Yeah, user21820 has some possible counters on that, he then showed me a MO question (which I can link here if you want), but most importantly, that caused me to recently spent some time meddling with Lebesgue measure, and thus showing the countable set result
1. A function is Riemann integrable if and only if it has at most countably many discontinuties
->That might be sidestepable by using other notion of integration by changing the measure, or redefine continuity on the new topology of the n-computable reals