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9:00 PM
like yesterday
 
I also applied to engineering programs this year.
I applied to physics for back up though.
 
Where are you based?
 
Canada.
 
Cool, I applied for University of Waterloo
But mostly US colleges
 
I say "Thursday next week" but I'm weird.
 
9:05 PM
I'm brazilian tho
 
@BernardMeurer Why not university of toronto?
The engineering program there is better than waterloo.
It's more difficult*
 
Napoleon
 
@0celo7 To refer to which thursday?
 
@0537 Waterloo has a very nice research center for quantum computing
I was on the hype while applying
 
You're into quantum computing? I see. Then waterloo is probably better for that.
For physics too.
 
9:08 PM
I am yeah hahaha
 
Waterloo has perimeter institute and their physics courses are really cool.
 
I took a good look at their labs, they seem really amazing
 
For all other engineering uoft is better though.
I applied to aerospace.
 
Aerospace is damn cool. The simulations involved <3
 
I guess.
Right now I'm doing CFD which is basically the simulation stuff.
Though idk how to code simulations myself from first principles right now.
I use commercial software... like fluent.
 
9:11 PM
The little I dealed with simulation I really liked it
it was solid works stuff tho
simulating part stress
 
I can't afford solid works.
 
Neither can I, did it as an intern
 
I see.
 
The price is abusive
 
There should be a free student edition.
 
9:13 PM
Autodesk is a beauty tho
 
Fluent and CFX have free student versions which is basically the full version.
 
giving us free software because we're students
 
Abuse implies initiation of force, I think.
 
Hahahaha
 
@0celo7 Well if you're forced to buy it... does that count?
 
9:15 PM
@0537 The person who is forcing you to buy it is initiating force.
Duh?
 
You made up that definition of abuse.
So no duh.
Besides abuse can have multiple definitions.
 
A price is abusive if it costs more than a minimun salary
 
@BernardMeurer Lol?
 
@BernardMeurer You also made that up lol
 
So Ferrari pricing is abusive?
 
9:16 PM
since minimun salary here is 800BRL which is 198USD it is very abusive
YES
 
iPhone pricing is abusive.
Though everyone abuses themselves anyway.
 
Absolutely
 
Expensive prostitutes are abusive!
 
@0celo7 Only if you like that sort of thing. :P
 
Everything is abusive, yet we all have a secret fetish for being abused by the companies
 
9:18 PM
I think you have to look up the definition of abuse.
 
Extremely offensive and insulting, habitual violence/cruelty, injustice/illegality
 
Healthy discipline with the integration of hardware.
I like that one
 
ello ello what's all this about
 
abuse appearently
 
9:22 PM
Someone flagged something?
 
well it's probably not appropriate discourse for a publicly viewable and community moderated chat room
you're abusing it man
 
Anyway, high pricing is not abuse.
 
Why is this even a discussion?
 
It's not like software is lebensnotwendig (ACM pls find English word)
Vital!
@0537 Because.
 
@0537 because faceless flagging and resolution is unproductive to future change
 
9:25 PM
@ACuriousMind Going back to school on Sunday, I need to find a way to smuggle my baby back with me
And hide him in my room
 
@0celo7 You didn't even tell me you were pregnant!
 
Don't worry, it's not yours.
He's too orange...and you keep telling me you're not a ginger.
@Quill who flagged?
 
dunno, not a mod
 
Probably ACM, he's against child beating.
 
mods can tell, but >10k users can't
 
9:29 PM
Ah.
 
Is it weird that I've been wearing the same shoes for 5 years? [I buy a new pair every year]
 
Yes.
 
like that character in Mr Megorium's Wonder Emporium
 
Never heard of it
 
he buys enough pairs of the same shoe to last him his entire life and when he runs out he decides it's his time to die
 
9:34 PM
@Quill lol.
 
10:02 PM
0
Q: She is so big she is invisable!

JenCan a black hole be so big that it would bend light to be a clear sphere? gyrating and emitting particles from the center of the galaxy while consuming all matter around her?

Thoughts?
 
@EmilioPisanty Many that should not be uttered.
 
@ACuriousMind Ditto.
Part of me screams "close", but I'm not quite sure which button to press
 
unclear what you're asking, I'd say. Alas, I'm out of votes for the day.
 
Love the comment on the edit, though
 
10:27 PM
She?
In which language is "black hole" feminine?
@ACuriousMind Is it common for people who natively speak a language with grammatical genders to bring it over to English?
 
@0celo7 Uh...one would think so, but I'm definitely not an expert on that topic
 
I got banned for half an hour! Abusive!
 
Wrong again.
@ACuriousMind What's the Latin word for "hole"?
 
cavum
 
10:34 PM
Why on earth do you know latin @ACuriousMind
 
Uh...because I learnt it in school?
 
So, assuming Latin derivative languages maintain the gender of that word, the OP is not a native speaker of such a language.
 
Ooh, didn't know you were german
 
@BernardMeurer I also learned it but brain damage.
 
I just get a fancy word in Portuguese, put "um" at the end and its correct 90% of the time
hole->cavidade->cavum
 
10:36 PM
Besides German and Romance languages are there any others that have genders?
Hard mode: no Google cheating
 
10:53 PM
why can the spin vector of a relativistic particle not be orthogonal to its momentum? I can see that it would lead to problems, since the spin vector has to "approach" the momentum axis at high speeds, but what happens when we accelerate an electron in spin up eigenstate along the x axis?
 
