 8:21 AM
This question gained some attention after (probably) getting into hot questions list and also being mentioned on meta.
-10  How can you simplify $\cos^6x+\sin^6x$ to $1−3\sin^2x\cos^2x$

I wonder whether this has been asked in the past.
I have tried a few queries.
Searching for $\cos^6x+\sin^6x$ (IIRC this is the same as the previous search)
The questions about $\sin^6x+\cos^6x$ which I found were the following:
6  I have $\sin 2x=\frac 23$ , and I'm supposed to express $\sin^6 x+\cos^6 x$ as $\frac ab$ where $a, b$ are co-prime positive integers. This is what I did: First, notice that $(\sin x +\cos x)^2=\sin^2 x+\cos^2 x+\sin 2x=1+ \frac 23=\frac53$ . Now, from what was given we have $\sin x=\frac{1}{... 2  In this question, the only proof of the trigonometric identity: $$\cos^6{\theta}+\sin^6{\theta}=\frac{1}{8}(5+3\cos{4\theta})$$ is via factoring the sum of cubes: $$\cos^6{\theta}+\sin^6{\theta}=(\cos^2{\theta}+\sin^2{\theta})(\cos^4{\theta}-\cos^2{\theta}\sin^2{\theta}+\sin^4{\theta})$$ Is th... Neither of them can be considered duplicate of the above. 1 hour later… 9:30 AM Does Approch0 distinguish between \frac and \dfrac? I suppose it does not (which is good). At least when I try to search for$\frac{\cos x}{\sin x}$and to search for$\dfrac{\cos x}{\sin x}$, the first page of results is the same. 4 hours later… 1:09 PM @MartinSleziak For frac and dfrac, no, Approach0 does not distinguish between them. @MartinSleziak Yes, you do not need to try different sequence for commutative expressions. The same for expressions on two sides of equal sign, Approach0 know they are commutative too. So what is your question? You mean you cannot find the second post by using all the listed queries you have tried? @WeiZhong What you mean by second post? BTW. How do you refer to a post and show its snippet like above?  Because I want to show you which post I refer to Yes, by second post I that post (ID 1324028). 1:24 PM @WeiZhong I found that post through above queries, too. @WeiZhong It is called oneboxing. See also chat faq. If you post only link to a SE post in your message, it is displayed like that. @MartinSleziak OK, so you are just sharing your experience on searching that hot question? @WeiZhong Do you mean why I posted the above question and search queries here? Well I was searching for other questions about$\cos^6x+\sin^6x=1−3\sin^2x\cos^2x\$ (if they exists).
After all, purpose of this room is to help people who are looking for some question(s).
And, as and aside, since Approach0 is new, this room is also used for testing it. @MartinSleziak Thanks for letting me know, but I writes the link of a post too: chat.stackexchange.com/transcript/message/33602655#33602655
no snippet is shown. @WeiZhong But your message was longer, not only link to the question.
Oct 1 at 8:30, by Martin Sleziak
Searching for questions is not easy. So this room was created for such situations - you can ask here for advice, maybe some other user will have better luck when searching the question.
Oct 1 at 8:31, by Martin Sleziak
However, the main reason that I started this room now is that recently there seem to be interest in this new search engine:
So this rooms is for both purposes: 1) searching in general; 2) testing Approach0 (and other search engines). I understand, I just want to make sure you are not reporting any problem of Approach0 :P 1:31 PM
No. This time are genuinely asking for help. Of course, it is possible that there is no duplicate and this trigonometric equality was posted on this site for the first time in the above question. Sorry about my misunderstanding. I thought you were asking why you were not getting that two posts by entering the queries you had listed. No. I was searching for a duplicate. And I have listed the question which I found so far. I got you.
I searched this query: approach0.xyz/search/…