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09:08
Morning all
 
3 hours later…
SBM
SBM
11:38
Hello
gamma(0.5) = sqrt(pi)
?
@SBM yes
@SkeletonBow yo!
SBM
SBM
yes maybe by using Euler's reflection formula
By the way, I have Discord and Kik for anyone to contact me
@SBM you just need Euler's integral form of gamma function and a u-substitution followed by polar coordinates
SBM
SBM
Um, is it something like this?
I guess I need to learn integration
SBM
SBM
Really I do not think I know to handle multiple integrals
SBM
SBM
or some other kinds of integrals
Someone asked me
to find
$$\int \sin(\ln x) \mathrm{d} x $$
12:53
@SBM hm...no bounds?
@SBM have you tried anything like $x=ue^{k\pi}$ for even or odd $k$?
Hey, glad you noticed me :) just need a few more weeks, then I'll be free
13:12
@SkeletonBow cool! =)
 
1 hour later…
14:16
@SimplyBeautifulArt Good day! Any thoughts on this? mathematica.stackexchange.com/questions/144605/…
SBM
SBM
oh
not working
14:42
@InfiniteMonkey @SBM I'm here! Someone need me?
@InfiniteMonkey I haven't any experience on that
SBM
SBM
The function seems impossible to integrate
@SBM Without bounds, probably
SBM
SBM
How do you know if a function is integrable?
@SimplyBeautifulArt Ok thanks! I think I'll bounty a 100 rep on it to see if I can get some educated answer on the differences between the two...
In any case the student Alpha PRO is only about 60$/year so I will most likely buy it anyway since it can be accessed from the web, which is a major advantage.
@SBM A special algorithm
196
Q: How can you prove that a function has no closed form integral?

Simon NickersonI've come across statements in the past along the lines of "function $f(x)$ has no closed form integral", which I assume means that there is no combination of the operations: addition/subtraction multiplication/division raising to powers and roots trigonometric functions exponential functions l...

@SBM
SBM
SBM
14:54
oh
thank you
Look up "Risch's algorithm" @SBM

 Mith's Desk

@Mithrandir's office
SBM
SBM
ok
@Mithrandir Need help with xkcd feed?
14:58
@SimplyBeautifulArt nope, got it, I think
But it was inspired by you :)
okay :D
Perhaps you should get book related feeds
SBM
SBM
xkcd lol
 
3 hours later…
18:23
@SimplyBeautifulArt Ping! ding....dong / wing....wong / wring....wrong / sing...song / ping pong .... .....................
Not Good. Same user posted an additional 2 problem statement questions, and deleted both.....
-3
Q: Use mathematical induction to prove $n>\ln(n)$ for all integers n greater equal to 1.

MloUse mathematical induction to prove $n>\ln(n)$ for all integers n greater equal to $1$. $y=\ln(x)$ is an increasing function, that is, if $a<b$, then $\ln(a)<\ln(b)$. Using S_k and S_(k+1)

 
2 hours later…
20:06
@amWhy Voted to close, I'm pretty sure I already did earlier but I can't find that flag... OP don't seem to have done any work, doesn't know ln e = 1 and keep "squeezing out" further info from answerers, that is a NO.
20:36
mhm...
 
2 hours later…
22:46
It isn't, I am a highschool student and I know this, we are taught in Physics how to take a derivative rather than it's definition in beginning of 11th grade. Since Limits is taught before derivatives and after calculus in Physics, we use L'Hospital's rule (remembering the standard results of derivative) directly without knowing actual definition of derivative. — Jaideep Khare 29 secs ago
Anyone, just anyone tell me this is completely wrong.
23:00
hmmm... well as "anyone" I'd chime in and say that this is a bit silly but to be fair that person seems to refer to his/her personal experience with the learning of the subject...
yeah, but... its horrible in my opinion
I want a Rubik's cube like that
@InfiniteMonkey Say, you busy at the moment?
@SimplyBeautifulArt After reading the comment again I'd say you're right that comment is very wrong, on every level.
@SimplyBeautifulArt I'ts called a "mirror cube", it changes shapes, I own a handmade one its a lot of fun!
@SimplyBeautifulArt No I'm not really I'm looking for stuff to read...
Okay. I just found a nifty sorta explanation of how to handle ordinals that you might find nice
23:16
I'm interested please share :) by the way check this link for the cube : amazon.com/ThinkMax-Silver-Black-Mirror-3x3x3/dp/B004D0C5WY
just 6$
Let A={1,2} and B={3,4,5}. Then...

