In Kavin's last question you said that the equilibrium extension is half the maximum extension. Will that hold for all cases, like a spring attached to a wall at one end, a spring-pulley system, etc? If not, how did you decide it was applicable in that case?
But you do have to think about the system e.g. with a spring attached to a wall the equilibrium point is when the spring is relaxed. Then the two extremes are an extension of A and a compression of -A.
So the equilibrium point is still halfway between the extremes, but unlike the mass hanging from a spring the equilibrium point is zero extension.
@StutiGupta This method comes in useful when the equations are hard. That question about pulling the masses connected by a spring is a good example of where using the equations of motion is hard but using the equilibrium extension is easy.
@JohnRennie Oh, I see. Though if we were to give the first block an initial velocity and a force of 90N as well, then? (I'm sorry, I haven't done SHM yet.)
@KavinIshwaran I for ring is about point of contact. You can visualise by imagining 3 scenarios
Imagine it's I is about centre then it would remain constant no matter where it is
So rolling ring with some acceleration would feel same everytime
But that's not true, If a person have to roll the ring on surface then it would take highest force in 1st case and lowest in 3rd and hence proved that we take MOI of mass m about point of contact.
Problem Solving Strategies
Problem Solving Strategies