I made one error of copy so I forgot of write one iota... Is it possible that f←{9≥k←⍵:0⋄∨/{14=∣r-k÷r←⍵⊃v}¨≢v←π⍵} is as f←{9≥k←⍵:0⋄∨/{14=∣r-k÷r←⍵⊃v}¨⍳≢v←π⍵}

is it a bug or not?

(the iota is the 7 character begin to end)

@RosLuP For that question you only need to test for the largest prime factor of n since p-14 will not have any prime factor greater than p

So, you don't need the ⍳

Oh, forgot about the n=p(p+14) case, but if p+14 is prime then call it q and you have n=q(q-14) So you're good. This provides some nice golfs, since you won't need absolute values

Never mind, you still need | (silly mistake)