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Partial answer:
Note that:
$\log(a)+\log(aq)+\log(aq^2)=\log(a\cdot aq\cdot aq^2)=\log(a^3q^3)=\log(aq)^3=3\log(aq)$
Therefore:
$\log(a)+\log(aq)+\log(aq^2)=3\implies3\log(aq)=3\implies\log(aq)=1\implies aq=10$
Therefore:
$a+aq+aq^2=62 \implies a+10+10q=62 \implies a=52-10q$
So now we have...