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09:43
uh, so I just noticed Forth has been used thrice... and the third time was by me...
I solved the next sequence. Try it online! (I'll try to port it to another language)
Warning: Very inefficient
I did it also: Try it online!
@NieDzejkob Can't you just switch the version?
(in Python)
I'll try another more efficient approach in Pyth too
And then port
Got a much shorter and much more efficient one now: Try it online!
Let's see... Looking for a golfing language that hasn't been used yet (Except for Brachylog) Perfect... Gaia!
@NieDzejkob Posted (I thought I'd let you know just in case you were porting it too).
10:16
CMP: How much rep did you earn thanks to "One OEIS after another"
@Mr.Xcoder 380.
Caird should have gotten exactly double according to my calculations, 760
 
2 hours later…
12:22
@Mr.Xcoder Forth compatibility is, to put it mildly, terrible
Ah ok.
It would be best to find a Forth with arbitrary arithmetic, because if I'm specifying the interpreter, it better compute the sequence up to a 1000
@NieDzejkob You'll change the language without affecting the byte count or something?
Or you can just let it be this way, as long as you don't use Forth in the next 150 languages (a new series is coming soon) ?
but it still might be a problem since answer #256 needs more than 64 bits of integer precision to compute indexes above 17
IDK I have 0 experience with forth...
12:42
I have an idea
I'm all ears
13:27
@Mr.Xcoder edited
Thanks god you fixed that
Actually most Java solution overflow 32 bit int...
Shhh :P
it doesn't matter if the result doesn't fit in 32 bit, but this divided a big number by another big number at the very end, which makes the result fit, but not the intermediate steps
13:50
@Mr.Xcoder Any way to calculate it efficiently? ...
@user202729 Yeah. Type user:me One OEIS after another in PPCG's search bar, add the votes on each and multiply by 10 (unless you are caird)
In that case, add 83 * 5 - 3 * 2.
var a=$('.vote-count-post strong'),s=0;for(var x=0x<a.length;++x)s+=+a[x].innerHTML;s*10
> 500
(assuming they fit on one page)
 
4 hours later…
17:49
Am I right that the g.f. for the next sequence is [1 + 2(x + x^2 + x^3 + x^4 + x^5 + x^6 + ...)]^5?
 
1 hour later…
19:08
new sequence
(and the feed still doesn't work)
19:26
New sequence
The next one is really nice.
 
3 hours later…
22:47
Solved it in Unefunge, with an easter egg as padding :P

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