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1:50 AM
@Holo So I had a thought... instead of applying the Newton series to $b\uparrow\uparrow n$, we could apply it to $\frac1{b\uparrow\uparrow n}$. Would be cool if you could throw in some cool graphs for this with something like $b=2$.
 
2:03 AM
@user21820 hmm I'll give it a try!
 
 
7 hours later…
9:26 AM
@SimplyBeautifulArt but this would be just 1/(previous graph). It won't be so interesting no?
 
 
6 hours later…
3:23 PM
@SimplyBeautifulArt Did you manage to solve it? =)
 
 
1 hour later…
4:51 PM
 
 
2 hours later…
6:55 PM
array is a word which starts with "a" and ends with "y"
 
Lol
 

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