Mathematics - 2013-03-09 (page 1 of 4)

Jonas Teuwen

00:03

Alright.

Jonas Teuwen

00:19

@HenningMakholm I can win you the (future) backstabber award.

@JacobBlack Yes, it does not allow me to login :'). Also, I am working on papers.

anorton

00:34

@user58512 I tend to get my continued fractions from Wikipedia. :p I'm not sure how to find it, though... (I haven't had any classes that used continued fractions--when I told my current prof about continued fractions, he was a little surprised...)

Jonas Teuwen

00:45

Why?

Tobias Kildetoft

01:28

@user58512 Hey, you here?

user2041143

If we have THREE numbers
a=4 b=3.2 c=1.95
Their sum is 9.15
Can we find THREE multipliers for those numbers m1,m2,m3 whose sum m1+m2+m3 is equal or smaller by multiplication of a*m1, b*m2 or c*m3
Note: you can't multiplicate a*m3.

Charlie

How is your head @jonas?

user2041143

01:44

Anyone?

user19161

@Amzoti Yes, you can steal everything you want, except my heart. =)

Peter Tamaroff

@JonasTeuwen Man, the first thing I do when I get near your place is eat in the restaurant you posted pics of. Looks fucking delicious.

If I ever get near you place...

@oldjohn looks like your fb is getting spammed.

Charlie

@PeterTamaroff hola

Buenas?

Peter Tamaroff

@Charlie Did you always have so little rep?

Charlie

@PeterTamaroff yes, does it bother you?

user19161

02:00

@Charlie No.

user19161

@PeterTamaroff Pedro, I change my name in 19 hours. Can you think of a nice name for me?

Charlie

Hmm

I'm dumb, that's why

user19161

@Charlie What are you talking about?

Peter Tamaroff

@Charlie I don't think we can talk anymore.

Charlie

@jacob what about Jasper?

user19161

02:02

@Charlie That's why what?

Peter Tamaroff

@JacobBlack Wilhelm

user19161

@PeterTamaroff Ah, why is that nice?

Charlie

@PeterTamaroff mejor

Peter Tamaroff

@JacobBlack Because I think it is nice.

Charlie

@JacobBlack I have low rep,.because I'm dumb, and stupid

Peter Tamaroff

02:05

@Charlie Wrong. You can't be both!

Charlie

@PeterTamaroff but I'm both

Peter Tamaroff

@Charlie If you insist.

Charlie

I only know simple math, like count from 1 to 10

Peter Tamaroff

@Charlie But, can you count to POTATO?

Charlie

No, I onky know positive integers

*only

Good night, everyone.

anorton

02:30

Grrr... sometimes, I get really annoyed at the people who try to "game" math.SE to get their homework done. I'm not an "on call" homework-checking service!

Tobias Kildetoft

@anorton then don't answer the homework questions

anorton

I'm about to stop entirely... I've been spending way to much time on math.SE anyway, so I think a month-long hiatus would be good for me.

I can tolerate a lot, but it's when some user looks at my answer, accepts it, unaccepts it, and says "You took a different path than I did to get the answer. If you write out my solution, I'll accept your answer." (I'm the only answer on the question.)

The same user proceeds to post several more questions saying "I'll try this in a minute-- can you guys solve it?"

:\

Tobias Kildetoft

link?

anorton

-1

Q: Computing $\iint \sin(4x^2 +2y^2)\, \mathrm dA$ over an elliptical region

$$\iint \sin(4x^2 +2y^2)dA,$$ where the region is bounded by ellipse $4x^2 + 2y^2 = \pi$ and the lines $y = 0$ and $y = \sqrt{2}x$. This looks like a change of variables integral. Need some hints. You guys are right. say region is also bounded by first quadrant. Here is what I did: ok you mu...

(In comments and through the edits to the post)

(Now looking at his comment on my answer, it appears he changed its text. Originally, it contained wording very similar to (I paraphrased slightly) my chat message above...)

George V. Williams

02:53

0

Q: Volume of bounded region between sphere and a plane

A solid spherical cap of radius $R$ is the solid delimited by a sphere of radius $R$ and a plane that intersects the sphere. The height $h$ of the solid spherical cap is the largest distance from a point of the solid to the plane intersecting the sphere. Show that the volume of a solid sph...

homework multivariable-calculus

"Give me a few min to try it out."

