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07:42
It seems that was created, removed and created again on this questions: math.stackexchange.com/posts/4761137/revisions
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Q: Are the integral and differential definitions of Ito process equivalent?

étale-cohomologyI think an ito process $X_t$ can be defined as $$X_t := X_0 + \int_0^t\sigma_s dB_s + \int_0^t\mu_s ds.$$ (Is this an Ito drift-difussion process?) (Why use the subscript $s$? Eg. why is it $\sigma_s$ and not just $\sigma$?) And I've also seen: $$dX_t := \sigma_t dB_t + \mu_t dt$$ Are the 2 defin...

Questions where the tag was added/removed (including the editors): data.stackexchange.com/math/query/1105163/… data.stackexchange.com/math/query/1038474/…
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5 hours later…
12:31
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Q: Stochastic multiple Ito integrals in higher order Milstein schemes (>1)

apelleIn the series expansion to obtain the form of higher order Milstein schemes you need to evaluate these two sister integrals (where W_t is the Wiener process): $$ \int_{t_i}^{t_{i+1}}dW_u\int_{t_i}^{u}ds\\ \int_{t_i}^{t_{i+1}}du\int_{t_i}^{u}dW_s, $$ after I evaluate the innermost integral I obtai...

 
3 hours later…
15:55
A new tag . This tag was created and removed a few times before - most recently a few days ago.
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Q: What does it mean that we have a topology greater than another topology?

Luthier415HzIn this article I read that two topologies can be compared. Suppose that $f : X \longrightarrow X $ be the identity map, $f (x) = x$ for any $x$. Consider on $X$ two topologies $\tau_1 , \tau_2 $. Suppose that $\tau_1 < \tau_2$ . Is $f : (X, \tau_1 ) \longrightarrow (X, \tau_2 ) $ always contin...

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Q: What does it mean that we have a topology greater than another topology?

Luthier415HzIn this article I read that two topologies can be compared. Suppose that $f : X \longrightarrow X $ be the identity map, $f (x) = x$ for any $x$. Consider on $X$ two topologies $\tau_1 , \tau_2 $. Suppose that $\tau_1 < \tau_2$ . Is $f : (X, \tau_1 ) \longrightarrow (X, \tau_2 ) $ always contin...

 
8 hours later…
23:30
@MartinSleziak Thanks.
@MartinSleziak I've removed this tag. It doesn't seem particularly useful, and it didn't go through channels.

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