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user19161
11:13 AM
@robjohn You're up early.
 
user19161
@κρανίοπεριπολία What does that smiley mean?
 
That's my impersonation of the "mean square."
 
huhu you all
 
11:23 AM
Hey, how to calculate in excel a number, that I can substract 5% and
 
get specific number
 
@JasperLoy I am?
 
like, I need to get 250, and I have found that 263,16-(263,16*0,05) = 250,002
 
We are going to see a lot of new users around here soon:
 
11:27 AM
how to "reverse" this expression?
 
Why exactly are there so many "First Posts" right now? I've never seen more than 3, and now there are 88. - 7h ago by Andrew Salmon ▼
 
user19161
@DominicMichaelis That guy just edited his question.
 
how i love that
i will prove that when f is convex a local minimum implies a global minimum
 
user19161
@DominicMichaelis Haha, just see my elementary proof!
 
@jasper yeah but i don'T want to copy you ;)
so i make it as complicated as possible
 
user19161
11:32 AM
@DominicMichaelis Yeah, it's good to see different solutions, though in this case, I doubt the asker will understand, but it's still instructive for other readers.
 
i am eating right now, it will take some time ^^
 
user19161
@DominicMichaelis Only 3 votes for my answer, I thought it would have 9000 by now!
 
yeah i love how easy you made it, bad luck you was faster as i ^^
 
user19161
I hope it gets 9000 later!
 
user19161
I only know easy proofs, I am only a banana.
 
11:37 AM
the most votes on an answer I saw was over 3000
 
How to find a number, that substracted by 5%, equals given number?
 
@deele 0.95 x= given number
 
@DominicMichaelis No, that is not solution. For example, given number is 2500, and solution (according to goal seeker in excel) is 2631,578..., and if I substract 5% from 2631,578 I get 2500
@DominicMichaelis but if I reverse that, it is solution, 2500 / 0,95 = 2631,578...
 
wait wait wait i always see the same number
the problem is that $(0.95 * x)*(1.05)\neq x
 
user19161
11:52 AM
I just answered a beautiful question!
 
by a beautiful mind
 
what beautiful question?
 
user19161
3
Q: Finding the triples

user69872If $x,y,z$ are integers satisfy $xyz+4(x+y+z)=2(xy+yz+zx)+7$ .How to find the triples$(x,y,z)$ that satisfy the equation

 
@jasper i updated mine answer
 
I see.
It is indeed beautiful!
 
11:57 AM
gee that got a long answer, i hope someone will read it although it is so long
 
BTW, in English it is a "convex" function, not "konvex".
 
oh crap
 
minor point. :D
 
most times i called it convex ^^
 
user19161
It shows he is German. =)))
 
12:04 PM
:)
 
I guess i should at a picture to the definition of convexity
 
user19161
I thought the beautiful question will have 9000 votes by now...
 
It resembles a result in calculus of variations, stating that, if F is convex, and if u^k minimizes an integral function related to F, then u^k minimizes that functional in the whole Lipschitz space!
 
user19161
Dinner time...
 
Bye! Blue banana
 
12:07 PM
bye
mh maybe it would be better if i only prove the simple case where $f$ is 2 times differentiable
 
But the most interesting, or troublesome, case is when there is no such condition!
:D
 
yeah i just use the convexity without being differentiable a single time
 
Good!
Hm... Yesterday I sleeped only 5 hours, so I think I am going to take a rest now!
later everyone!
 
well i used when f is 2 times differentialbe and f'' > 0 that f is convex, as I didn't want to write down the proof for the convexity
seee you later
 
:-D
 
user19161
12:46 PM
@awllower The past tense of sleep is slept.
 
user19161
1:12 PM
Guys, I just posted my 400th answer, yay!!!
 
That's awesome!
 
@JasperLoy cool.
I just noticed I have exactly 100 answers
 
I have 116. Now I have to answer 34 more so it's a nice multiple of 50. :\
 
Hey guys, can you give me some help?

I'm solving some exercises for school about complex numbers and it asks this:

If f(z) = z2 - z + 1, then f(1 - i) is equal to:
a) i

b) -i + 1

c) i - 1

d) i + 1

e) -i

My answer:
f(1 - i) = ( 1 - i ) * 2 - ( 1 - i ) + 1
f(1 - i) = 2 - 2i - 1 + i +1
f(1 - i) = 2 - i

Of course this answer is not an option, but it's written below the question that the answer is the letter C, how can that be possible? What I did wrong?.
 