;_;

anorton

@GeorgeV.Williams Exactly. :\

user19161

03:14

Wow, I have 7 messages on the star wall. This is a miracle!

κρανίοπεριπολία

03:55

You must have believed.

Alexander Gruber

04:39

WHAT UP CHUMPS.

Jayesh Badwaik

@AlexanderGruber I see you are in exalted neighbourhoods. :-)

By the way, I asked yesterday the topic of your thesis, but I think you had gone away by then. So, if you don't mind, may I know what are you working on?

Alexander Gruber

Ohhh, my undergrad thesis?

Jayesh Badwaik

yes

Alexander Gruber

i'll show you

Jayesh Badwaik

okay.

Alexander Gruber

04:45

@JayeshBadwaik jstor.org/discover/10.2307/…

this is a paper by alan parks written the year i was born

Jayesh Badwaik

okay.

Alexander Gruber

the point is to describe M-groups completely group theoretically

so they can be understood by people who don't know character theory

Jayesh Badwaik

okay.

Alexander Gruber

so he defines these things called good pairs, which are subgroups (H,M) with 1 < M < H < G that abide to some certain properties

there is an equivalence relation on the set of good pairs in any group, which can be proved relatively easily using characters

then using that equivalence relation, he can prove all the things he is trying to prove

Jayesh Badwaik

okay

Alexander Gruber

04:48

but the whole point of the thing was to describe these guys completely using group theory, so it's a little dumb that there's still a part of it that can't be proved without characters

my thesis is a group theoretic proof of the equivalence relation

Jayesh Badwaik

ah, I see.

nice.

Alexander Gruber

yeah, i think it's pretty neat.

Alex Youcis

Why do we want a purely group theoretic way of describing them?For example, even though people really wanted a group theoretic way to prove Burnside's theorem, it is much better/nicer/easier to use character theory.

Alexander Gruber

basically just because it's not necessary

characters are kind of overkill for a lot of basic M-group stuff - parks was showing that you can understand the definition easily without any representaiton theory at all

Alex Youcis

What are M-groups?

Alexander Gruber

04:51

groups for which every irreducible character is induced from a linear character

Alex Youcis

Haha. Is there hope that they can be phrased without characters?

Alexander Gruber

yeah! parks was successful.

Alex Youcis

Is it as simple as the character theoretic description?

Alexander Gruber

no. :P

Alex Youcis

Yeah haha

I just read it

Why are M-groups useful?

I mean, I guess I see their simplicity in character theory

Alexander Gruber

04:53

i actually have no idea why but they are studied a whole lot

there are some interesting results though, unexpected ones - for example, they have to be solvable

i never would've seen that coming.

Alex Youcis

Hmm. Interesting.

Alexander Gruber

then for physics my thesis is just a bunch of data analysis algorithms for cherenkov detectors

(basically just using my work from the past few years so that I don't have to do anything new)

awllower

06:10

Does anyone know why this is true?

I mean my comment below the answer of Don Antonio.

I cannot understand how can the order of the automorphism group of P be 48.

user19161

06:26

@κρανίοπεριπολία Indeed. I see you have changed your name. I know not how to call you now.

κρανίοπεριπολία

Yep. @JacobBlack

awllower

@κρανίοπεριπολία
What happened to skullpatrol??

What have you done to him??

Oh

This is Greek skull patrol!
I see!
It must be that you have traveled to Greek, and thus changed the name accordingly, right?

Ethan

@awllower what is your profile picture

awllower

06:42

@Ethan It is a definition of zëta function on an elliptic curve.

Also it could imply the class-number formula for imaginary quadratic number fields.

Ethan

lol, lost me at elliptic curve

awllower

So i thought it would be wonderful to use that as apicture. :)

Oh

Ethan

is E a character?

awllower

$E$ means an elliptic curve in fact...

Ethan

lol

awllower

06:44

You can view it as a formal group law, if this makes you more comfortable. :D

Ethan

so its not an L function?

awllower

it is still L-function, with certain changes.