Addition:
A+B = {A+3, A+4, A+5}
B+A = {B+1, B+2}

Multiplication:
AB = {A3, A4, A5}
BA = {A, A2}

Exponentiation:
A^B = {A^3, A^4, A^5}
B^A = {B, B^2}
very worth it if you want to rack your brains!
yes indeed...
A5 means A+A+A+A+A
@SimplyBeautifulArt This is showing "successorship" in a nice compact way, would A^^B={A^^3, A^^4, A^^5} and B^^A={B^^1, B^^2} then?
@InfiniteMonkey No, ordinals do not mix well with higher arrow notations
23:31
So are we talking about ordinal arithmetic here?
@SimplyBeautifulArt im back!! sorrya about what happened a few days ago...
my internet shorted out completely
@InfiniteMonkey Yes
@AlexanderDay Hey!
21 mins ago, by Simply Beautiful Art
Let A={1,2} and B={3,4,5}. Then...

Addition:
A+B = {A+3, A+4, A+5}
B+A = {B+1, B+2}

Multiplication:
AB = {A3, A4, A5}
BA = {A, A2}

Exponentiation:
A^B = {A^3, A^4, A^5}
B^A = {B, B^2}
Aren't Knuth's up arrows or Conway chains also ordinal arithmetic? I'm a bit confused and not sure what to read to fill the gaps...
@InfiniteMonkey No, you get the Veblen function, remember?
Yeah epsilon zero I remember now!
e0
am i intrudung on your teaching of another person?
Nope
you're joining
@AlexanderDay Not at all!
@AlexanderDay So you saw how adding, multiplying, and exponentiation work?
and did you change the label of the SBA chat rm?
no.
23:40
Maybe I changed the change of the stuff
:)
it once said that u may learn about large numbers.
now it says open discussions
and i dont get why the stuff aforementioned is non-communitave
could you repeat it, or ill just read the transcript...
Let A={1,2} and B={3,4,5}. Then...

Addition:
A+B = {A+3, A+4, A+5}
B+A = {B+1, B+2}

Multiplication:
AB = {A3, A4, A5}
BA = {A, A2}

Exponentiation:
A^B = {A^3, A^4, A^5}
B^A = {B, B^2}
Basically, you expand the thing on the right
and it is for what?
23:44
ω = {1, 2, 3, ...}
vebelian function?
Not yet
ω3
= ω2+ω
= {ω2+1, ω2+2, ω2+3, ....}
Nice now I see!
then the 4w and 5w and then w^2
@AlexanderDay Was I showing you the fast growing hierarchy before?
23:45
oh wait...
Yes!
except probably want ω4 instead of 4ω
Let A = ω^ω
23:46
k
then...
hello?
A = ω^ω
= {ω, ω^2, ω^3, ...}

ω^ω^ω
= ω^A
= {ω^ω, ω^ω^2, ω^ω^3, ....}
Sorry, this stuff takes a while to write
@SimplyBeautifulArt That is a nice and simple way to get the point across you found there with A and B
k
so you are decompressing A??
Yeah, pretty much
@AlexanderDay did I show you the fast growing hierarchy?
You really got to get on that book writing there "Simply" are NONE on the subject!
And we see that ω^2 = ω*ω = {ω, ω2, ω3, ω4, ....}
is there anything beyond FGH???
yes...
There is always something beyond anything...
Yes, there are things beyond FGH
but its very big and we aren't there yet
23:50
YAY
BOO
So did I tell you about ε0?
Gotta go eat, brb
Bon appétit!
Did I tell you about ε1?
check
the epsilon...
23:53
Okay, so we have this
you explained everything up to what comes before the Veblan function
i think
oh, so I got to the weird t/z shaped stuff?
I'll just explain real quick again:
ε1 = {ε0, ε0^ε0, ε0^ε0^ε0, ...}
ε2 = {ε1, ε1^ε1, ε1^ε1^ε1, ...}
...
εω = {ε1, ε2, ε3, ...}
ε(ω+1) = {εω, εω^εω, εω^εω^εω, ...}
---
φ(1,x) = ε(x)
Veblen function time
YAY!!
i get dis
for now
23:56
On a side note, mirror cubes are solved with the same strategy as the 6 color 3x3 cube but it is way harder. If you really want to get crazy there are also "ghosts cubes"
φ(2,0) = {ε0, ε(ε0), ε(ε(ε0)), ...}
but not dat one!!
@InfiniteMonkey i can solve a mirror cube blindfolded...
@SimplyBeautifulArt k i get it
φ(2,1) = {ε(x), ε(ε(x)), ε(ε(ε(x))), ...} where x=φ(2,0)+1
φ(2,2) = {ε(y), ε(ε(y)), ε(ε(ε(y))), ...} where y=φ(2,1)+1
just add 1?
23:58
φ(2,ω) = {φ(2,1), φ(2,2), φ(2,3), ...}
oh wait...
Add one and then do lots of ε's
i get the 2nd line now
eh
???

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