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00:00
jesus, they seriously have no life
@qbert Rotterdam
@projectilemotion in uni?
Im always curious about people's ages and educational levels on this site
I'm a high-schooler (pre-uni) @qbert
00:21
that's very impressive simple art
Oh, ok, thank you :-)
@qbert Actually i'm not in uni yet, I self taught myself a lot of mathematics while i'm on my final year
I like ODE's and multivariable calculus
So, i'm in high school now and planning to double major in maths and physics
@projectilemotion :-P
Drama going down on multivariable limits
1
Q: Finding the values of n where the function is continuous at (0,0)

Jacob BoertjesI have to find the values of $n$ where this limit exists or doesn't exist. $$\lim_{(x,y)->(0,0)}\frac{|x||y|^n}{x^2 + y^2}$$ I have tried to use different paths like $y=mx$ or $y=mx^2$ and such but I don' t know what other strategies to try?

:D
00:38
@projectilemotion also great! I wish i had known about mathstackexchange back then
Lol, same
Well, good night all
01:24
And good morning @Ramanujan
@SimpleArt good morning :)
It is my night sadly
Have a good night :(
(´・_・`)
02:22
@Ramanujan oh, whoops, my bad
02:34
@Ramanujan You need to either give me your Discord username or you can add me as a friend
Simple_Art
#1200
 
5 hours later…
07:11
@SimpleArt what happened? Well... I guess I let myself get out of hand. I think the mods took my behavior as vandalism rather than as actual efforts to remove all the posts I was told were garbage. I probably shouldn't care. People are rude but sometimes I wonder if I'm too attached to my ideas.
after all the only way to truly tell if you care about something is if you destroy it and see if you have regret. Not remorse. That shows you're sympathetic towards others losses.
you know what I mean? You ever have that situation where you're like "I really like this but maybe I should just get of it anyway... just to invoke emotion. Shouldn't matter anyway. One should never be attached to anything."
@SimpleArt to sum it all up. What happened was an experiment in destroying those things that I care about and it was "successful" in that I feel no regret for once. I'm no longer wrapped up in all my weird diff. eq. Ideas I guess. No loss really. Absolutely nobody liked them anyways.
 
5 hours later…
11:57
@TheGreatDuck Lmao, ok then
 
3 hours later…
14:55
in Mathematics, 8 mins ago, by Simple Art
$$\int te^t\ dt=f'(1),\quad f(x)=\int e^{tx}dt$$
@SimpleArt Does not seemed like a particular rule, more like an expression of the symmetry for functions of the form $te^t$ under the functional $\int$
Suggest to see if you can find a similar symmetry for gamma functions
15:13
@Secret I know, but it seems like a broadly applicable method
@Secret by the way, welcome to my chat room full of random people
I am not sure how you initially get this result but I do get it after using integration by parts and noticing the pattern in the resulting terms
I usually post random problems that maybe fun to tackle if you are interested
@Secret hm? The point is that it is easy to evaluate one thing. Then differentiate any way you want. :-)
@SimpleArt hello
So you never went through some kind of substitution nor integraton by parts and you got this relation?
:-) hello
@Secret you need u substitution or something to get the first integral, but from there no integration by parts.
15:20
Initially I thought you are doing it by some kind of inverse chain rule $\int f'(x)g(f(x))dx=g(f(x))^2/2+C$, however $dt/dt=1$ thus the substitution is not a clear one to me
Well, can you take $\int e^{tx}\ dt$?
Once you do that, differentiate both sides and set $x=1$ :3
That substitution is ok, as it is just some function of x.
Hmm...
$$\frac{du}{dx}=\frac{d}{dx}\int e^{tx}dt=te^{tx}$$
Interesting, so you make a substitution that is an integral.
$\frac d{dx}\int e^{tx}\ dt=\int te^{tx}\ dt$?
Missing a few integral signs :-)
@Secret as you can see, I try to do math in weird ways.
From the working it is a type of substitution that is quite uncommon in typical problem solving because integrals are often perceived as harder than differentiation.

