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16:01
@Argon You mean $(3)$?
16:12
hello
Hey gus
hi @AkramHassan
what's up @user58512?
hi @robjohn?
im confused
user19161
So am I.
16:21
I am just fused having carried out too many cons.
@JacobBlack what is wrong with my answer?
user19161
@Khromonkey Which one?
the one about the gp
guys, Apostal or Spivak, for "really" understanding calculus?
Spivak
16:23
spivak
user19161
Why Spivak?
because i haven't read apostal
Spitvak.
user19161
@Khromonkey Your first sentence is already wrong, so I did not read further.
Apostol is better.
16:26
why?
think it is correct
user19161
The form of a GP is a, ar, ar^2,...
i divided by a
user19161
It is not 1, a, a^2,...
user19161
Then the writing is not clear.
user19161
Even if it is 1,a,a^2, the formula is wrong.
16:28
@Ethereal Why do you think so?
I personally found Apostol not coherent, especially in the starting. There is no big picture about where we are going. In spivak, I could predict and work out what happens in the later chapter on my own. I could not do similarly in Apostol. I found it rather, here is the stuff, and here is how to do it.
is it?
user19161
Read carefully.
Apostol seems really pure
which i like
its correct
16:30
@OrangeHarvester I found it hard.
My opinion doesn't matter, but still...
@Ethereal Spivak?
$a^0+a+a^2...+a^n=\frac{a^{n+1}-1}{a-1}$
user19161
@Khromonkey That is not what you wrote there.
@Ethereal I am not arguing against you, just wanted an opinion. It is perfectly fine to like apostol too. (Your opinions matter.) :-)
:8247682
16:31
just get spivak its better
user19161
I prefer Apostol.
ok, is it correct now
?
I have too many books.
No more storage.
@JacobBlack, why?
I have too many books, I don't understand 1/4 of the books I own
My grandfather buys me math books
16:33
@JonasTeuwen Does your VPS provider give you ArchLinux for hosting?
You can chose or provide your own image.
But I took their pure Debian image.
It is a good choice for a server.
I see. Yes. I would prefer Debian too.
@AkramHassan hello
user19161
16:34
@Khromonkey No, because the ratio can be positive or negative.
what ratio?
There is also CentOS.
user19161
@user58512 Well, at least one gets more multivariable calculus and also differential equations and probability thrown in as well. =)
@robjohn Yes, $(3)$. I differentiated the denominator and plugged $z^\pm_k$, but it didn't simplify well for me.
I see
16:35
oh, I only need it for positive a's
user19161
@JonasTeuwen CentOS does not even have TeXworks now.
That's perfect, I don't need it on a server.
It is a server OS.
Otherwise take Fedora.
user19161
@Khromonkey Why can't the ratio be negative?
he said that the sum was positive and a was also
@Argon Note that on the lines $\mathrm{Re}(z)=\pm\mathrm{Im}(z)$, that $\cos(z)=\overline{\cosh(z)}$
16:38
@jacob hello, Jaspito
user19161
@Khromonkey The first term can be postivie and the ratio can be negative and the sum still can be positive.
good point
user19161
Also, why use a for the ratio when the common notation is r?
user19161
Bad notation, wrong ratio, and originally wrong first line, QED.
@JacobBlack And there you go again.
Using QED unnecessarily. You should burn, man.
16:40
If I want to use :) as ratio, I do
user19161
@PeterTamaroff Hehe, with you.
using QED when critizising other people is sort of like having sex in front of your ex
7
@Charlie My math teacher sometimes uses smileyfaces as variables
user19161
WTF?
user19161
Well, if you ask me, be prepared for my strict criticism.
16:42
@Khromonkey I fail to see the paralellism.
I'm only gonna break your heart.
user19161
See, after Peter asks me sth he will say bleh, then he might as well not ask me.
@Argon Is the teacher a he or a she?
what is sth?
@Argon yay!
16:42
@PeterTamaroff She
user19161
sth is something
user19161
sb is somebody
somebody is me
@Argon She's lonely.
16:43
oh
@user58512 Here, have a candy.
how to find hte minimum of a function f(1),f(2) to f(1000) in pari gp??
@PeterTamaroff She is married
@PeterTamaroff and he would be?
@Argon all the more the reason to be lonely. :P
@Argon That doesn't mean anytinhg.
16:43
This is so unfounded :)
I'M not understanding anything!
@OrangeHarvester He would be probably a pederast. But who knows...
Oh, so then the question might have two solutions
@Charlie Good.
user19161
I suggest you study AP, GP again @khr.
16:44
@Argon or using $(1)$ is even easier
@Argon do you mean confounded?
come on don't insult me
I haven't even studied gp yet
@OrangeHarvester That too haha
user19161
I am serious, it does not hurt to study again.
16:44
I just took that result out of a book
user19161
One cannot fly before running.
user19161
One cannot run before walking.
@PeterTamaroff estás borracho, Pedro?
@Charlie habla espanol, amigos?
user19161
As I always say, if you go too fast, it will all fall apart.
16:46
and if you go too slow.....
user19161
There is no such thing.
but the ratio still works @JacobBlack
It's not wrong
Slowly you go far
unless a=1
@OrangeHarvester No estaba esperando eso.
@Charlie Not at all.
user19161
16:48
@Khromonkey What do you mean by still works?
is still true
user19161
Anyway, the rest is your homework.
user19161
What is true?
@PeterTamaroff are you sure?
user19161
If the first step is wrong, there is no need to see the second.
@PeterTamaroff I do not know anything else. :P
user19161
However, if one can reduce it to the case where the ratio is positive, then one must explain why.
@Charlie How can't I be sure. Listen to yourself!
user19161
But I am not saying that is the case here.
what is the case?
I don't understand anything
user19161
16:51
