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20:00
i am fine and how are you ?
my theo exam was such a mess
@charlie still fine :D
J G
J G
Has anybody used the EM algorithm before (Efficiency-Maximization)?
@Charlie $\sup$?
I'm fine
@JG yes, sometimes I go the diagonal of a rectangle instead of the perimeter when I'm walking
@DominicMichaelis why?
J G
J G
20:06
Oops. I meant expectations-maximization
NBP
NBP
Is there a reason why I'm not getting answers for a coupling question I asked? Is this not a known probability concept?
@anon @MarianoSuárez-Alvarez Hahha. Need some help!
@anon HOw did the storm go?
had to shovel snow
three times
20:07
Did you have no problems?
thursday campus was closed
NBP
NBP
anon: we got no snow where I live.
Are you from scotland?
otherwise no issues
midwest usa
@NBP Nebraska man.
NBP
NBP
Could anyone help me with a coupling problem?
20:08
@NBP Chocolate usually works.
NBP
NBP
Peter, I don't understand
you're saying eating choclate makes people think better and thus solve coupling problems?
clearly you are not a romantic then!
You said you had a coupling problem...
NBP
NBP
that would be true for all mathematical problems I think
i never thought that a 2 x 2 matrix could ever be so ugly
NBP
NBP
20:09
I see no reason for this tip to be specifically useful for these type of problems
a 2 x 2 matrix can be four times as ugly as any normal expression
2
it's a joke, not a tip
@DominicMichaelis what??
@anon Anon.
Peter.
20:10
My solutions to coupling problems always begin with, "here, have this glass of wine first."
NBP
NBP
@anon, I've already found my one true love, so it's not that kind of coupling problem
Anyway, this is a mathematics channel, why would I address you guys with relationship issues
not sure if serious
NBP
NBP
It should be obvious from context that I'm referring to a mathematics coupling problem.
specifically a probability space one
I have been given the following problem. Define a group on $\Bbb Z^3$ by summing coordinatewise in the following manner $$(x_1,x_2,x_3)\oplus (y_1,y_2,y_3)=(x_1+y_1+x_2y_3,x_2+y_2,x_3+y_3)$$
NBP
NBP
sorry for not being clearer anyway
so, could any of you guys help me with a probability coupling problem?
20:11
@NBP we talk about everything here
NBP
NBP
@Charlie but it says mathematics..
nbp, everything was clear from the start, you just need to get used to people having fun for the sake of having fun
@anon I have to show that this group is isomorphic with the group $G$ obtained by the relations $x_1x_2x_3=x_2x_1$, $x_1x_3=x_3x_1$ and $x_2x_3=x_3x_2$ on $FG^{(3)}$
"rarely if ever expressible as the ratio of integers" was put in the room description for a reason :)
NBP
NBP
@anon, I figured mathematicians were above these sort of stuff. alas
20:12
Now, as I understand it, $G$ is $FG^{(3)}$ quoted by the normal group generated by the elements of those equations $=1$.
NBP
NBP
Can I link you to the problem?
yes
@NBP everything is math
Namely $x_1x_3x_1^{-1}x_3^{-1}$ &c...
NBP
NBP
20:13
it should be simple for men of your stature
though I see no algorithmic way to approach such an exercise.
not sure if there's a probabilist in the room atm
NBP
NBP
@Charlie, I have never experienced anything physical that is math. in my opinion maths deals with abstract, pure concept
@NBP I think Didier Piau is boss at prob.
NBP
NBP
@anon, where can I find one?
Is he the guy who answered me?
20:14
He's user is "Did"
@DominicMichaelis write the entries as a,b,c,d - solve for eigenvalues in terms of these, then plug in the expressions for a,b,c,d
NBP
NBP
Well, I think he misunderstood my issue
and now he's not responding
@NBP Yes.
He commented.
@NBP Do not upset him.
I think he's kinda moody =P
NBP
NBP
I didn't, sorry
"All you have to do now is to show size 4 is not possible. Assume Ω has size 4 and try to reach a contradiction."
Oh, you don't like that.
20:16
@DominicMichaelis oh
@anon yeah it was in a theoretical physics exam
NBP
NBP
Well I couldn't do that, but that's really missing the point of my question (which is also why I didn't post the probability space I found in the first place)
@anon What do you think of my problem?
@PeterTamaroff You want to define a map $F^{3}\to G$ such that the images of the $x_1,x_2,x_3$ satisfy the desired relations. My first guess would be to check out (1,0,0),(0,1,0),(0,0,1), and if adapt if need be.
NBP
NBP
@Peter Tamaroff, my biggest concern is not being able to assert that the cardinality of that probability space would be five, and it feels as if I found it by chance - and only then would it be viable for me to address the fact that 5 is the minimal probability space required.
20:17
@anon Yes, but then I'd have to quote by the kernel, yes?
@NBP Chance is good!
Many times we find stuff by chance.
NBP
NBP
Not when it's in an exam and you have 5 minutes to solve a problem
then (given surjectivity), G would be iso to the quotient of F3 by the ker, yes
NBP
NBP
As happened to me
@anon Oh, yes. That is the basic of free groups plus the 1st iso.
Tim
Tim
@Ilya: Hello, can I ask a few quick questions regarding my two posts?
20:19
@anon Using $e_i$ in order we don't get what we want.
We get $(a,0,0)\oplus(0,b,0)\oplus (0,0,c)=(a+bc,b,c)$
I think $e_1,e_3,e_2$ does it.
you want a puzzle ?
