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10:28
⋄(⊂1 1 1)+¨⊆(1 1 1)(1 1 1)
@doug
┌─────┬─────┐
│2 2 2│2 2 2│
└─────┴─────┘
@doug doesn't do anything there.
⋄(⊂1 1 1)+⊆(1 1 1)(1 1 1)
@doug
┌─────┬─────┐
│2 2 2│2 2 2│
└─────┴─────┘
 
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14:59
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