BTW, I am only a beginner in this field, so sorry I cannot provide a detailed and simultaneously intructive and inspiring explanation.

I am recently bothered by group actions...
I forgot a number of clever tricks now.

<-- Poor memory...

Alex Youcis

@awllower Have you ever used Sage or Pari?

awllower

Unfortunately I have never.

Alex Youcis

Ah, ok. Oh well haha

awllower

06:51

In my country, they are not very ubiquitous...

Alex Youcis

What is your country?

awllower

In fact I know what they are quite recently, haha

Taiwan, an island near china

Alex Youcis

I know what Taiwan is haha

awllower

:D

Alex Youcis

Interesting. You're into number theory I see?

awllower

06:53

I hope. :)

Alex Youcis

Haha, I guess that's as honest of an answer as one could hope for.

awllower

But the truth is: there are still much more to be learned, so that I cannot be said to start the journey. :(

Alex Youcis

Yeah, I know the feeling. What are you learning about right now?

awllower

CFT, ellptic curves(again), and some other things such as cohomology, or Galois descent.

Alex Youcis

A ha! Very interesting!

awllower

06:55

and do not forget about the representations :D

Alex Youcis

Never forget those haha

awllower

:)

Alex Youcis

What books are you using for those courses?

awllower

well

I am learning by DIY, so no courses at all.

And mostly I just look around, searching for some interesting books. :D

Alex Youcis

Haha, that's fair enough.

awllower

07:06

For CFT, personally I recommend Jürgen Neukirch!

Alex Youcis

Neukirch for everything haha

awllower

haha

cohomology: per chance Eilenberg will be good enough.

Alex Youcis

Have you tried Milne/

awllower

representations: Serre or IMartinIssacs

yes

Alex Youcis

Fan?

awllower

07:07

I tried once, but failed to fall in love with, :D

Alex Youcis

That's fair enough I guess. It's hard to beat Neukirch honestly.

His approach is just so modern and clean

it's perfect

awllower

And one concludes by one sentence: all is in group theory. :P

Alex Youcis

Sure haha.

awllower

Also, recently I found the book by Emil.Artin and John.Tate

Alex Youcis

Artin and Tate is not bad

awllower

07:09

amazing! is what I felt.

Alex Youcis

if you're looking for something slightly easier--some bedside reading--Nancy Childress's book is good

awllower

in particular, I went to that book because many people recommend that one when doing explicit computations.

Oh

Sadly my university did not possess the book...

Hey, I found PDF!!
I shall spend some time o it. Thanks for the recommendation!

Alex Youcis

Haha, no problem

awllower

Judgeing from the content, it starts by global case, thus proceeding to local one? Interesting!

Alex Youcis

Yeah. In fact, it really does local kind of half-ass at the end. It's very much more in the spirit of the original development of CFT

awllower

07:23

I see. Good to find a book!

awllower

07:36

I am wondering: why a group of order $9$ cannot have automorphisms of order=5 or 7?

Alex Youcis

Well

there is a

way to see it but its a little crass

your G is either Z_9 or Z_3^2

the automorphism groups of each are

have orders

6 and (3^2-1)(3^2-3) respectively

neither of which are divisible by 5 or 7

awllower

I have no question about the first: Z_9 case.
But how about the latter?
How to comute Aut(Z_3^2)?

Alex Youcis

You can interpret Aut_{grp}(Z_3^2) as Aut_{Z_3}(Z_3^2), and so you're looking at GL_2(Z/3) which you can just compute to have order (3^2-1)(3^2-3)

awllower

Is it related to matrix groups?

Alex Youcis

^^

awllower

07:41

haha

so it works like that...

Thanks a lot!

Alex Youcis

Haha, no problem. There may be a more elegant way--but you can just hack it that way.

awllower

indeed: it is quite good also.

Alex Youcis

Thanks ;)

awllower

;O

Alex Youcis

In what context did that come up?

awllower

07:46

This question.

Alex Youcis

Ah, I see. Makes sense haha

awllower

I have not yet been able to find a way to solve it which does not use the above-mentioned fact...

