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17:00
I think your argument is not correct
even tho it seems logical
I don't know
need a rigorous proof
Why can't it be a "rigorous proof" ?
ask in the h bar
it doesn't sound conviencing
they will point out the flaws
try showing your entire proof in h bar
Anonymous
17:04
@Yashas Ah, that is interesting. You should "definitely" take up CS in college :-) Personally am not so interested in programming
Getting CS in IIT is way to hard
Anonymous
1000 should be good enough?
Anonymous
You'll get in the new iits
sssh
new iits are not good
Anonymous
CS departments in the new iits have some of the best students
Anonymous
17:06
Professors are useless everywhere
Anonymous
=P
Anonymous
I'd choose branch over college
I'd take EE
Anonymous
@Yashas Well, I was thinking of engineering physics
Anonymous
Or mechanical
17:08
you get engineering physics at 5k
Anonymous
@Yashas That'll do :P
I want CS or EE becaz I want $$
Anonymous
I'm sorta scared you know...maybe I'm dreaming way too much before advanced
I have multiple projects WIP
another work in progress project
this one is big
Anonymous
@Yashas Considering the fact that Sundar Pichai was from metallurgy...I tend to believe that department doesn't matter anymore :P
Anonymous
17:11
@Yashas Cool!
Anonymous
Yep, I did see your Github page :-)
trying to port the entire C++ standard library to a scripting language ._.
try to prove that formula
prove that formula too
Anonymous
Gimme a break =P
Anonymous
I'll take days to prove that
Anonymous
17:14
Ok, I've some jee questions now
Anonymous
In $E=n\frac{hc}{\lambda}$ if E=288 kJ/mole then what will be $n$? I can't understand from where they are getting a conversion factor of $96$ kJ/mol
Anonymous
How is 1eV=96 kJ/mol ? @Yashas
-.-
1eV per unit = 96 kJ per mol
It is similar to faraday's constant
F = e * N_A
Anonymous
@Yashas Per unit?
here E = 1 eV * N_A
but 1 eV = 1.6 x 10^-19 J
so the numbers are the same for both
F = 96500 C
1ev = 96500 J
@blue yes
you cannot have energy = energy/mol
dimensions don't match
each photon might be having X eV
Anonymous
17:19
@Yashas exactly my point...
a mole of of photons will have X 96kJ
Anonymous
So 1 eV energy for 1 mole of electrons
Anonymous
Hmm
Anonymous
I get it
Anonymous
Oh god
Anonymous
17:20
I'm so dumb
Is the question now correct on h-bar?
US drops biggest 'mother of all bombs' in Afghanistan: Pentagon
Is another war starting?
it was not a nuclear bomb -_-
stupid news media
they titled it "mother of all bombs"
Anonymous
@Yashas wtf
17:26
The GBU-43/B Massive Ordnance Air Blast (MOAB pronounced /ˈmoʊ.æb/, commonly known as the Mother of All Bombs) is a large-yield conventional (non-nuclear) bomb, developed for the United States military by Albert L. Weimorts, Jr. of the Air Force Research Laboratory. At the time of development, it was touted as the most powerful non-nuclear weapon ever designed. The bomb was designed to be delivered by a C-130 Hercules, primarily the MC-130E Combat Talon I or MC-130H Combat Talon II variants. Since then, Russia has tested its "Father of All Bombs", which is claimed to be four times as powerful as...
wikipedia already updated lol
On April 13, 2017, a MOAB was dropped on a target in Nangarhar Province, Afghanistan. It was the first non-testing use of the bomb.
They still don't answer the question @h-bar
Anonymous
@Yashas It is a massive bomb. I don't know why they used it.
Anonymous
The US seems to be bullying all the smaller militant striken nations.
17:52
They are not answering :|
they probably did not understand
I am going to sleep now
will see tmrow
Okay
Just once
Try this :
dy/dx = √(1-x^2) . y(0)=0. Draw graph of y vs x.
Oh hell... dy/dx=√(1-y^2). Y(0)=0. Draw graph of y vs x
(Try the last one)

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