V'dibarta Bam

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1:09 AM

@AdamMosheh ask it! I'm sure everyone will think its a good question based on a foundation of good assumptions and you'll get lots of upvotes!

Shmuel Brin

@mochinrechavim Not everyone

Shmuel Brin

1:57 AM

Monica Cellio, Pittsburgh PA

6.5k 2 7 52

Isaac Moses

@mochinrechavim According to Quantcast's statistics (wherever they come from), we are less male-skewed than SO or TorahMusings, for example

Moshe

3:03 AM

gizmodo.com/5911984/…

betabeat.com/2012/05/21/…

scribd.com/rlitzlon/d/…

Asifa articles.

1 hour later…

ه ه

4:26 AM

This site has helped me a lot in the past, perhaps someone can help me now: can someone explain how to use the substitution rule to find an indefinite integral when theres no perfect g'(x) in the function (on one foot please)?

I think the point is to do something to both sides of the integral so that whatever is tainting the g'(x) "cancels out" and ur left with a perfect g'(x). Can anyone confirm or let me know if i have it all wrong?

2 hours later…

Double AA

6:23 AM

@هه @Vram math.stackexchange.com/questions/ask

@هه @Vram Do you mean something like Int(cos2x * sin2x dx)? To solve that you put 2 in the integral and 1/2 outside it like: 0.5*Int(2cos2x * sin2x dx). Then with u=sin2x & du=2cos2x dx you can substitue to make 0.5*Int(u du) = (u^2)/4 = sin^2(2x)/4

The key is you're multiplying by 2/2=1 so it doesn't change, but you can bring constants into and out of an integral, so you only bring in the numerator (or in other cases, the denominator) as neccasary.

9 hours ago, by Double AA

http://judaism.stackexchange.com/q/16536/759 is too broad. Every possible case needs to be dealt with individually, as evidenced already in the comments.

6 hours later…

Double AA

12:31 PM

@IsaacMoses Good morning! What do you think ^^^?

Isaac Moses

@DoubleAA Good morning. Gotta run. I think that from the Q's POV, it's one question, so it should stay that way, but I could be wrong

ه ه

@DoubleAA I understand that it's a problem by problem method that's not really one size fits all; I'm mostly fishing for a kelal. In any event, test is in 40 min so I guess all I can do now is pray

@DoubleAA thank you for your assistance.

ه ه

1:01 PM

m.wolframalpha.com/input/?i=int%28sin2x*cos2x%29&x=0&y=0&assumption=*C.in‌t-_*IntegralsWord-

1 hour later…

msh210

2:29 PM

Q: Final Vote to name Mi Yodeya's chat room - Closes May 22 23:59 UTC

We've had a number of good suggestions for our chat room's name, and the upvotes and downvotes on each showed that there are five favorites (answers with net vote count greater than one standard deviation above the mean as of this writing, if you care). Here, you're being asked to vote among thos...

discussion featured chat site-name

@هه Hatzlacha! (I can still tell you that as long as the exam isn't graded, right?)

1 hour later…

ه ه

3:44 PM

@msh210 judaism.stackexchange.com/q/15875/1172

Stack Exchange

Blog - Stack Exchange: Encyclopedia Stack Exchange

Joel Spolsky on May 21, 2012

Remember this old picture?

What’s that “Blog” circle supposed to be about, you ask? WHERE’S THE BLOGGING?

Since Stack Overflow launched, we’ve been trying to explain that it’s not just a Q&A platform: it’s also a place where you can publish things that you’ve learned: recipes, FAQs, HOWTOs, walkthroughs, and even bits of product documentation, as long you format it as a question and answer.

As Jeff wrote:

if you have a question that you already know the answer to …

ه ه

4:43 PM

@DoubleAA wolframalpha.com/input/?i=int%28sqrt%284-x%5E2%29%29&a=*C.int-_*IntegralsWord-

@DoubleAA this was his substitution question- where did sin come from??

msh210

5:11 PM

@هه It's a trick. Basically, it works, and there's no easier way to do it.

@هه Why did you point that out to me?

@هه Note that sqrt(4-x^2), if you substitute x=2sin t, becomes sqrt(4-4sin^2 t)=sqrt(4(1-sin^2 t))=sqrt(4cos^2 t)=abs(2cos t).

Shmuel Brin

5:26 PM

@msh210 closing time in 7 hours

msh210

@ShmuelBrin Ah.

Double AA

@ShmuelBrin @msh210 I think he was saying that you can always say hatzlacha until after the grading.

msh210

@DoubleAA Ah. Yes, that's probably it. @هه, if you click the arrow that appear at the bottom-right of a chat message when you hover over the latter, then your message will be listed as a reply to that message and you'll reduce ambiguity.

Shmuel Brin

@DoubleAA Oops, followed wrong link :(

1 hour later…

msh210

6:56 PM

@ElendiaStarman, welcome :-)

El'endia Starman

@msh210 Thanks. :)

msh210

@IsaacMoses We also trail SO in our respective percentages of visitors that have kids in their households. (Possibly within the margin of error, though.) (Both those and the sex numbers are for visitors, though, not contributors.)

El'endia Starman

7:58 PM

I may not be Jewish, but that doesn't stop me from drawing an impossible Star of David. ^_^

msh210

@ElendiaStarman Neat. :-)

@ElendiaStarman Probably harder to draw an impossible (Latin) cross.

El'endia Starman

@msh210 Indeed! You'd have to twist it. Here, since the Star of David is triangles, I can...uh, well, "snap" the ends together and it's impossible! :P

1 hour later…

Double AA

9:38 PM

Why is everyone calling it the Asifah and not the Aseifah (with the long tzeirei)? Is that a yiddish-ism of which I am unaware?

msh210

@DoubleAA The word in Hebrew is אֲסִיפָה, innit?

(Like sh'mira, asiya, etc.)

Double AA

@msh210 I have always heard it pronounced אֲסֵיפָה = a meeting.

msh210

@DoubleAA I don't know why it would be.

Double AA