@Bass From a QM perspective, the spin up vector has a component along the X axis
You can expand the spin up state in terms of X axis eigensates
 
you can expand in any eigenstates...
 
@Bass How is the spin vector for a relativistic particle defined again?
 
@0celo7 why? if an electron in spin-up eigenstate (z axis) is in a potential in the x direction, it gains some momentum which is purely in the x axis. Which relativistic process changes its spin?
 
How is the spin defined again?
2
 
11:00 PM
@0celo7 Dirac spinors. But I think this can be answered without the full Dirac theory. Just imagine the electron in its rest frame, in a spin up eigenstate. Then some potential sets in and the electron goes off to +x. Something has to change its spin, otherwise spin and momentum would be orthogonal
 
How is the spin vector of a Dirac sun or defined
 
@0celo7 uhh.. two-dimensional irreps of $SU(2)$ or $SL(2,\mathbb C)$? Don't know what you want to hear?
 
Well I'm not talking about the state vector...I'm talking about the 4-vector
Is that what you mean by "spin vector"
To say that it's orthogonal means you have some definition where orthogonality has meaning
I think
 
I mean that if you measure spin (say non-relativistic QM), you have to decide along which axis you measure. Usually in the literature they choose z. This measurement puts the spin in a "spin z" eigenstate. This direction is what I mean by spin vector.
In this sense, the spin vector is a normal 3-vector, which can be orthogonal to the 3-momentum
for example Stern-Gerlach, if the magnetic field lines are more or less along the z axis, then you measure "spin z"
 
In which frame is it a 3 vector
Since we're talking about Relativistic QM
What frame are we considering
 
11:09 PM
8 mins ago, by Bass
@0celo7 Dirac spinors. But I think this can be answered without the full Dirac theory. Just imagine the electron in its rest frame, in a spin up eigenstate. Then some potential sets in and the electron goes off to +x. Something has to change its spin, otherwise spin and momentum would be orthogonal
 
It has zero 3-momentum in this frame
So it's trivially orthogonal to the spin
 
Please read my previous msg: Then some potential sets in.....
 
@Bass Uh, ok. I don't see how momentum is not zero. But why do you think they can't be orthogonal?
 
@0celo7 It's non-zero when the electron starts accelerating because of the potential.
maybe I should have said "lab rest frame" instead of "rest frame". I mean the frame where the elecron is at rest initially, but when the potential sets in, the electron starts moving.
 
According to Weinberg spin is always orthogonal to 4-momentum.
Page 47 of Gravitation and Cosmology.
 
11:19 PM
and 3-momentum? counter-example the photon, whose spin is always in the 3-momentum axis
 
I meant to say 4-velocity.
 
(what's the word for two vectors in the same axis? besides linearly dependent? colinear?)
 
Parallel
 
duh!!! :D (same as in german)
 
Jawohl
 
11:22 PM
gonna ask that on the main site
 
@Bass Note that since orthogonality is frame independent they will be orthogonal in the lab as well.
 
0
Q: Why can the spin of a relativistic particle not be orthogonal to its momentum?

BassI have read that the 3-momentum of a relativistic particle cannot be orthogonal to its spin 3-vector. When thinking about how the spin vector transforms when the particle approaches light speed, it seems clear that it cannot be orthogonal to the boost direction, but I'm wondering what is the exac...

 
user54412
@ACuriousMind yes; "this coming" and "this past" can be used to differentiate; "next Monday" would be in 13 days for me (though confusingly this would also be "the Monday after next")
 
user54412
also, the first day of the week is country/language/religion-dependent
 
11:38 PM
First day of the week is Monday. Everyone else be dammed -- we won the war.
 
@0537 The Reynolds number limits (high, low) should be easy to program yourself if you're into that. You should find ample material for Euler equations, which are the type of stuff you see in screensavers. Lattice Boltzmann, smoothed particle hydrodynamics and variants of the vortex method usually provide the stuff you see in movies (and games) so plenty of references all over the interwebs. Finite difference and spectral should also be relatively easy if you do a couple of approximations.
 
Is the tag solely for astronomical binary systems? 4/5 questions use it in that context.
 
@Bass Unsolicited nitpick: orthogonality of 3-vectors is not a Lorentz invariant statement. So you're saying that in the lab frame specifically the spin and momentum 3-vectors are orthogonal?
 
11:54 PM
@0celo7 which other frames did we consider?
 
Rest frame?
 
re unsolicited nitpick: if one of the vectors is parallel to the boost direction, i think orthogonality is Lorentz invariant
 
user54412
@HDE226868 My suggestion: untag that outlier, rename the tag to binary-stars, and put something in the tag wiki. If anyone wants binary data, they can make a new tag.
 
user54412
Reminds me: I need to do this for
 
@Bass Maybe...I'd have to do that calculation myself. On mobile in a parking lot so that won't happen.
 
11:58 PM
@DavidZ Can you rename the tag?
@ChrisWhite Okay, edit done. It was a closed question, anyway.
 
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