However when you elaborated as above, it seemed to be what is known as Feymann's integral trick, which is a special case of differentiation under the integral sign
(I tend to be warry before I differentiate under the integral sign, because your integrand need to be uniformly continuous before you can pull the derivative in)
:-P mhm...
15:28
don't worry, I also do maths in weird ways. We seemed to be focused on the symmetry of the problem when solving them and try to avoid many steps
DCT works too
Ah, nice
however you approach is quite opposite to how most people are taught to solve these things. For us, we tend to be taught to solve them via differentiation. Yours instead approach them via the integrals as a substitution
which is nice because this exploits the symmetry of some of these integrands, which most people tend to feel hard to solve
@Secret since you seem intelligent in analysis, would you like the first problem this chat room has to offer?
15:32
Nah, I actually suck at analysis. This is the well known illusion about me. I just happened to know just enough stuff in a random but broad mush and they all clicked together when I solve some problems
:-P it also lets me answer integrals that look unsolvable in ways not already posted.
Lol. Sound
Sounds like me
Be aware that feymann's trick is a special case of differentiation under integral sign, thus you must check whether you can actually interchange the two limits (one that forms the integral sign and the other forms the derivartive operator). The criteria for that is uniform continuity
XD I know mate. Treat differentiation like a limit, blah blah blah
Most functions tend to act nice in physics, which is why feymann's trick is quite common for gaussian integral evaluations
The criteria is dominated convergence. Uniform is a special case
15:35
ah yes
X.X kill me, Chinese class sucks sight now
Right*
you and another breifly stayed user known as @Idomathart (although she is actually still active in the main site) reminded me the importance of symmetry in integrands. It is only then I start to look at integrals as functionals since I can handle some mathematical objects better when presented abstractly without too much specific details
@Secret can you take this integral without IBP?$$\int x^2\sin(x)e^x\ dx$$
Cool :D
@Secret btw, I'm currently the top user as far as rep earned this year.
not suprising, just answering a weath of integral questions is enough for that cause they are so hard due to all that pattern matching needed to make nice substitutions
Yeah XD
@anderstood sup?
@Secret I'm taking my 'second' year if calculus, but I can answer complex analysis questions
:-)
15:51
my complex analysis is quite shaky, given in my undergrad I never have enough course slots to formally take it and I rely on my friends and lecture notes to learn most of the basis.
I also have a huge gap in topology because of that, which I planned to fill in this summer, because I need that to understand physics like GR, QFT, and also maths like real analysis, differential geometry

*meanwhile still solving that integral, and I presume your method does not involve converting sin x into the compelx exponential*
:P designed to make you think, and I'm a junior...in high school
$x^2 \sin x$ is obviously a function that has a nice odd symmetry thus some definite integrals will be quite easy due to symetry arguments. The trick is then how to incoporate $e^x$ into tha consideration. Exponentials are very nice functions because they are eigenfunctions of the integral and differential operator, and thus one can exploit them for some substitutions
:-) but I want indefinite integration
 
1 hour later…
17:00
Ok I am kinda stuck. While I uncover some kind of fourier transform like symmetry for this integrand, it does not help me in solving it
$$I(x)=\int x^2\sin(x)e^x dx$$
Let $u=\int e^{T(x)t}dx$. Then $\frac{du}{dt}=\frac{d}{dt}\int e^{T(x)t}dx=\int \frac{\partial}{\partial t}e^{T(x)t}dx=\int T'(x)e^{T(x)t}dx$

Set $t=1$ and equating integrands (forgot/don't know necessary condition that allow one to do so)

This gives (1)

$T'(x)e^{T(x)}=x^2\sin(x)e^x=I'(x)$

Integrate wrt x to get (2)

$\frac{e^{2T(x)}}{2}=I(x)+C_1$

$e^{2T(x)}=2I(x)+C_2$

$(1) \times (2)$ then integrate

$T'(x)e^{3T(x)}=2I(x)I'(x)+C_2I'(x)$

$\frac{1}{3}e^{3T(x)}=I(x)^2+C_2I(x)+C_3$
17:51
@Secret it helps if you start with $\int \sin(x)e^x\ dx$ and appropriately placing $x$... :P
 
1 hour later…
18:59
@RSerrao :D
19:17
@SimpleArt hey there ;) still finishing some studying
when I finish it, I'll get back to the summation :P
:D And nice answer btw ;)
:P Ok. Your gonna have a rough time probably XD
I am working on my CSP class :P
As in not really I'm kinda almost done already for half of next week
Thanks for the invitation :)
@TheGeekGreek Oh, hello and welcome to SimpleArt's room for random people
Usually there are random problems I run through that you can tackle at your leisure, and they usually do not require a lot of experience or anything like that. Meant to make you think very differently and possibly learn something
@TheGeekGreek So what kinds of math do you do?
19:44
@projectilemotion sup?
@SimpleArt Not too much going on for me, and you?
:-P Not much either, rather bored
Gotta catch the bus now :-/
Talk to you guys later! :D
Oh ok, see you later then
20:28
Sorry, was busy.
This sounds great!
At the moment I am studying for an abstract algebra I exam, so things like groups and rings. Simultaniously, I am doing topology and some measure theory.
 
1 hour later…
21:33
@TheGeekGreek hm, ok. I don't do any of those subjects sadly!
21:49
So what do you do'
?
 
1 hour later…
23:08
@TheGeekGreek I do analysis type things, some basic number theory, I know quite a few special functions, I do infinite series stuff, and I like to think outside the box

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