« first day (4930 days earlier)   

1:27 AM
@SillyGoose Causal Perturbation theory is good if you can understand it
@Obliv That is the $\beta\to\infty$ and $\beta\to0$ limits. You know the Taylor expansion of exp, which applies to the zero limit. The infinite limit, convert to negative exponents, so that then the exp goes to zero.
@SillyGoose ok, nice; when you are doing these integrals, say the last one, is it $\int_0^{\pi/2}\cos^4\theta_{n+1}\,\mathrm d\theta_{n+1}$ alone, or are there a lot of $\int_0^{\pi/2}\mathrm d\theta_i$ to also integrate?
Anyway, I'm sure you will find the following identity useful $$\cos^2\theta=\frac{1+\cos2\theta}2\qquad\bigwedge\qquad\sin^2\theta=\frac{1-\cos2\theta}2$$
 
1:46 AM
m i a o ~
 
thanks, I did have to give up and look at the solution. I'm definitely memorizing it I've seen it this many times
power series, geometric series, etc. I'm going to do a nice review of fundamentals of calculus after finals
 
 
1 hour later…
2:50 AM
wow it just occurred to me, as I was working this problem out that involved radio waves
gigahertz are really slow..?
er wait
why are radiowaves in the 20kHz to 300+GHz range
my familiarity with frequencies involve computer processors where people consider higher GHz to be "faster"
 
f =1/T
 
hmm ill have to recalculate then lol
yea nope i did it right.. I'm getting an associated radiowave of 841GHz for the absorption frequency of this paramagnetic solid
I'm buggin
or maybe this is normal and i wasn't aware cpus operated at the same frequency as radiowaves..
whatever CPU frequency even means
ye nvm that's too high to be radiowave. I suppose I did it wrong
 
 
3 hours later…
6:30 AM
@SillyGoose there's only one thing worse than QFT
Rigorous QFT
 
7:09 AM
is q²/T a possible new username for you? (joke) @fqq :P
 
By the way, I've always wondered what "fqq" stands for
 
Dec 15, 2022 at 23:41, by antimony
finest quantum questions
 
 
2 hours later…
8:55 AM
So are we considering complex transformations too?!
Infinitesimally, $D_n$ generates $\theta\mapsto\theta+\mathrm{e}^{in\theta}$
 
9:28 AM
@Mr.Feynman hi. complex valued diffeomorphisms do not make sense on a circle, so theyre probably only using these as a basis for real diffeomorphisms
one can take linear combinations of these generators to get the $\sin n\theta$ and $\cos n\theta$ generators, which then only form a basis of real diffeomorphisms
 
Oh, like the usual Fourier basis
 
this is an example of a basis of an infinite dimensional lie algebra. i wonder if one cud also use the delta functions here
or maybe the Hermite polynomials for diffeomorphisms on the real line
really pretty how math ideas assemble
 
@RyderRude why would you?
 
idk. theyre probably too pathological for lie algebras
imagine $\delta (x-x_0)\frac{d}{dx}$ lol
 

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