also add the greek alphabet to your phone, and just type in the κ
 
I don't think that's a kappa
 
Ah, it's a kappa?
 
1:21 PM
It's "small caps", not Greek, I think.
 
I do actually have Greek on the keyboard ;)
Let's try
 
Yep @ACuriousMind
"small caps"
 
@Danu WRONG
 
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51 mins ago, by 0celo7
Typical Raiders fan
 
1:39 PM
Mar 23 at 1:04, by 0celo7
But be warned: this chat is mostly GR
^ that.
So, can I ask a casual, rookie GR question?
Actually, its not even GR, simply combinatorics and has no Physics, that's why more suited to chat than the main site.
1
Q: Counting independent components of Riemann curvature tensor

The Dark SideI'm having some trouble understanding the counting procedure for the number of independent components of Riemann curvature tensor $R_{iklm}$ in 4D spacetime. (The answer is supposed to be 20, but I'm trying to understand how so!) Let's do it sequentially: Since we are looking at a rank 4 tenso...

 
Houston, we have a problem here!
Me: Grrr, back to the drawing board!
 
@TheDarkSide Check for instance Carroll's book.
 
@Secret FYI (AIKWTYBWECAU!): My aim is to project the covector as a contour map in $\mathbb{R}^n$ onto the face of the n-parallelpiped that is opposite to the ith column vector so that the row vector information can be encoded into the pictorial representation. However, as this proof shows, there exists nontrivial cases where this is impossible, meaning that the pictorial representation has to be modified to address that
 
1:58 PM
@Danu Thanks for that input, but let's break down Caroll's argument wherein he uses both symmetry and antisymmetry at once. I mean, I am thinking more on the lines of Weber, Arfken, Harris, wherein we want to see how antisymmetry reduces 256 to 36 first up, and only later, you place the requirement of symmetry which reduces the no. to 21.
 
@Sᴋᴜʟʟᴘᴇᴛʀᴏʟ way to play on the gang stereotype
Can you change your name now?
 
Now, how do we infer about the number 36? 6*6, or rather ${}^N C_2$ squared, but how exactly?
 
@TheDarkSide TBH I've never actually verified that statement.
I've always taken it for granted -- it doesn't seem interesting.
 
@0celo7 :)
 
There are many "easy" statements that are just incredibly tedious to prove
 
2:03 PM
@0celo7 This is not one of them.
The argument is not that difficult.
 
That seems pretty hard to me.
But I can't count.
 
The only step I don't know immediately is seeing how to get the number of conditions from the Bianchi identity
 
I'm still not convinced a symmetric tensor has however many components it has
 
I remember not seeing it on the spot, then seeing and being like oh that's simple enough, but now I forgot again.
@0celo7 lol
...okay :P
 
@Danu :)
 
2:05 PM
Just view it as an array of numbers
 
I have better things to worry about
@Danu I know how to do it lol
 
@TheDarkSide I find your post very hard to read, and I don't get what it is that confuses you about the 36. You have to choose the first and the second and the third and the fourth index as pairs of distinct indices, since the tensor vanishes if the first/third is the same as the second/fourth. From $\{1,2,3,4\}$, you can sample 6 such pairs: 12,13,14,23,24, and thus 36 possibilities to choose two such pairs.
 
@Danu No, I've seen that (TBH after you recommended Caroll), but again, can we do that in steps?
 
@0celo7 Then why say you're not convinced? :P
 
Uh...I think I forgot how to do it :P
 
2:06 PM
@Danu He has a strange aversion to being convinced by proofs :P
 
I'd find the antisymmetric part first
Then subtract it from n^2
 
Someone did a joke proof on clausius inequality
 
@ACuriousMind :: munches over it ::
 
@Danu I remember how to do it!
You always get n terms on the diagonal and then (n^2-n)/2 from the rest
So you add those and simplify
I'm bad at simplifying things :(
n(n+1)/2. And that gives the right answer for the metric in 4 dimensions, so I'm correct.
HA,take that @ACuriousMind
I did something without your help
 
I'd say it's much simpler to note that it's equivalent to adding the integers up to $n$.
 
2:13 PM
You need induction for that one though
And you think I remember how to do induction?
 
triangular numbers hint hint
 
@0celo7 What? You just note that the upper triangle part of a symmetric matrix determines the whole matrix.
 
@ACuriousMind That's what I did in my proof.
 
Yeah, but there's no need to split it up into "the diagonal" and "the rest". Just note that a triangle of length $n$ has $\sum_{i=1}^n i$ entries.
Oh, you mean one needs induction to prove $\sum_{i=1}^n i = \frac{n(n+1)}{2}$?
 
I like my proof dammit
@ACuriousMind Yes!
 
2:15 PM
@0celo7 I think I can prove it without induction.
 
That's like the most ridiculously easy induction ever.
 
