OK sir, I have a circular plate dipped in a liquid of density k, plate has a mass M, and radius R, disc is allowed to rotate vertically, I need to find the resistive torque offered by liquid, if the disc is rotating with constant angular velocity $w$, by a constant internal mechanical force $F$. @JohnRennie
Container height is $H$, and disc is dipped completely, actually sir I do not have the pic, because I got the same language question through whatsapp @JohnRennie
I have no idea how to start with this. Sorry I forgot to give liquid mass it is $m$,
Whenever you are making a liquid flow there are two forces: 1. viscous 2. inertial
Generally speaking viscous forces dominate at low flow rates and inertial forces dominate at high flow rates
The viscous forces come from the thickness of the liquid i.e. how gooey it is. It takes more force to make a thick liquid like honey flow than to make a thin liquid like water flow.
the inertial forces come from the fact the liquid has a mass, and to make it flow you have to accelerate it. The force is due to Newton's second law F=ma, where m is the mass of the bit of the liquid you are accelerating and a is how much you accelerate the liquid.
@yuvrajsingh in this problem we aren't given the viscosity, so that implies we are supposed to consider just the inertial forces.
But we don't know how much the liquid is being accelerated by the rotating disk because it depends on exactly how the liquid floes around the disk.
@JohnRennie okay sir...ethane is already saturated...but after combustion it releases more energy than ethene which is unsaturated...I got the reason...but isn't it a bit confusing sir?
@JohnRennie sir, since hydrogen is highly combustible, can we say that since ethane has 6 H's while ethene only has 4 hence ethane releases more energy...sorry if that's wrong...I made this reason
@JohnRennie I am having some difficulty in trying to understand your answer. Will be thankful for any help. Actually time reversal can be written as a product of unitary operator and complex congugation operator.In the coordinate space the unitary operator is just an identity operator so one just takes the complex congugation.
We know that, Convection is the mode of heat transfer due to the motion of individual molecules of a fluid (liquid or gas). The motion of the constituent particles arises due to difference in densities.
In the absence of gravity, water takes a spherical shape in order to minimize the energy due ...
@JohnRennie, I think, upon heating water gradually from the centre, the heat must travel to the surface by conduction. When the entire sphere's temperature reaches 100 degree Celsius, bubbles start to form at the centre. After that I am clueless.
I don't know whether it will explode or not.
I don't know how will convection behave in the absence of gravity.
Ok, so we could put a heating element on the end of a wire, push the element gently into the middle of the drop then turn on the electricity to heat it.
Water is a very poor conductor of heat. The reason water heats up fast in a pan on the oven is because we get convention currents that mix the hot water at the bottom of the pan with the cold water above it.
In zero g there are no convection currents, so what happens is that the water in contact with the element stays there and heats up fast while the rest of the water stays cold.
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Eventually the water in contact with the element boils and forms a bubble of steam around the element.
@Intellex yes, but if we keep pumping in heat that heat has to go somewhere. What it will do is heat the steam in contact with the element, and that steam will heat the water at the edge of the bubble of steam and make it evaporate. So the bubble of steam will grow steadily.
The bubbles explode because they superheat. The oil prevents the nucleation of steam bubbles you get when heating water in a pan, and the water drops turn to steam all at once and of course the steam expands explosively.
Even though water and steam are in equilbrium at 100°C there is a potential...
That describes what superheating is, and actually it's quite relevant to what we're discussing here.
@JohnRennie, Reading in progress, but a small doubt. Why should steam bubbles form at scratch points or defects? Is that something to do with surface tension sir?
@Intellex water molecules generally interact strongly with the molecules at solid surfaces, and this can lower the activation neergy for formation of a bubble.
As @user8718165 says, this process is called nucleation.
Exactly how this occurs is going to depend on the exact interaction going on and is generally complicated.
@Intellex no. You get superheating because there is a barrier to nucleation of a steam bubble. You need to get the temperature above 100°C to generate enough energy to get over this barrier and form the bubble.
So this will probably happen with your droplet floating in zero g.
Of course you can put the water into a pressure cooker and heat it at increased pressure, but that needs some form of pressure vessel. Superheating happens at ambient pressure.
Anyhow, if superheating happens with your water drop in zero g then when the bubble does nucleate you'll get an explosive growth in the bubble size as the superheated water changes rapidly to steam.
The drop will explode and spatter boiling water all over you :-)
Now some notifications in my brain: I have seen supercooling - where one shakes some water after taking it from refrigerator when it immediately freezes to form ice. Is this the analogue for superheating?
@JohnRennie So sad, I thought the story must be a good-ending one :)
@Intellex yes, supercooling happens for exactly the same reason. There is a barrier to nucleation of an ice crystal just like there is a barrier to nucleation of a steam bubble.
The Wikipedia Article on Van Allen Radiation Belt gives the following explanation:
A Van Allen radiation belt is a zone of energetic charged particles, most of which originate from the solar wind, that are captured by and held around a planet by that planet's magnetic field.
The term "energ...
In the Magnetic Bottle 1 YouTube video the charged particles are reflected from the ends of the bottle (where the ring are) because the magnetic field in non-uniform there. The particles tend to stay in the middle of the bottle where the field lines are roughly parallel.
The same thing happens i...
@JohnRennie, Thank you for sharing that sir. I will read that and ask if I have any doubts. I thought I discovered something new based on my high school physics and some little about astronomy. You know I was on pins and needles after this idea came into my mind :)
It's always good fun thinking about things like this. I used to do it all the time as an enthusiastic teenage physicist. 99.9% of the time you won't find anything new, but it's fun anyway :-)
After my PhD I became an industrial scientist working for Unilever. As a general rule you only get to be an FRS if you stay in university and become a professor.
Life is hard for scientists trying to stay at university. Only a very small percentage end up with a senior academic post. I decided to go into industry and make lots of money instead :-)
Well going into industry meant I made enough money that I could give up full time work when I was 50. That's why I have the time to answer questions here.
No. Making plans is fun but basically pointless. You can never tell how things are going to work out. As it happens two of the companies I have worked for no longer exist, so if I had tried to stay with them I'd have lost my job.
As it is I had left for a new job before they shut down.
With the JEE I think it's not really about learning physics or chemistry or whatever. It's about learning how to answer JEE questions fast and accurately.
I suspect the toppers are just people who have really good memories and manage to memorise enough previous JEE questions that they can recognise the questions in their years exam.
@JohnRennie no sir...you tell stuff from your memory...I'm pretty sure...I also google questions before asking you. I hardly find what I need there :-(