1:28 PM
@Zignd is the z2 a $z^2$?
 
no it's z * 2
 
what an odd way of writing it then
 
do you think my answer is correct?
 
Well, then f(z)=z+1
 
also, if it was a square then that would explain why you get a result that is not an option
since you calculation is correct
 
1:30 PM
If it is z^2, I get -i
 
@user67848 Well I saw an commentary below this question that says that "the answer for this question is the letter E (-i) instead of C" I think it was incorrectly written (the question).
 
@Zignd Did the worksheet have f(z)=z2-z+1, with the 2 after the z? In this case, I think they just messed up the exponent.
 
@user67848 Yeah you're probably right. Thanks for helping guys. Cya.
 
@Zignd Btw, an easy way to get -i is to manipulate the expression z^2-z+1=z^2-2z+1+z=(z-1)^2+z.
 
user19161
40 more to cap today.
 
1:45 PM
I think I have only capped once
 
2:28 PM
So jealous of how good people on here are!
 
2:39 PM
hi guys
 
hhh
3:04 PM
Simple q about matlab, how to read the output?

solve(x==y+1, y^2==z,z==9)

ans =

x: [2x1 sym]
y: [2x1 sym]
z: [2x1 sym]
 
@κρανίοπεριπολία Hi!
@karl's hii!
 
@Charlie hi honey!
 
@Karl'sstudents how are you sweetheart?
 
@Charlie I am fine, and I miss Jasper Loy!
 
@Karl'sstudents I saw him yesterday
 
3:18 PM
@Charlie I am solving a mathematics problem now...
 
@Karl'sstudents ah, wonderful!
@Jasper Hi, Jaspy, we miss you :)
 
@Charlie I am hibernating...
 
@Karl'sstudents Oh!
 
3:31 PM
There is an interview in LaTeX site. The interviewee is a TeX expert from China. chat.stackexchange.com/rooms/1728/textalk-interviews
 
3:45 PM
:)
 
morning
 
4:01 PM
@Arkamis Hi Ed!
 
@Charlie How goes it?
 
everything fine, and you?
 
sore
Played my last hockey game of the season last night
 
Oh noes! Did you win?
 
Nope, lost 2-1, was a good game
 
4:05 PM
huhu
 
@DominicMichaelis hi Dommy
@Arkamis hahaha
 
Sore though, I got knocked on my ass pretty hard, feet kicked out from under me, landed right on my tailbone.
 
Ouch!!!
A game where no one gets hurt, is not a good game
 
there is no laurent series tag?
 
@charlie This is true.
 
4:18 PM
shall i make one ?
 
@DominicMichaelis Check meta first, see if there's been any discussion. Otherwise, go ahead. Seems like a reasonable tag.
 
search for laurent gives 0 results
 
fire away
 
Bang bang
 
is there in the tag body no mathe allowed?
 
4:25 PM
@DominicMichaelis Correct
from what I remember
 
explain a laurent series without using integrals formula, thats a hard one for tabu ...
 
Nice I changed my gravatar :)
 
i will search for some questions which should have that tag
you have the word wunderbar ? :D
 
4:43 PM
No hahaha
 
@DominicMichaelis is it like awesomebar?
 
i guess it is pretty much the same as awesome
 
Wunderkind
 
4:56 PM
gee there are a lot of questions about laurent series
 
@DominicMichaelis Don't go too edit-happy
People will not want to see a flood of older Laurent Series questions on the front page ;)
 
oh so i will make it from time to time
 
@κρανίοπεριπολία hi Skull!!!
 
@Charlie Chucky? Is that you?
 
@κρανίοπεριπολία yipyipyip
 
:)
@κρανίοπεριπολία how are you ?
 
@Charlie Fine thanks. How are you?
 
@κρανίοπεριπολία I'm good, Skull
 
@Charlie Rating please.
 
@κρανίοπεριπολία 7.83
 
5:13 PM
@Charlie Fair enough.
 
@κρανίοπεριπολία really?
 
