Music Lover/Teacher grew up in a society that told her simultaneously that she could be president and that a woman's job is in the home.
Music Lover/Teacher has a golden ear surpassed by the warmest honey voice, when things look like they'll work out, and the sharpest mind that taught me to leave stepping stones more than imperatives.
You should see Music Lover/Teacher try to write a short message.
Like Mark Twain, given two weeks they can make it short, sweet and concentrated.
The only reason that famous people ask my help with typesetting is so they can claim the Good Housekeeping Seal of Approval: "Never touched by hman hands."
When you "hm" @m_____t, i'll give you all the slack it takes to find out what's at the other end of that rope. (You don't have to rope it every time, either, i for one bat for average, and 1/3 is better than average.)
> Lynn October 27, 2019, established by the Christian Federation a breakthrough for a grandmother in the kitchen in the north of France for the month to 24.
Music Lover/Teacher called about many other issues that got through the wringer, after which i complimented with this Yes piece is where Mom and i saw eye to eye.
Mom bought me the album, sight unheard, as if anything by Yes would demonstrate her love.
I said, "I've always loved you." And she gasped "I know."
@manshu was @m____ before scientists could do anything about it.
Weirdly fun on sidewalks last night: Dude gave me the pitch and i replied "you're half a century too late"
A few blocks (and more hours) later i plunked down next to a sufferer and begged her to let me hold her injured hand.
She gave me a blanket!
Went back just now to express my gratitude and, real in the making. everyone else said she wasn't hee last night and that she' is he. I hate English almost as much as love it.
\begin{description}
\item[given]solution in interval notation: $-1\cup2\cup\left[3,\ \infty\right)$
\item[find/create]polynomial with that solution
\end{description}
it's actually quite simple. reverse the sign of $-1$ and $2$ and put them in an $\left(x+\ \right)^2$. do the same for the $\left[3,\ \infty\right)$ but don't square it. multiply them together, add $\geq$*, \textsl{et voil\`a}!
$$\left(x+1\right)^2\left(x-2\right)^2\left(x+3\right)\geq0$$
\footnotesize{*because of the $\left[\right.$ and the $\infty$}
