when you have a Euler graph where two of the edges are odd but one is 1 while the other is 3 can you visit all the edges
this is my euler graph [["MUC", "LHR"], ["JFK", "MUC"], ["SFO", "SJC"], ["LHR", "SFO"]] I can visit all the vertaces but not all the edges is this problramatic?
if I start from an odd vertex i can visit all the edges
but I can't visit all the edges form an even vertex
I was under the impression that I can visit all the edges from any vertex but I might be wrong.
@Abcd Yes. The forces are always equal and opposite, and they act for exactly same amount of time. So impulses are equal and opposite. Impulse = change in momentum. So change in momentum is equal and opposite for both parts.
@Abcd I found the question difficult to understand also. The two cars are moving to right at same speed of 30 kph, 5 km apart. The 3rd car is coming towards them moving left. It passes lst car then 2nd car. Time between passings is 4 mins.
If you imagine 1st and 2nd car at rest, 3rd car moves 5km in 4 mins which is 75 kph. From that you have to subtract 30 kph which is speed of 1st and 2nd cars. But it is same as your calculation, which is correct.
@Abcd Some of these problems the hardest part is understanding what the question means!
A question in my textbook involve finding the electric field amplitude at a point in space given the intensity of light. It uses the following equation to solve it: -
$\frac{1}{2}I=\frac{1}{2}\epsilon_{0}|E_{rms}|^2c$
But where did this equation come from? I am unable to find an explanation for...
@Abcd You said reject option 1. But we can reject that also because if intensity from each slit is different the combined intensity will never be zero.
@Abcd How did you get C?
You mean option 3?
I agree, option 3.
You wanted to learn "trick" methods so that you can get the answer quickly. Formal method will take too long in an exam.
@Abcd Yes if you want. It amounts to the same thing. Adding two oscillations with a phase difference between them. Try it using whichever method you want.
2nd question : Use conservation of angular momentum about point of contact ; $mv_0r=I\omega=\frac32 mr^2\omega$.
3rd question : Calculate the circumference $C$ of the drop which is squashed between the plates. The force on each plate is approx $\gamma C$.
I am not sure how the angle of contact can be used in this calculation. Also the volume of the drop. Seems to be too much information here.
@Abcd At some point the amplitudes from slits 1 and 2 are A1 and A2. There is a phase difference of phi between them. They have same frequency so phase difference does not change with time, it depends only on position.
If you do not like this explanation use one which you do like.
I've read it a lot of times. But I've not been able to get around magnifying power and magnification of a simple microscope and the difference between them. Can someone explain?
@Abcd No. In children the lens material is more flexible and muscles are stronger because they are newer. So the eye is more "adaptable". It can adjust more easily to focus on closer objects - and further ones also.
@sammygerbil i was interpreting the definition of least distance of distinct vision like "child can see distinctly objects till 8 cm only" and "elders can see till 200 cm" which was wrong
@sammygerbil i was interpreting the definition of least distance of distinct vision like "child can see distinctly objects till 8 cm only" and "elders can see till 200 cm" which was wrong
This^.
@sammygerbil Also, sorry for concept questions. Please tell whenever you arent OK with it frankly. Wont ask then.
@Abcd To view something comfortably it should be at the least distance of distinct vision. Objects which are closer appear bigger so they can be seen more clearly, but the closer they are the more difficult it is for the eye to focus on them. A distance of 20-25 cm gives the best compromise. So that's where you want the image to be.
@sammygerbil D= 25 cm means object should be at least (or at most?) 25 cm (that is externally 25 cm away from the eye?) away from us so that we can see it properly?
@Abcd The closest distance to focus without discomfort is D=20cm. Any closer you can probably see it by squinting but you will quickly tire out your eyes doing this.
You could not read a whole chapter of a book at 5 cm from your eyes. For most adults the comfortable distance is 20-25cm. They can focus on things closer for short periods, a few seconds, but the eye will quickly tire and become uncomfortable.
@sammygerbil Now my question is why is there no "maximum distance of distinct vision " ? ... Like we cant see any far off things after like 20 m or something...
Thanks. OK let me contextualize a little bit. I have to get the pressure of a gas as a function of its density. This is the integral I have to solve. imgur.com/a/mDhUUnQ Do not worry about the terminology. $\epsilon_f$ is the fermi energy.
Now I will explain what I have done
And in what exactly I am stuck with.
We know to what a specific part of this integral equals to: imgur.com/a/dxn1Ipd