:)

Alex Youcis

I think that fact is pretty important. You want to prove there doesn't exist a non-trivial semidirect product, which basically is equivalent to showing that Hom(H,Aut(N)) is trivial. The easiest way to show that Hom(H,Aut(N)) is trivial is to show that Aut(N) and H have incomensurable orders so that you can't have a non-trivial map H--->Aut(N).

awllower

Indeed: so it stems from a cohomological property in fact?

Oh: if interpreted this way, I think I can understand why Andreas Caranti wrote his answer that way now!

Alex Youcis

The vanishing of H^2? Yeah, it's Schur-Zassenhaus. You have the extension $1\to N\to G\to H\to 1$ where $N$ is order $21$ and $H$ is of order $9$. But, Schur-Zassenhaus says then that H^2 vanishes so the sequence splits

awllower

07:53

Good!
It breaks the mists!

Alex Youcis

Haha, I'm glad I could be a mist breaker

awllower

Congrats: you have earned the badge: mist-breaker!
:D

Alex Youcis

Oh great--now my parents are going to want to hang that up on the fridge.

awllower

haha

Alex Youcis

@AlexanderGruber I wonder if there is any more clever way to deduce this fact.

@awllower Ever studied modular forms?

awllower

08:10

Studied a little as well.

Alex Youcis

@awllower Do you mind if I ask you a question about intuition?

awllower

intuition about modular forms?

Alex Youcis

@awllower You know what, I'm going to ask this question on the main forum. I'll link you to it when I post it.

awllower

Alright.
Looking forward then.

@AlexYoucis Well
I have to depart now. Maybe you can tag me and link the question, or you can just e-mail me!
[email protected]
Thanks in any case in advance for the attention!
Nice to talk with you!

Alex Youcis

see ya!

awllower

08:22

Later everyone.

Mats Granvik

08:41

I am of the opinion that $\lim_{n\to \infty } \, \frac{(n-1) \mu (n-1)}{\mu (n)} = 0$,where $\mu$ is the Moebius function in number theory.

Tomarinator

We need a latex parser for the chatroom.

Jayesh Badwaik

We already have one.

Mats Granvik

robjohn has put latex parser links here:
http://www.math.ucla.edu/~robjohn/math/mathjax.html

Alex Youcis

@awllower Here is the link to the question I asked

http://math.stackexchange.com/questions/325364/intuition-for-the-importance-of-modular-forms

@MatsGranvik Do you have to drag and drop that javascript every time you start a new chat?

Mats Granvik

No you drag and drop them once. And then in Internet Explorer you need to click them in the favourites for every new session. But I don't remember exactly how I got them moved to the favourites section.

Also I don't know if they need to be clicked for every new session.

delayed render is what works in my browser.

Ravi Upadhyay

09:04

If in a ring a.b=0 for all a in ring, then can we say that b=0.

Jayesh Badwaik

@AlexYoucis you save the javascript as a bookmark, and click on it everytime you manually refresh/visit this chat page.

for new changes from the server side, it does an automatic refresh.

Alex Youcis

@JayeshBadwaik How does one save the javascript as a bookmark?

@RaviUpadhyay No. Take $a=b=p$ in Z/p^2Z

@RaviUpadhyay Ah, I missed your "for all". The answer is still no, but I need a minute to remember the example.

Ravi Upadhyay

hmm, ok

Jayesh Badwaik

On robjohn's page, you can right click on the link and save it as a bookmark.
Basically, bookmarks have two fields
1. Name
2. Location

The javascript is the location and name can be anything you like.
If you have some kind of bookmark bar, then you can drag and drop the link in the bar.

Alex Youcis

@JayeshBadwaik Thank you! I hate to be "that guy", but I have a mac, and can't just right-click and save as a bookmark. Do you know how it works on a mac?

Jayesh Badwaik

09:12

@AlexYoucis How do you save other bookmarks? There should be no difference between them and this.

Ravi Upadhyay

right click on bookmark toolbar, give it any name, and then in location copy paste the javascript.

*right click on bookmark toolbar and create a new bookmark

Jayesh Badwaik

@RaviUpadhyay Duude, there is no right click in his mac. ;-)

Ravi Upadhyay

apple.com/findouthow/mac/#bookmark

Alex Youcis

@RaviUpadhyay Does this work

we clearly need the ring to be non-unital

yeah?