@Charlie yipyipyip
 
@κρανίοπεριπολία :D
 
@Charlie Not everything the Jacksons do is a 9.
IMO
 
@κρανίοπεριπολία agreed
 
5:19 PM
@Charlie Nice gravatar Chucky!
 
@κρανίοπεριπολία Thanks, you liked?
 
@Charlie Oh yeah...eyes without a face...black cat
Very nice.
 
@κρανίοπεριπολία :D
@κρανίοπεριπολία ;)
 
@κρανίοπεριπολία O:-)
 
:*
 
@κρανίοπεριπολία what did you remove?
 
Aah
 
5:34 PM
@Charlie Is that OK?
 
@κρανίοπεριπολία yipyipyip
 
:)
 
Our gravatars^^ contrast each other nicely :)
 
Like black and silver:)
 
5:41 PM
$\Huge\text{Bleed the Silver & Black}$
Silver & Black Is What I Bleed
 
@κρανίοπεριπολία a lot of f***, no?
 
@Charlie Yeah, too much.
 
:-/
 
Hi! Does anyone know PavelM ? He used to be on math.SE (at least until January)...
 
5:57 PM
@anon Sup, nerdizzle?
 
yo, P-drizzle
 
shizzle shizzle
 
@anon The commutator subgroup is the smallest normal subgroup of $G$ such that $G/N$ is abelian! =)
 
reading alex I see
 
I wonder who found this to be a good question math.stackexchange.com/questions/344917/…
 
6:10 PM
ouch
 
@anon Ah?
 
Does anybody experience this drop down message in chat?

There seems to be a problem connecting to the server.
Please check your internet connection and reload this page.
 
@WhitAngl PavelM left
He changed his user name to 5pm at some point; there is a meta thread on his departure.
 
@κρανίοπεριπολία That happens to me when I close the browser on my phone and reopen it, say.
 
@Arkamis: thanks! Do you know his real name by any chance ?
 
@WhitAngl cannot say I do
But others around do
 
6:37 PM
ok ; I'd like to acknowledge him in a paper, and referring to a pseudonym that doesn't even exist anymore doesn't do him justice ;)
 
24
Q: What happened to 5PM?

maximumtagHey I am wondering where 5PM is? I enjoyed reading his posts on partial differential equations and am just curious. The account seems to be deleted.

 
yep I just saw. I'm reading the thread. I didn't know PavelM=5pm
thanks!
 
7:00 PM
@AlexanderGruber Yello.
 
@PeterTamaroff hi
 
@AlexanderGruber I'm showing any finite domain is a division ring.
I'm thinking as follows:
 
Take $R=\{r_0,r_1,r_2,\dots,r_m\}$ where $r_0=0\neq 1 =r_1$.
Choose a $r_j\neq 1,0$ and make $r_jR=\{r_0,r_j,\dots,r_\ell\}$
Since $r_j\neq 0,1$, there must exist an $r_i$ in $r_jR$ with $r_i=1$ (since $r_jR=R$) so $1=r_jr_i$ for some $i$.
Then repeat till exhaustion of elements of $R$.
Obviosuly this is just a sketch. And I need to look at right products too, not left only.
 
@PeterTamaroff note that the inverse of some non-zero element will actually be a power of that element
 
7:09 PM
where do you use the domain property?
 
the domain property is needed to know that multiplication-by-r_j is injective (and hence 1 has a preimage under it, r_i)
showing finite division rings are necessarily commutative is much harder
 
yes, that works then
pigeonhole principle stuff
haha, wonder who nuked our answers @anon?
 
it's the same reason it is enough to check closed under composition to check whether something is a subgroup of a finite group (inverses then being automatic)
 
@AlexanderGruber @anon was downvoted!
 
we both were
 
7:20 PM
sounds like someone has some fetishes about his reputation points
 
@anon True. Was it caveman?
 
fetishes plural?
I don't care to jump to conclusions, nor do I care who it is.
 
yeah, can be more than one... who knows
 
7:22 PM
just got 20+ historical french math books for free today.. from Weil, Banach, Bourbaki, Serre, Dieudonné, Fréchet... :) :) cool!
 
nice
 
That is cool.
Especially Bourbaki.
 
