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03:18
@MartinSleziak I'm sympathetic, and since the post in Meta has gotten five upvotes (none are mine) and no downvotes, I'll create the tag and add information suggested by the user gciriani. I'll notify them by posting a Comment on the Answer.
 
1 hour later…
04:35
The tag fractional-differential-equations has been created, using your suggested text for the tag excerpt. I also wrote up a tag wikia with some links to definitions, etc. It seems to me that the new tag should not exclude tags for ordinary differential equations or partial differential equations, since fractional derivatives may arise in either univariate or multivariate contexts (and my wikia text reflects that). — hardmath 50 mins ago
As mentioned above, the tag was created. It has a tag-excerpt and a tag-wiki.
1
Q: Fractional Bernoulli equation and logistic function

gcirianiI'm investigating the solution of the special case of the Bernoulli differential equation $$ \dfrac{dy}{dt} = \dfrac{y(1-y)}{\tau}, \tag{1} $$ with $\tau$ a time constant, and which models innovation processes fairly well, and whose solution is the logistic curve $$ y = \dfrac{1}{1+e^{-t/\tau}}.\...

 
3 hours later…
07:09
1
Q: Curious for other elegant methods for solving $x+\sqrt{x+\frac12+\sqrt{x+\frac14}}=4$

MathStackexchangeIsNotSoBad Solve the equation $$x+\sqrt{x+\frac12+\sqrt{x+\frac14}}=4$$ Actually I have solved this question but I want to know other methods of solving this question. It's not that I am curious for just elementary methods but you all can give solutions using advance maths too (which I'll see and learn). ...

 
2 hours later…
09:21
@MartinSleziak I have replaced [more-solutions] by [alternative-proof]. – Not sure if [solving-equations] is really needed, or if there is a better choice.
09:35
1
Q: Curious for other elegant methods for solving $x+\sqrt{x+\frac12+\sqrt{x+\frac14}}=4$

MathStackexchangeIsNotSoBad Solve the equation $$x+\sqrt{x+\frac12+\sqrt{x+\frac14}}=4$$ Actually I have solved this question but I want to know other methods of solving this question. It's not that I am curious for just elementary methods but you all can give solutions using advance maths too (which I'll see and learn). ...

@MartinR I would consider tags such as and as suitable options for that question.
Unrelated to this particular question, maybe it could be useful to discuss at some point, whether it would be better to have a tag called - which would include the questions asking for an . With a synonym between them - similarly as and .
-6
Q: Creation of the tag : alternate-solution

sai-kartikI propose to create this tag : alternate-solution for my most recent question. This tag is to be used when the user is asking different approaches for the same question. Is there such a tag existing already? If not, can I proceed to create this?

5
A: Creation of the tag : alternate-solution

quidI am against the creation of such a tag. It would be a "meta tag" and for the most part we try to avoid those. The information that you are searching for an alternative solution should be conveyed in the body of the post.

10:10
@MartinSleziak Probably. But I am always unsure about the various “calculus” tags ([calculus], [algebra-precalcus], [real-analysis], ...) therefore I do not feel confident enough to make that change.
I have included the tag . (And removed the newly created tag.)
1
Q: Curious for other elegant methods for solving $x+\sqrt{x+\frac12+\sqrt{x+\frac14}}=4$

MathStackexchangeIsNotSoBad Solve the equation $$x+\sqrt{x+\frac12+\sqrt{x+\frac14}}=4$$ Actually I have solved this question but I want to know other methods of solving this question. It's not that I am curious for just elementary methods but you all can give solutions using advance maths too (which I'll see and learn). ...

All five spots are taken - so there's no place for . (Although I am not sure whether , and are really needed there.) Maybe somebody else will improve the choice of tags a bit further.
 
10 hours later…
19:55
1
Q: Characterization of equivalence of multicategories

Elías Guisado VillalgordoConsider the well-known categorical result: Theorem 1.5.9 (of Riehl's book). A functor defining an equivalence of categories is full, faithful, and essentially surjective on objects. Assuming the axiom of choice, any functor with these properties defines an equivalence of categories. I was wond...


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