Ravi Upadhyay

yes

Alex Youcis

09:17

Ok, so let $A=\begin{pmatrix}0 &1\\ 0 & 0\end{pmatrix}$. Let $R$ be the ring $\{p(A):p\in \mathbb{R}[x], \deg(p(x))>0\}$

Jayesh Badwaik

@RaviUpadhyay you cannot visit the javascript as a site, and that creates problems I suppose.

Alex Youcis

So you take the set of elements of the form c_nA^n+...+c_1A

note then that since A^2=0

A annihilates everything in this ring

@RaviUpadhyay Yeah?

Jayesh Badwaik

@AlexYoucis I guess the best way is to open your bookmark manager, and try to add a custom bookmark and then enter the javascript as a location. (I have never used a mac, but I think this should be possible atleast.)

Ravi Upadhyay

is there any zero element in the ring?

Alex Youcis

@RaviUpadhyay Yeah. So basically $R$ is the ring of matrices of the form $c_n A^n+...+c_1 A$, where all the $c_i$ could be zero.

Ravi Upadhyay

09:24

@AlexYoucis but what is the zero element in your ring? All the elements in the ring are of degree > 0.

Alex Youcis

0 is degree infinity

@RaviUpadhyay

Ravi Upadhyay

@AlexYoucis i

Alex Youcis

@RaviUpadhyay Yes, my friend?

Ravi Upadhyay

've just begun Rings. Sorry but I am having trouble understanding which is the 0 element of the ring.

Alex Youcis

Here are some leements of the ring

3A_5A^3

sorry

3A+5A^3

-26A^2+A^7

4A^2+8A^8+88A^10

0A+0A^2=0

Ravi Upadhyay

09:39

but degree is defined as the largest integer i for which the ith coefficient is not 0, and if the polynomial is constant we regard it as 0 degree.

so wouldn't that make the degree of 0A+0A^2 0, rather than infinity.

Alex Youcis

@RaviUpadhyay You're fixating on a minor concept. The zero polynomial is defined to be degree infinity--there is NO power of $A$ with non-zero ceofficients.

Ravi Upadhyay

@AlexYoucis

Alex Youcis

no

If the coefficient of that poly was zero

that would mean the coefficient of A^0 was nonzero

which it isn't

its infinite degree

@RaviUpadhyay

Ravi Upadhyay

ok, thanks. got it.

Alex Youcis

no problem man

Jayesh Badwaik

09:44

@AlexYoucis Isn't a zero polynomial said to be of degree -1 in general?

Alex Youcis

No. Infinite degree.

Jayesh Badwaik

I see.

Ravi Upadhyay

Degree of a polynomial

The degree of a polynomial is the highest degree of its terms, when the polynomial is expressed in canonical form (i.e. as a linear combination of monomials). The degree of a term is the sum of the exponents of the variables that appear in it. The word degree is now standard, but in some older books, the word order may be used instead. For example, the polynomial 7x^2y^3 + 4x - 9 has three terms. (Notice, this polynomial can also be expressed as 7x^2y^3 + 4x^1y^0 - 9x^0y^0.) The first term has a degree of 5 (the sum of the powers 2 and 3), the second term has a degree of 1, and the last te...

here it says -infy

Alex Youcis

Haha, jesus guys.

we define deg(p) to be inf{n:a_n\ne 0\}

Infimum

In mathematics, the infimum (plural infima) of a subset S of a partially ordered set T is the greatest element of T that is less than or equal to all elements of S. Consequently the term greatest lower bound (abbreviated as glb or GLB) is also commonly used. Infima of real numbers are a common special case that is especially important in analysis. However, the general definition remains valid in the more abstract setting of order theory where arbitrary partially ordered sets are considered. If the infimum exists, it is unique. If S contains a least element, then that element is the inf...

infimum of empty set is infinity

Ravi Upadhyay

ohh, sorry.

infinity it is. seconded :)

Alex Youcis

09:47

@Ethereal what?

Jayesh Badwaik

Yes. its not big deal I agree.

Ethereal

How does this make an assumption that if $p|a^m$ then $p|a$?

@κρα Math symbols much?

Ravi Upadhyay

on the contrary assume p does not divide a.

