@BabakS. Really? Oh...I see what you mean..."user was removed"... The answer remains, usually, but you lose any points you got as upvotes from the user
@GustavoBandeira To discuss music taste continues to remain interesting. Where you describe something as "Amazing.", I would describe it as "Boring." :)
@GustavoBandeira Nice! There's something intangible about piano pieces. The only thing getting close to it is the violin IMO. Most other instruments are quite boring compared to these.
Take, $aha^{-1}$ then let $a = (34)$. Then $aha^{-1} = (34)h(43)$. If I plug in (3) I get $(34)h4$ and if h and (4) are disjoint so they dont commute and its not in $H$
Ok i have the (ultra) metric $$d_{37}: \mathbb{Z} \times \mathbb{Z} \to \mathbb{R}: d(x,y)=\begin{cases} 2^{-a_{x,y}}; & x \neq y \\ 0 & ; x=y \end{cases} $$ where $a_{x,y}$ is the highest exponential of $37$ in the prime factorization of $|x-y|$
no I shall find an ultra metric $d'_{37}:\mathbb{Q} \times \mathbb{Q}\to \mathbb{R}$ such that it conicides with $d_{37}$ on $\mathbb{Z}\times \mathbb{Z}$
@shobon But i just thought of this, and I am quite should that I this was not explicitly written down in my book anywhere. I was wondering if there is some very obvious reason.
@DominicMichaelis Then you could IMO suffice with describing an algorithm rather than giving the list. That'd be the only worthwhile part of the exercise in any case; nobody cares about such lists.
@Charlie As is explained on my profile, I am affiliated with ProofWiki. Indeed, I am also the person behind the identically named profile on that site.
Shot through the heart and you're to blame You give love a bad name I play my part and you play your game You give love a bad name You give love a bad name
