and \

is overwritting I thinl

Why Logical AND?

Just use concatenation

to add to end

ooooo

brb in 10 mins

I found the solution for an extra 2 bytes and replacing one byte.

Ḷ”$ẋ;”\Y

concats to end on the whole thing not each element

Yes. Now what do you do to make something happen to each element of a list?

multiply?

No. Remember the map quick we were talking about?

y

ea

?

how do I use € to map

You put it after the atom you want to affect.

That means you want to map over ;”\ .

Ḷ”$ẋ€;”\Y

However, do note that that's 2 links, so you need to combine the two links into one chain and map over that single chain, hence the second byte used.

tio.run/##y0rNyan8///hjm2PGuaqPNzV/ahpjTWQGRP5//9/UwA

@NoahCristino No. You don't want to map the repeat since that's fine already. You want to map over the concat part.

how do I map over?

@HyperNeutrino

brb

OK. So, during parsing, a Jelly program is converted to links which are then chained together. The links are put onto a stack of links (functions, essentially). When a quick is encountered, it will pop off a number of links and push a new link with a different function. So, putting € after a link will remove that link and make its function to apply the original link's function to each element in whatever iterable it receives as an argument.

back

what are links exactly?

A link is an atom or a group of atoms that have been put together.

ok

so

what does mapping do?

just like a loop over an array?

@HyperNeutrino

Let's say you have concat. If you're given ["a", "b"] as input and you concat("c"), you get ["a", "b", "c"]. However, if you map over concat("c"), you get ["ac", "bc"] because you're applying to every element in the array.

ok

how do I map over concat?

You put the map quick after the link.

after what link?

@HyperNeutrino

Firstly, you are mapping over concat("\\"). Since that means you have a dyad (concat) followed by a nilad (string literal), you need to combine them into a monad. How do you combine two links into a monad?

shouldn't I map like this

Ḷ€;”\”$ẋY

Uh, no.

That way you're taking the range, concatenating a string to each number, and then repeating the string. That won't work.

oh

so

anyway brb

µ? @HyperNeutrino

hi @DigitalTrauma

can you help me?

@StepHen I need help

@NoahCristino can I help?

yay

sure

What's the challenge?

tio.run/##y0rNyan8///hjm2PGuYqPNzVHfn//39TAA

the diagnol line

I need to map and concat a \ to the end of the array

@cairdcoinheringaahing

@NoahCristino ok. So what's the command for concat?

;

and map is €

I have €;”\

but I don't know where to put it @cairdcoinheringaahing

@NoahCristino how is € used? Where do you place it when working on a dyad?

<dyad>€

@NoahCristino exactly, so where should you move the €?

but what dyad do I put it after?

if I put after ẋ

@NoahCristino with the link you gave me, and €;”\ , you have all the commands you need.

it uses that as the right arg

tio.run/##y0rNyan8///hjm2PGuYqPNzV/ahpjTWQGRP5//9/UwA

@cairdcoinheringaahing

@NoahCristino what command should you be mapping?

;”\

oh

;”\€?

@cairdcoinheringaahing

@NoahCristino what's the dyad in ;”\ ?

none

; is a monad

@NoahCristino is it?

nvm

dyad

tio.run/##y0rNyan8///hjm2PGuYqPNzVbQ2kYx41rYn8//@/KQA

@NoahCristino so if ; is the dyad, where do you place the €?

before

before

the dyad before

i mean

@NoahCristino yes.

tio.run/##y0rNyan8///hjm2PGuYqPNzVbQ2kYx41rYn8//@/KQA

but it doesn't output anythinggg

TypeError: <lambda>() missing 1 required positional argument: 'x'

@NoahCristino because € isn't in front of the dyad, its in front of the nilad

tio.run/##y0rNyan8///hjm2PGuYqPNzV/ahpjTWQGRP5//9/UwA

@NoahCristino that's the wrong dyad. What are the dyads in the code?

the ; is the dyad

tio.run/##y0rNyan8///hjm2PGuYqPNzVbf2oaQ2QGRP5//9/UwA

I did it

@NoahCristino good. Now, can you remove 4 bytes?

nope xD

@NoahCristino what takes up a lot of bytes in the program?

the strings

@NoahCristino so lets try to remove them

how?

What's the first string?

a space

@NoahCristino or ' ' in python?

ya

@NoahCristino so look for ' ' in the atoms page

k

Ḷ⁶ẋ;€”\Y

@NoahCristino so that's one out of 4 gone. Lets take a look at the other string.

k

\

Does it have to be a \?

no

@NoahCristino what 1 digit things can it be?

any thing

thats not a space

@NoahCristino try replacing ”\ with various characters, see what works

I can do this Ḷ⁶ẋ;€ƈY

and put \ in the input

tio.run/##AR4A4f9qZWxsef//4bi24oG24bqLO@KCrMaIWf//XP8xMDA

@NoahCristino that's not allowed.

why not

@NoahCristino it can only take 1 input

Rules of the challenge

aw

you mean characters

without ”

infront

@NoahCristino do I?

idk do you?

What's the current challenge?

@HyperNeutrino diagonal line

i'm just golfing down now

tio.run/##AR4A4f9qZWxsef//4bi24oG24bqLO@KCrOKAnVxZ////MTU

@NoahCristino just try replacing ”\ with characters on your keyboard

See what works

k

tio.run/##y0rNyan8///hjm2PGrc93NVt/ahpTV3k////DU0B

I get -16 but it works

@NoahCristino single character, sorry. But close

why does that output -16?

. outputs 0.5

Because ~ means bitwise invert which is -1 - thing

@NoahCristino ~n is the same as -n-1

. => 0.5, - => -1

Also this ;€”\ trick is nice I forgot about it lol

@HyperNeutrino markdown hates this challenge

I can't find anything

Yeah especially since \\ doesn't isn't even an escape

@NoahCristino Think about it. . did 0.5 which is a literal. What one-character literals are there?

0?

@NoahCristino what does that produce?

®

That's not a literal.

but ® produces 0

I mean, it works in this case, but that's not what it's meant to do.

Ḷ⁶ẋ;€®Y

tio.run/##ARwA4/9qZWxsef//4bi24oG24bqLO@KCrMKuWf///zE1

hahahahhhah

@NoahCristino good. Now to golf 2 more bytes. On a separate note, I have to go now, bye!

2 more chars...

bye

o/

... code-block formatting

ik

that's hard

im going to try an easier one first

no just put 4 spaces before each line

I mean a new challenge

oh you meant the challenge is hard

ya

the square is easier

What square

Draw a square with side length N

Okay

how do I make 2d arrays?

@HyperNeutrino

You wrap an array into an array and repeat it

okkk

@NoahCristino Progress?