I already told you the ratio can be positive or negative.
what ratio?
user19161
The ratio of the GP.
@PeterTamaroff some drunks claim not to be drunk, it.happens
ok, i assumed it was positive
but I can check for the negative case
@Charlie Oh, man. When will you upload a picture of you to your facebook?
16:52
but I think the answer asked for positive
you guys are friends on facebook?
@Charlie Hey, you're not that much older than me. Barely a year.
user19161
I have no facebook.
@PeterTamaroff when is your birthday?
user19161
I also have no face.
@Charlie July the 6$^{th}$
16:54
@Khromonkey yes
@JacobBlack But you have books!
user19161
@Argon There can be miracles when you believe.
@JacobBlack Hehehe
@PeterTamaroff less than a year then
16:55
@Charlie When is your birthday?
@PeterTamaroff may 22nd
user19161
Some time this year.
september 2
user19161
Just announce it when your BD comes. I will be here to smash a cake into your face.
@anon how is the hangover going?
user19161
16:58
@Khromonkey How do you write dates there, month or day first?
day, I think its better
go from shorter to longer
why can't dates be written Jan, Feb, etc. instead of numbers - then it doesn't matter what order you write it
user19161
I like writing in this format: 03 Jun 1452
I like writing it like this:
1361725232
@OrangeHarvester stardate...
17:02
@Charlie Hmm, mine is the number of seconds since 01/01/1970 00:00:00 UTC
stardate is cool too.
Hmm... 1361725405015
:)
@Argon cool. That is even better I think. :P
@OrangeHarvester This is Java's "System.currentTimeMillis()"
I write 24/02/13
I write 24/02/2013 actually.
17:04
I like writing in days after megan fox was born
@Khromonkey you win the contest I suppose.
I use dates from the Seleucid Era
:)
what's good about megan fox
I think "find" should be able to handle regex
@user58512 everything
i can see
17:12
@Argon it does.
@OrangeHarvester Not on Windows
@Argon Windows has "find"!
Not with regex!
I mean I am surprised that windows has find.
Hello @robjohn, I believe the linked question here is not an exact duplicate. Don't you agree?
17:14
@OrangeHarvester Of course! Ctrl-F :)
@Argon Eh, I thought you were talking about the find command on command line.
@OrangeHarvester No, no. I mean find in general, on pages and stuff
:)
@Gigili They look pretty identical. They both ask for a bijection from $2^A$ and $\mathcal{P}(A)$
17:18
@robjohn Umm, not really.
@Argon i wanted to have ctrl+f everywhere...
@Charlie It would be handy for notes :)
@robjohn Pfft, you're right. I was looking at another page!
@Argon YES
Sorry.
17:21
Hmm... It's snowing!
@Argon cool!
17:34
I feel sleepy now
17:50
Is (2) a Liouville number?
can someone tell me if i am right ?
in the following taylor expansion .
$\phi (t)=u(tx+(1-t)y)$
i want to expand $\phi$ around $1$ .
$\sum _{j=0}^{m-1} \frac{1}{j!} \phi^j(t)$
18:08
Halp
18:26
@Khromonkey good. woke up still drunk, chugged water, back to sleep, wake up craving french toast.
what did you drink?
@arkamis how?
I have a complex analysis question.
jagermeister, russian standard, white russian, some wine I don't remember
why did you get drunk?
Suppose an entire function maps two horizontal lines onto two other horizontal lines. Prove that its derivative is periodic.
18:29
I think robjohn is good at complex analyisis
There is a hint given, assume f = u+iv maps y=y1 and y=y2 to v=v1 and v=v2 with y2-y1 = c and v2-v1 = d. Show that f(z+2ci) + f(z)+2di.
24 hours ago, by anon
ladyfriend's bday party tonight. otherwise, math and nostalgia.
I've got no idea where even to begin, aside from using schwartz reflection principle
:-)
18:35
Is there any non real solution of cosz=1/2 ?
@WaqasAliAzhar yes, if you write it using complex exponentials, multiply through you can obtain a quadratic equation
yes, by my calculations, i get only real
is that true?
oh, right, 1/2 is in the range of cos. then only reals sounds right.
what about sinz=1/2?
same thing no?
18:39
I am solving this, please wait for a sec
the solutions to sin(z)=a and cos(z)=a are in bijection to each other according to the transformation x->pi/2-x, which preserves reals and nonreals.
exp(iz)-exp(-iz)=i
oh great
but how to do it for sin, using exponentials
again by quadratic formula?
yeah
ok thank you, can i ask one more thing?
yeah
18:44
what is the image of a unit circle and an open unit disc under the transformation z--> 1/z
unit circle stays (since reciprocation is just conjugation on it). the image of the open unit disk is its complement (0 and the point at infinity notwithstanding)
oh so the open disc becomes the remaining part of the plane
with zero as well
z->1/z is a standard way to do inversive geometry using the complex plane, in fact
i know that the exponential map is the covering of unit circle
so what i get if i apply this to only x between -1/2 and 1/2(end points also included) and y greater equals to 1
I'm not doing your homework for you am I?
18:49
no
It's an exercise in the book that i am reading on complex analysis
look at where each segment of the rectancle's perimeter would be sent under exponentiating, then fill in accordingly
hello
I feel lazy :(
does anyon want talk
19:09
hi
hello
@user58512 how are u?
I'm ok a bit confused
how are you
@user58512 feel bad
what's wrong?
19:11
@user58512 math's exam is coming and I still have a lot of things to do
it'll be ok
$z^2-2sin(\alpha)z+2(1+cos(\alpha))=0$ like solving this equation in $\mathbb{C}$
19:22
I need to do some work :(
I am too lazy
@gnometorule, hello
19:35
@user58512 me too
I have tried to upvote my own answers like a thousand times
0
Q: Schwartz Reflection Principle -- Mapping across horizontal lines

