In the book "The theory of Ordinary Differential Equations" I'm having trouble understanding $Lemma(1.6)$ which assets Lipchitz Continuity defined below, specifically the gap in my understanding is within the operation taken within $(2.)$,specifically speaking the specifics of my question can be ...
@SimplyBeautifulArt Please reread the comment of mine you responded to: "For example, in this chat room you needn't worry about informal...". So you are simply repeating my point, otherwise, why were you reponding to me?
@Zophikel Sometimes intuitive definitions are useful for assisting understanding. But one must always be able to provide precise definitions when requested. That is the peculiar but precious hallmark of mathematics. If we are unable to precisely define something, there could be many reasons. Perhaps we do not understand the fundamentals enough. Or perhaps we are looking for something vague. See this meta post for more explanation.
That doesn't mean we should stop asking. Rather it means we should just try to learn what is it that we are lacking in precision, and especially try to look from a stranger's point of view. The reason I say this is that sometimes being precise is actually the key to solving the problem; a lot of students cannot solve problems simply because they do not even know what precisely is being asked, and what precisely are the given assumptions and known facts.
Sometimes this means that instead of asking our original question we might want to ask about the fundamentals for that topic instead, because it might very well enable us to solve not just our original question but many others as well.
Well about Kolmogorov complexity, it's not that useless. It's true that it's uncomputable and all that, but did you know that you can use it to prove things like the incompleteness theorems?
the ZFC thing, the only people disliking it also did computer aided proofs for the existence of good. so my preconceptions regarding disliking ZFC are not on your side
because these are the only people, I've met, wo opposed ZFC. these people brought god into it. it does not have anything to do with ZFC itself. just said that, because I wanted to make my emotional standing clear.
@shredalert Yes we are. But there are practical issues here. We don't want to build a bridge whose stability is based on some theorem proven in a formal system that also proves 1=2...
@FabianGerhardt That's fine. But that's not the only people disliking ZFC. =)
@FabianGerhardt I'd be interested to see if you have some reference for that Godel believed formally proving existence of God is silly. The linked wikipedia article seems to suggest that he actually took it seriously.
Don't know whether you two have heard of the easily reproducible experiment that people always attempt to confirm what they believe instead of testing it, and hence get more and more convinced with zero evidence.
Like this: I'm thinking of a pattern for triples of numbers, and one of them is (2,4,6). You can ask any triple and I'll tell you whether it follows the pattern or not. When you think you got the pattern, you can say so and we'll see whether you're right.
Of course, I don't expect this to work on Math people. =)
But you may be surprised how many non-Math people fall for it. Try on your parents and see! =D
I don't know. I think I wouldn't need it at all, but then again, that's precisely the kind of mistake that I believe people who should take that course make when they don't want to take it.
@user21820 for normal continuity basically we have our function defined on an interval (a) we say that the function exists if: $\lim_{x \rightarrow a}(f(x)) \, = f(a)$
If this condition isn't satisfied then we say our function is discontinuous.
But @user21820 I feel like what I said wasn't detailed or precise :(
Personally, if you wrote all that in the right format, I'd be satisfied. I suppose sometimes, what we mean is we want you to use less words (which are vague/ill-defined) and... uh, more math
For all f(a) in A, then $\frac{\partial }{\partial a_i}= $\lim\limits_{h\to 0} \frac{a_1,....,a_{I-1} -f(a_i, ..., a_i ...., a_n)}{h}$ then our function is continuous at f(a).
^ @Simply I had written this one before-hand when revisting my question
@user21820 what's a good way to practice this: i'm thinking everytime I look a definition within a proof I write down what I had to look up and then practice the definition
A function f from R to R is said to be continuous at the point c in R iff f(x) -> f(c) as x -> c. The last part could be phrased as lim_{x->c} f(x) = f(c). In turn, you should know how to expand the definition of the limit.
@Zophikel I'm not sure what's a good way; you just need to attempt to write down the definition of every term you come across that you are not already absolutely certain of being able to write down.
Informally, we can say that for any positive error margin ε, there is a positive window of size δ around c such that if x is in that window then f(x) is close to f(c) within the error margin.
@Zophikel: First do what I originally asked for, namely expand the statement "lim_{x->c} f(x) = f(c)". It should be similar.
> A function f from R to R is said to be continuous at the point c in R iff f(x) -> f(c) as x -> c. The last part could be phrased as lim_{x->c} f(x) = f(c). In turn, you should know how to expand the definition of the limit.