Ethereal

@AlexYoucis What what?

Alex Youcis

@Ethereal what?

Ethereal

09:51

@RaviUpadhyay Can you explain further?

Ravi Upadhyay

@Ethereal use prime factorization of a.

since p doesn't divde a, it won't occur in p.f. of a.

hence it won't occur in p.f. of a^m

thus if p|a^m => p divides some other prime number other than itself

Ethereal

wait, let me think.

libjup

morning guys :-)

Ravi Upadhyay

good afternoon.

Ethereal

Ah, all right.

libjup

09:54

if I have a triangle and a circle in 3D how can I determine the points in which they intersect?

Ethereal

I thought earlier what you were thinking, but I was in doubt.

libjup

* I have the coordinates of the triangle and the equation of the circle

user19161

My favourite colour is now black.

Tomarinator

I see ;)

user19161

Zev is blue, Julien is red, and I am black, QED.

Tomarinator

10:10

I was once black too, but then I decided to transform to much much cooler avatar, i.e trunks from dbz.

Why do I sound like Michael jackson :p

I run the "start chatjax" bookmarklet, from here , nothing happens , and error reported in the console is Uncaught ReferenceError: MathJax is not defined , though it was running like a charm few minutes ago. weird

Jayesh Badwaik

Runs alright for me as of now. May be mathjax site is unaccessible from your place?

Tomarinator

@JayeshBadwaik I am able to open Mathjax.org

Jayesh Badwaik

Ahaa, then there must be some other error.

Tomarinator

I think its the firewall, yes thats it.

Jayesh Badwaik

what had you firewalled?

all non-approved javascripts?

Tomarinator

10:25

Its my college firewall, and it blocks a lot of stuff. Its stupid as shit

Jayesh Badwaik

proxytunnel is a good tool to keep all firewall headaches away.

Tomarinator

Checkin it out

Rustyn Yazdanpour

@libjup how would it be any different from 2D? That's what you should ask yourself

Jayesh Badwaik

For windows I think proxifier is more popular, I am not sure.

@RustynYazdanpour Hi. I saw your question on meta "Academic Integrity" and I was not completely sure what you were getting at. I think that the main points of your worries were the following two:

1. Answers on different levels of expertise which may or may not benefit the reader.
2. Automatically providing answers to any questions which may help students cheat in their courses.

Is that correct?

Rustyn Yazdanpour

@JayeshBadwaik 2. is my biggest concern

uhh but no.

I'm more concerned with the act of compulsive answering, (I'm no longer concerned with cheating)

Giving a full answer can hinder the learning process and create dependency cycles.

@JayeshBadwaik The student needs to develop their own rapport with mathematics, and that won't happen if he or she doesn't discover things. Logical leaps are what brings them closer to trusting their own faculties. They need to experience continual success attributed to their own efforts. By providing a full answer to a low quality question, (or demand), we perpetuate a dependency cycle. This action isn't fostering academic independence.

@JayeshBadwaik In that spirit, I should probably rename the question.

awllower

10:42

@AlexYoucis I see the question. But sorry I cannot help you: I am not familiar enough with such geometric notions as the line bundles, tangent bundles, and cotangent bundles. But I see what you are asking in general. Again I cannot help you, for I am only a beginner...Sorry again. :P

Jayesh Badwaik

Okay, that is good. Because, personally I feel, fighting a battle against cheating by holding back answers is a completely losing proposition and will create more harm than help.

About providing full answers, I agree completely with you. Simple, short questions should be given only hints. The response of the answerer should be proportional to the response of the poster (especially for very basic questions).

I am also thinking of "hiding" answers by default and then showing them by drop-down arrow, in case the student wants to see a particular answer. In this way, a student willing to exer…

Rustyn Yazdanpour

@JayeshBadwaik I just renamed the question: 'Curtailing a student's potential'

@JayeshBadwaik Unfortunately now it's no longer on the community bulletin board :(

Jayesh Badwaik

@RustynYazdanpour It will come back soon enough I guess. :-)

Rustyn Yazdanpour

11:08

@JayeshBadwaik I have made some edits to the main post and I was wondering if you would feel inclined to read them.

