0
$w_1=4.5$kN
$w_2=0.9$kN
$F=2.7$ kN
Using the equation for a triangular distributed load we get
$F_R= .5(3)(w_1-w_2)+ F$
$F_R = 8.1$kN
But another student said that $.5(3)(w_1+w_2)$ works as well.
I have tried solving for $F_R$ both ways and keep getting $10.8$ kN or $8.10$ kN, but both answers ar...