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08:08
@JohnRennie hi
@Nobodyrecognizeable hi :-)
@JohnRennie had a question
Yes ... ?
not that
sorry let me find it
@JohnRennie this one
@JohnRennie sorry for delay . first time through laptop
The difference between an isochoric process and an isobaric process is that in the former the density remains constant while in the latter the density is proportional to 1/T.
I guess that's what the question is getting at, since the mean free path depends on the density.
08:19
@JohnRennie yes on number density. actually inversely proportional
$PM=dRT$
The mean free path also depends on the velocity, and that is proportional to √T.
So I guess you write down the expression for λ and then see how the various terms in it depend on T.
I must admit I'm not sure what the question is asking.
$\lambda= \dfrac{1}{\sqrt{2}\pi b^2 n}$
n= number density
I'm used to the form:
$$ \lambda = \frac{kT}{\sqrt{2}\pi d^2 P} $$
pv=nKT so p/KT = n/v=number density
08:27
@satan29 @JohnRennie yes
So for an isobaric process $\lambda \propto T$
@JohnRennie how can we prove the latter part of the statement
10 mins ago, by John Rennie
The difference between an isochoric process and an isobaric process is that in the former the density remains constant while in the latter the density is proportional to 1/T.
For an isobaric process $V \propto T$. Density is proportional to $1/V$, and since $V = constant \times T$ the density is also proportional to $1/T$.
@JohnRennie PM=dRT ; how do we know that the density for isochoric process is constant?
d= density
@JohnRennie got it
No problem
Thanks for the help
 
3 hours later…
11:41
I wanted to ask how to revise the chapter
Like a solved questions on circular motion which are 300 pages. Many I solved. Then , some questions are similar to other questions even sub parts of certain question are.... Some are way too hard questions and certain are easy. The level of difficulty is also shuffled inside the notebook where I solved all my questions.
Some questions have tricks which are similar to other question . So , exactly I don’t have to revise it again. Then , what should be my strategy to revise all of the questions that I need to only.
Also , I feel some questions I should have had solved with more tricks or more ways. Which I haven’t now.
 
3 hours later…
14:50
Anyone can answer .

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