One can use the Gauss argument
But that's cheating
@ACuriousMind IF you know how to induce
 
I do maths like a physicists and a programmer combined, but I do physics like maths

I will always find ways to shot down my derivations until it cannot be shot down
 
It's just logic! There's no "trick" or dark secret to induction.
 
How about doing it like this: $$\sum_{k=1}^n k^2=\sum_{k=0}^n (k+1)^2-(n+1)^2$$
I think I actually forgot how to make the large sum symbol in tex
lolwut
 
2:17 PM
some proof by induction has more than one starting cases (not for this case though)
 
@Danu on mobile, can't really parse that in my head
 
@Danu wat
 
$$\sum blah$$
 
\sum
 
Did you just use \Sigma instead of \sum? :D
 
2:17 PM
@ACuriousMind oh, I tried \Sum and forgot it automatically corrects size
@ACuriousMind I am ashamed of myself
 
@Danu You should be!
 
Anyways, this yields a proof without induction, I think
 
In algebra we actually proved induction is equivalent to well ordering of the naturals.
 
Also it generalizes to find $\sum_{k=1}^n k^m$ for any $m$ from the previous ones
 
@Danu Probably not more than I am right now :(
 
2:19 PM
But I cannot prove that sum by induction
(In my head)
So I like my argument the best! It can be done in your head.
 
Because it yields $$ 0= 2\sum_{k=0}^n k+(n+1)-(n+1)^2$$
 
('coz I seem to have understood ACM's logic). And now I feel silly.
 
$$\Huge{\Huge{\Huge{\Huge{\Huge{\sum}}}}}$$
 
I think that that trick is beautiful, even more so than the Gauss trick.
Because it actually generalizes.
I'd almost gather the energy required to write out $\sum_{k=1}^n k^m$ for arbitrary integer $m$ in terms of the lower series
 
Do it!
 
2:25 PM
What are we talking about here?
 
@BalarkaSen This nice trick to compute $\sum_{k=1}^n k^m$ for arbitrary integer $m$ in terms of only the series for each $m'<m$
(which allows you to sum integers up to $n$ without using induction)
 
I think you're the only one talking about that ;P
 
YES
AND I LOVE IT
I am basking in its glory
 
What's the trick?
 
Say you want to compute it for some fixed $m$
Then instead you consider the series for $m+1$
and use the following:
$$\sum_{k=1}^n k^{m+1}=\sum_{k=0}^n (k+1)^{m+1}-(n+1)^{m+1}$$
The first term on the right cancels the left hand side and then yields the series of $k^m$ in terms of only the lower ones
 
2:29 PM
okie.
 
Good ol' Do Nothing Technique
 
Thanks @Danu and @ACuriousMind - because I seem to have understood that argument, and because I feel silly for not having got it directly, I now feel tempted to think harder to make sense of those 112 vanishing components and 84 double counted ones, before I ask in this chat.
 
@BalarkaSen BASK IN ITS GLORYYYYY
 
Must admit I didn't get those 112 and 84 the first time either!
 
How are you doing @BalarkaSen
 
2:31 PM
So-so. Struggling with math.
 
What do you do outside math?
 
Um.
I study algebra occasionally.
 
You don't want to talk about your life outside academics?
 
which ain't Maths?
 
'Twas just a joke on geometers hating pure algebra.
@Danu I don't have a life inside academics, let alone outside. How can I talk about a nonexistent thing?
 
2:35 PM
@BalarkaSen Wrong room for that joke :P
@BalarkaSen Really?
 
@Danu I at least hoped you'd get it.
 
Nopes
I'm doing some Greek exercises
 
You're learning Greek?
 
@Danu wait, I keep getting 0=0, how do you rearrange the first term in the summation to cancel out the LHS and left behind $\sum k^m$ ?
 
@BalarkaSen Yup.
 
2:42 PM
@Danu I mean I really don't know what you mean when you say life outside academics. Most of the time I just read something - it may not always be math I am reading. Would you consider that academic activity?
 
@BalarkaSen I mean "general/everyday life", hobbies, etc.
 
Still quite unclear to me, honestly. Why is "my hobby is to study math" not a valid answer?
Or, "my everyday life consists of reading".
 
I guess I can't imagine that that's literally all you do in life
 
Of course that's not literally all what I do in life. E.g., I chat in SE chatrooms.
It's just what I do most of the time.
 
I suppose, if you're an undergraduate or beginning grad student, anything you do because you think it will help you in a class (one you're currently taking, or one you expect to take in the future) counts as academics. Anything else counts as non-academic life.
Roughly speaking.
 
2:47 PM
yesterday, by ACuriousMind
YES WE HAVE NO LIFE WHATS IT TO YOU
 
lol, @TheDarkSide.
 
:) and :( simultaneously.
Bye guys.
 

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