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Kritixi Lithos
Kritixi Lithos
10:57 AM
@Adám so how would you do, say, 5&7 using the Under operator?
 
 
11 hours later…
Adám
Adám
10:17 PM
@KritixiLithos 5∧⍢(2∘⊥⍣¯1)7 for now, but if monadic ⊤ will be 2∘⊥⍣¯1, then it will be just 5∧⍢⊤7.
 

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