Jayesh Badwaik

11:18

@RustynYazdanpour I am reading. As I said, I am much in support of your effort. I am not sure how to act upon it though. One method which I think might work is a guideline of posting a complete answer only 1-2 days after the question has been posted. This delay might be enough in generating requisite effort on the part of the student.

Till the period, people should only comment on the answer. However, knowing of the answering dynamics among the users, this effort is bound to fail in a way similar to prisoner's dilemma in case the requirement is unofficial.

(People will answer a little early in order to gain reputation before other people and slowly the margin would corrode away.)

Homework tag is somewhat ill-defined. For example, some of my questions are (homework) category, but since I am currently self-studying, I am not sure I want to put a (homework) tag in the questions.

which essentially boils down to robjohn's suggestion somewhere on the site.

The suggestion is bound to fail due to prisoner's dilemma. The only hope is to design something that takes into account the factor.

Rustyn Yazdanpour

@JayeshBadwaik I'm not suggesting a resolution to this problem. I realize we can't have uniformity in dealing with these issues. What I'm proposing is we embellish our about statement. I think we should have a different expectation in regard to dealing with questions from students, although I do not posit that we need any sort of uniform practice in dealing with these issues.

@JayeshBadwaik In regards to resolving the issue, 5pm gives the only plausible solution.

Jayesh Badwaik

11:39

Yes, I understand that. But I think I might have some ideas to make the situation better without forcing people to do something or the other. Let me see if I can get some aspects of it correctly. I might post this on meta in some time.

Rustyn Yazdanpour

@JayeshBadwaik I would appreciate your participation. The thread is not edited in full.

now*

Garbage Collector

12:18

@JayeshBadwaik: I think you are also a member of TeX.SX. If you don't mind, you can participate in meta.tex.stackexchange.com/questions/1564/tex-community-polls/….

Jayesh Badwaik

@GarbageCollector Ahh yes. Thanks.

Garbage Collector

@JayeshBadwaik OK. Thanks for participating. :-)

Jayesh Badwaik

@GarbageCollector How do I select my country? By upvoting the comment?

Garbage Collector

@JayeshBadwaik Yes. By upvoting the comment.

Martin Sleziak

12:34

@RustynYazdanpour Perhaps your question should be tagged homework now that you added that it is about bearing the homework tag

user19161

@GarbageCollector Hey W.

Garbage Collector

@JacobBlack: hi jasper loy.

Have you participated meta.tex.stackexchange.com/questions/1564/tex-community-polls/….

user19161

@GarbageCollector I have deleted all my accounts except math.

Garbage Collector

@JacobBlack Oh my ghost!

user19161

@GarbageCollector LOL

user58512

12:43

hello

κρανίοπεριπολία

hello

user19161

I have done 400 edits, so 100 more to get copy editor badge...

κρανίοπεριπολία

...good luck.

user19161

@κρανίοπεριπολία What does your new name mean?

κρανίοπεριπολία

The same as my old name.

user19161

12:52

These days I get very few votes for most answers, then suddenly many votes for an answer on a hot question.

κρανίοπεριπολία

Hi @GarbageCollector How are you?

Garbage Collector

@κρανίοπεριπολία Hi, I am almost fine everyday. :D And how are you?

κρανίοπεριπολία

Fine thanks. @GarbageCollector

:D

libjup

13:27

hi guys

if someone asks "how many meters of the triangle are outside the sphere?" what does he mean by that then?

user19161

13:50

@libjup It is not clear what he means without more context.

libjup

@JacobBlack there is a sphere and a triangle which intersect in two points. and now the question is "how many meters of the triangle are outside the sphere?". I don't get that question... I mean meters?! which distance?

Charlie

@κρανίοπεριπολία Hiiiii!

user19161

@libjup Would be better if one can see the diagram.

libjup

true but I only got thet text info.with the help of SO math.stackexchange.com/questions/325411/… I was able to solve the intersection points

user19161

@libjup Probably means the part of the triangle outside the sphere. Triangle has 3 lines.

libjup

13:55

you mean from the triangle to the surface of the sphere?

user19161

Yeah the two line segments outside the sphere.

user19161

But I don't see that question on your link.

Charlie

@jacob we're both black

Transcript for

$Mathematics$ Mathematics