@EriktheOutgolfer OK, let's see if I understand either of those. A nilad-dyad would compute dyad(nilad, a), and dyad-nilad would compute dyad(a, nilad)? Or does it depend on whatever comes next?
@NoahCristino when you post it here, wrap it in backticks (like you did), but when you actually code, don't wrap in backticks, unless you need the backtick commnd
@EriktheOutgolfer So to make sure I understand, <dyad>@<nilad> works by swapping the operands, so instead of dyad(a, nilad) you get dyad(nilad, a), but in a nilad-dyad pair, the nilad will always be the left argument, so <nilad><dyad> is basically the same thing?