Electrons are particles and have a mass, and Newton's first law applies to them. If you accelerate an electron up to some velocity by applying an electric field to it then if there is no resistance that electron will just carry on moving at a constant speed. Yes?
So about Wheatstone bridge or any circuit whenever there is 0V across why do we remove capacitor or resistor? It makes sense if resistance is high to stop momentum of electron but what if it small or ideal capacitor with 0 resistance
I mean current can still flow through that segment but it doesn't
Electrons do have a momentum, but it's a very, very small momentum. The drift velocity of electrons is typically less than 1 mm/s and their mass is about 10⁻³¹ kg.
So it's very, very easy to stop an electron!
Even a tiny resistance will do it.
I suppose you could argue about what happens with a truly ideal wire, but in real life there is no such thing.
Well both are true. I guess you're wondering about which is cause and which is effect i.e. does C₁/C₂ = C₃/C₄ cause ΔV = 0 or is it the other way round?
@JohnRennie Nah. I am still at Dorm. I am working on some project under a professor and he is unpredictable. Call me at random times to visit him T_T. The next sem starts from 1Jan
@JohnRennie Not really. Everyone is just interested in getting placed after graduation and just give exams for the sake of it. They are not really interested in tech or something. But such is life!
Given the circuit in the figure, determine the current intensity through each resistor, the potential difference across resistors $R_2$ and $R_3$, the power dissipated by each resistor, and the total power supplied by the generator.
Given the circuit in the figure, determine the current intensity through each resistor, the potential difference across resistors $R_2$ and $R_3$, the power dissipated by each resistor, and the total power supplied by the generator.
When it asks for the potential difference across a resistor it is asking for: ΔV = IR where I is the current through the resistor and R is the resistance.
i.e. the difference in the potential between the two ends of the resistor.
Like I was doing this question. While calculating the centrifugal force of a rotating body, do we take the rel angular velocity (the angular velcoity of the body wrt the rotating frame)?
Calculate the magnetic induction field at point $O$ marked in the figure, generated by the current $I$ flowing through the circuit, with $a$ and $b$ being the given distances. Furthermore, place a small magnetic needle at $O$ with a magnetic dipole moment $m$, oriented perpendicularly to the magnetic field $B$ produced by the circuit.
Write the torque of the forces acting on it and the work done in rotating it by $90^\circ$.
$(Data: I = 2 \, \text{mA}; a = 1 \, \text{cm}; b = 2 \, \text{cm}; m = 3 \, \text{Am}; \frac{\mu_0}{4\pi} = 10^{-7} \, \frac{\text{Tm}}{\text{A}})$