@κρανίοπεριπολία my thoughts exactly
 
"Algèbre" and "Intégration" :)
 
@WhitAngl Dieudonne ?? mdr
 
7:29 PM
@WhitAngl Damn! Lucky!
 
@WhitAngl je faisais reference a l'humoriste polémique bien entendu
 
Cartan-Dieudonné theorem... ;)
I like book give-aways at Harvard :p
 
do you live in the harvard area?
 
yep
 
@WhitAngl where did you get them exactly from ?
 
7:33 PM
@WhitAngl Your libraries are the largest in the world.
 
@Carpediem 33 oxford street, in the SEAS department. But it was only until 2pm. I don't know whether they plan to renew the event
(in Maxwell Dworkin)
 
0
Q: Derivatives of functions defined implicitly

CarpediemLet $F$ be a real-valued function of two real variables and assume that the partial derivatives $D_1 F$ and $D_2 F$ are never zero. Let u be another real-valued function of two real variables such that the partial derivatives $\partial u/ \partial x$ and $\partial u/ \partial y$ are related by th...

 
user19161
Why did I get a few votes from the -1 times -1 question today? It was not bumped.
 
no idea
 
user19161
Hmm, maybe something new was linked to it then...
 
user19161
7:38 PM
Ah, I have 100 votes for that answer, so a Great Answer Badge.
 
congratulation
and i need 41 reputation to cap today ^^
 
user19161
Also, I have capped for the day, thank you for your support, ladies and gentlemen.
 
Can someone help me with the above problem ?
 
@TobiasKildetoft Oh, I think that is tidier. I just multiply an element by itself till I get $1$.
 
i don't have a great answer badge :(
 
user19161
7:43 PM
@AlexanderGruber That is because you are already great!
 
user19161
Only bananas like me need badges.
 
i suppose that's true
 
user19161
You people will win Fields medals in future.
 
that's a lot like a great answer badge
 
user19161
Nah, the badges mean nothing.
 
user19161
7:45 PM
Only love is real.
 
@PeterTamaroff right, you just need to argue why you get 1 at some point
 
@TobiasKildetoft Sure. Though my idea also works.
 
user19161
I am trying to figure out which post was linked to the -1 times -1 question, hmm...
 
user19161
@amwhy With 40k, you can now retire!
 
@JasperLoy One point shy 39999...and capped in terms of up-votes for the day :-)
So I'll either hope for an "accept" before the day ends, or wait it out for the new day ;-)
 
user19161
7:49 PM
Everyone, happy Good Friday.
 
user19161
I am not Christian, but Jesus was still a great man, no less.
 
@anon Suppose that $R$ is a finite domain and I showed for each $r\neq 0$ there exists $r'\in R$ such that $rr'=1$.
 
user19161
Strange things happen. I was expecting votes for my latest answers, but I got votes for my -1 times -1 answer instead. Life is strange...
 
@JasperLoy It's not friday yet
 
Does this suffice to show invertibility?
 
7:53 PM
how to make a floor in LaTeX ?
 
user19161
@Carpediem Commenting on your own question with "can someone help me" will not help you get answers faster. In fact, it might have the opposite effect...
 
what is good friday?
 
user19161
@AlexanderGruber It is the day Jesus died on the cross.
 
@JasperLoy huh. that's... a little counterintuitive.
 
user19161
He said "God, why hast thou forsaken me?"
 
7:55 PM
@JasperLoy Meh..
 
user19161
And then he said "It is finished!"
 
user19161
To Christians, Jesus died for our sins and salvation.
 
user19161
Because of his death, Christians have life.
 
oh, that's right.
@DominicMichaelis lfoor rfloor
 
@JasperLoy The funny thing is the "sacrifice"
 
user19161
7:57 PM
@PeterTamaroff Well, I was just presenting the Christian point of view objectively.
 
Hey, you're gonna die and free people from sins. But then you'll be reborn, and be immortal and overlord of the world.
 
user19161
Of course, I have a Buddhist point of view myself.
 
What kind of "sacrifice" is that?
It was a total win win situation!
 
user19161
And to Muslims, Jesus is a prophet of God, but not God himself.
 
user19161
And to historians, there is no doubt about Jesus's existence on earth.
 