ArkamisI am stuck on the following problem: Suppose an entire function maps two horizontal lines onto two other horizontal lines. Prove that its derivative is periodic. The author supplies a hint: Assume $f = u+iv$ maps the lines $y=y_1$ and $y=y_2$ onto $v=v_1$ and $v=v_2$ with $y_2-y_1 = c$ and ...

If I could get a couple eyes on that, I'd love you all.
only to have my heart broken when it tells me I can't. Allthough for a second I feel great because the number does change and everything seems well.
0
Q: Solving complex equations

pourjourSuppose the equation $(E):z^2-2sin(\alpha)z+2(1+cos(\alpha))=0$ / $z\in \mathbb{C}$. I tried to calculate the discriminant but I could determinate it's sign(there is a hint $\Im (z_{1})\ge \Im(z_{2})$ / $z_{2}$ and $z_{1}$ are the two solution of the equation. In a second case we suppose $(E_{2...

19:56
@pourjour, are you an undergrad?
@user58512 yes
how many years left?
@user58512 this the last year
will you be glad when its over?
@user58512 yeah I'm tired of studying
20:05
I am tired of my work too, it will be nice to move on
@user58512 so you've got a job?
I mean the school work
@user58512 hmm
20:37
hi
I finished my work today!
@user58512 great!
I'm very pleased
@user58512 What did you do?
I went over my group theory notes
20:53
hi
hello
My first time on chat ^^
welcome
@GustavoMarra Run while you can!
how do I put verbatim text in a footnote?
in a latex document?
and what's the difference between text and verbatim text?
it's for source code
21:07
blah blah\footnote{stuff}. blah
so the entire footnote you write will go inline in the middle of your paragraph (in the source code)
I can't use verbatim inside footnote that way
thanks
@skull hi!
@Charlie $\Huge\text{Hi! :-D}$
21:18
@skullpatrol how are you??
@Charlie Fine thanks, how are you?
@skullpatrol Fine
@Charlie How did you like the songs I posted in the party zone?
I liked @skull :)
@Charlie I found another classic...
21:23
@anon, do you know Circle Method?
@skullpatrol nice!
nope
I want to learn it

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