@JohnRennie i didn't know that i thought it is so outdated

@PrateekMourya The laptop is about five years old, and it is a fairly basic laptop, but it will still work fine with Windows 10 and with an SSD would be pretty fast.

Ok

Can you judge the type of flow here i mean turbulent or streamline

I'm not sure.

To be honest I don't know that much about fluid mechanics. It was never a subject I enjoyed much.

Hello @JohnRennie sie

Sir

Hi

Here you can see there is variable density

Q26 ?

So i wrote f(bouyant) =v(density)g

Yes

But the density comtained some negative terms

So i break the force into to parts

Positive i treated as upthrust and negative one as downthrust and then applied wpe

Is the aporoach correct?

The question says Consider r << h0.

So?

So it is saying you can ignore the change in fluid density over the distance between the top and bottom of the ball.

Yes

So the ball is in equilibrium when the density of the liquid is equal to the density of the ball. Yes?

But the ball has gained some velocity till it reaches that point

So it will be some spring block situation

It asks for the equilibrium position of the ball.

If it is oscillating the equilibrium position would be the midpoint of the oscillation i.e. the point where the net force on the ball is zero.

And that point is where the density of the liquid and the ball is the same.

Ok so question is from shm

You do not need to worry about any oscillations the ball makes. The question just asks for the equilibrium position i.e. the position when any oscillations have ceased.

It is just $\rho_L = \rho_0(4 - 3h/h_0) = (5/2)\rho_0$

Actually i havent read shm yet

So the term equilibrium new to me

But now i know

Hello sir

I am not able to accept the solution of the book to this problem

@JohnRennie

Can you solve this your way

@PrateekMourya hi :-)

I would guess this is done by calculating the rate of change of momentum of the water at the bottom end of the tube to calculate the pressure.

Then subtract ρgh₀ and that gives you the pressure at the top of the tube. Then use Toricelli's equation to calculate the exit velocity at the top of the tube.

Why p1 =po+rhogy

How can hydrostatic pressure be equal to the presure at that point

Sir i have to leave now my test is about to begin

I will ask tomorrow

OK, see you later.