7:59 PM
@PeterTamaroff Can I ask you a question about a problem from Apostol
 
@JasperLoy is that true?
 
user19161
@AlexanderGruber Well, maybe there is some doubt, but not much!
 
oh i found one for this one here
 
@Carpediem OK.
@anon I got it.
 
@PeterTamaroff It's problem 8 page 303 (Section 9.8)
 
8:01 PM
@Carpediem Let me go fetch the book.
 
@PeterTamaroff It's volume 2
 
user19161
I wonder why so many questions have no accepts.
 
@Carpediem Ugh, I don't have that one in paper, let me look it up in the PC.
 
user19161
Is it because the asker does not really understand the solutions?
 
user19161
If so, they should really comment to ask for clarification.
 
8:04 PM
@Carpediem It's about showing properties of closed sets?
Oh,no wait,
 
Euh no
Here is the subject
1
Q: Derivatives of functions defined implicitly

CarpediemLet $F$ be a real-valued function of two real variables and assume that the partial derivatives $D_1 F$ and $D_2 F$ are never zero. Let u be another real-valued function of two real variables such that the partial derivatives $\partial u/ \partial x$ and $\partial u/ \partial y$ are related by th...

 
@Carpediem Oh, I really don't know about that.
I will study it this semester though.
 
@PeterTamaroff OK thanks anyway
 
@Carpediem try adding some tags
 
user19161
So guys, I plan to have 1k each month for the next 9 months. That will bring me to 30k this year.
 
8:08 PM
@JasperLoy That's not impossible.
I am however baffled by how Brian gets 8-9k each month, on average.
 
user19161
@PeterTamaroff Of course, I never speak of impossible things...
 
user19161
There can be miracles when you believe.
 
user19161
@PeterTamaroff Well, he has many accepts and also many fans.
 
user19161
I think @amwhy can get 100k this year if you continue at the same rate...
 
@jasper i plan to get mh i don't know i never plan something
 
user19161
8:15 PM
@DominicMichaelis What is mh?
 
just a sound when someone is thinking
 
user19161
lol
 
user19161
But it's really good practice writing solutions here. Will prepare you for writing books.
 
i use too much rep on bounties
 
user19161
I think I won't go to the other chat rooms from now, just stay in this one.
 
user19161
8:22 PM
Hey @argon happy Good Friday!
 
@JasperLoy To you too! :)
 
mh i got 8,2 k reputation in 43 days
i guess i will reach 20 k this year
 
I'm wearing a matching t-shirt for the occasion @JasperLoy
Let me show you.
 
user19161
@PeterTamaroff I wanna see your face!
 
user19161
Still waiting...
 
user19161
8:28 PM
Oh noes, I think Pedro has been kidnapped!
 
user19161
@PeterTamaroff Where is your face?
 
@JasperLoy Up! Heheheheh
I took it before you made that request...
 
user19161
@PeterTamaroff That is more important!
 
user19161
Anyway the T-shirt is very suitable.
 
8:32 PM
@peter do you think the hint is enough or should i make it explicit ?
 
@DominicMichaelis Maybe you can wait for the OPs input.
 
I am amazed that this answer hasn't gotten a comment for being so huge.
 
@robjohn What the...?!
 
at first i wanted to wrote "the obvious choice" but i thought it would be to chatty
 
@PeterTamaroff that is just a small pair of integers... there are many larger ;-)
 
8:36 PM
@robjohn I edited it, linked to PasteBin
 
still nobody know the identity of 5pm / PavelM ?
 
Dodek, lets suppose the set of vectors i gave you {(1 0 0 0 ) , (0 1 0 0 ), (2 0 0 0 )} implements the column vectors of a matrix, and that matrix implements Ax=b . I wanna turn the matrix A into reduced row echelon form, do i have 2 degrees of freedom to choose the free variables ?
 
argh i freaking hate it when people edit their question to add more questions
 
@DominicMichaelis I'm answering that one.
 
it's one line
preimages of closed sets are closed
 
8:48 PM
@PeterTamaroff I like my solution better. No need to move the answer off-site
 
@robjohn What was your solution?
 
i really thought that this answer would get more upvotes
 
@PeterTamaroff look
 
@robjohn Great one! claps
 
why not just taking preimages ?
 

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