The angular equivalent of Newton's second law is:
$$ \tau = I \alpha $$
where $I$ is the moment of inertia, $\tau$ is the torque and $\alpha$ is the angular acceleration. At first glance it looks as if $I$ is just a scalar, but it turns out to be more complicated that this. To see why consider ro...
@ManasDogra ping me when you're around. This is simpler than it looks. The motion needs to look like this:
i.e. in the field the charge moves in a circle with some radius r and we need that circle to just graze the outer circle so the particle returns to the inner circle again.
Although it looks complicated at first sight there is a really simple way to calculate r in terms of a and b.
From this diagram, I found the radius..Thanks I drew the wrong circle...I drew one with centre on the X axis with centre at ((a+b)/2,0) and radius (b-a)/2,i.e.,the circle touches (a,0) and (b,0) as diametrically opposite points on it...
@JackRod Circular...But I drew the wrong circle..not quite sure why its wrong...
@AnnamalaiSriram It's from IIT JAM physics postgrad entrance exam of 2020.
I knew it comes from the multipole expansion of potential...
From Group theory? Can you mention a reference from where I can read that...I know introductory group theory at the level of Tung.