Tim
Tim
1. in math.stackexchange.com/questions/309623/…, is my comment before the last one correct regarding Fubini's theorem and proving $f \in L^2([0,T]\times \Omega)$?
NBP
NBP
@Dominic Michaelis, no I haven't solved this coupling problem yet.
@anon Oh, great. If we set $x_1=e_1$, $x_2=e_3$ and $x_3=x_2$ we win.
goodie good.
20:22
I actually tried first to set up equations using the defining properties.
Tim
Tim
2. In the same link in 1, in Ito's isometry, on its LHS, is the ito integral $∫^T_0 X_t dW_t$ a $L^2(Ω)$ function?
And solving for the coordinates.
But I think I messed up.
Oh, no wait.
I just didn't chose wisely.
Because I did get $x_1=(x,0,0)$
Tim
Tim
3. On the RHS of Ito's isometry, is $∫^T_0 X^2 dt$ a Lebesgue integral or something else? (I asked it here math.stackexchange.com/questions/311211/…)
and $x_2=(0,0,1)$
I think I messed up with $x_3$
@anon Thanks.
I proved the following.
Let $N_S$ denote the normal subgroup generated by $S\subset G$, $G$ a group.
Then set $^g S=\bigcup_{g\in G} g^{-1}Sg$.
We have $\langle ^g S\rangle =N_S$
NBP
NBP
@Peter Tamaroff, how do I contact this Did guy?
20:25
@NBP Comment on the post.
NBP
NBP
Can I have his phone number? maybe he didn't notice I commented again
Just ping him.
NBP
NBP
I did comment on the post
@Did
@NBP Whu? Just be patient...
NBP
NBP
@Did, are you here?
20:25
@PeterTamaroff your union is called the normal closure operator (the intersection would be called the normal core operator). just trivia.
@NBP No, I never see him around.
@anon Oh, and why is it called like that?
NBP
NBP
@Peter Tamaroff, so pinging and commenting didn't help, where can I get his number?
I have only seen him here a handful of times. But of course if pinged he will see it in his inbox.
Also, it is bad practice to write $^g S$ for that conjuation?
@NBP random people over the internet don't often give their phone numbers to likewise random people
20:27
@NBP I don't have it, but I don't think he'll enjoy getting called and stuff.
He has a wwebpage. Google him.
Tim
Tim
I saw Didier once or twice in Chat room
I said hello to him
@anon Or their name [cough cough]
2 mins ago, by Peter Tamaroff
@anon Oh, and why is it called like that?
@PeterTamaroff probably, yes. oftentimes group theorists will use $S^g=\{g^{-1}sg:s\in S\}$ and ${}^gS=\{gsg^{-1}:s\in S\}$ (this way $x\mapsto x^g$ is a right action and $x\mapsto{}^gx$ is a left action, which makes exponential notation easier with composition)
typing, dammit
NBP
NBP
@Peter Tamaroff, I'll be respectful and my english is pretty good
@anon Oh, OK. Sorry!
20:28
>:<
(don't be too alarmed)
@anon And one is an homomorphism while the other is a antihomomorphism, or what was it called?
when $a(xy)=a(y)a(x)$
normal closure gives the smallest normal subgroup containing blah, just like the topological closure gives the smallest closed group containing blah. the normal core is the largest normal subgroup contained within blah (as it is inside, it is a "core"). note that the normal and topological closure are distinct in a topological group.
yes, antihomomorphism
or "right automorphism" (also seen this term)
@anon But the normal group generated by $S$ is the union of the normal closure of $S$ over all the $g$s, yes?
So $gSg^{-1}$ is he smallest normal subgroup contianing $g$; right?
oh, I suppose I am conflating the two, when technically the normal closure does not give you a subgroup generally
@PeterTamaroff why would it be normal?
no, conjugation and normal closure are different. normal closure is the union of all conjugates.
@anon Because $gg_i Sg_i^{-1}g^{-1}$ is also in the group?
@anon Oh, OK.
20:33
@PeterTamaroff if $S$ isn't normal then $gSg^{-1}$ isn't normal
@PeterTamaroff if $x\not\in N_G(S)$ (the normalizer) then $gxSx^{-1}g^{-1}\not\in gSg^{-1}$
@anon How silly of me, I see it.
there went my nap time
@anon Naps are for the weak!
20:35
nap? its called standby :D
3
@DominicMichaelis hehehe
Hi @jacob
whats up
Tim
Tim
Any analyst willing to help?
with what
you'r advanced
user19161
@NBP Nobody calls someone else here on SE, unless they are good friends.
20:40
i cant help you
user19161
@Charlie Hello.
Tim
Tim
@user58512 The three questions starting at chat.stackexchange.com/transcript/message/8230231#8230231
Axiom: It is impossible to recharge a foutnain pen without getting stained.
sorry
user19161
@PeterTamaroff You use a fountain pen?
Tim
Tim
20:41
@user58512 I am not. My questions are lhf
@JacobBlack :D
@JacobBlack Yes, that's why I said that.
user19161
@Tim Haha, then you should ask lhf for help.
not for me I don't even know this ito stuff
Tim
Tim
@JacobBlack ha
user19161
20:42
@PeterTamaroff I use a ballpoint pen. But I usually use a pencil for math.
user19161
@Tim I don't know. Just post your question on the site.
Tim
Tim
@JacobBlack I already. I pointed to my posts on the site.
user19161
@Tim Ah, then you should wait. Coming to this chat won't help you further much.
Tim
Tim
@JacobBlack Wait, you are good at analysis, aren't you?
user19161
@Tim No, I have forgotten all my math.
Tim
Tim
20:44
@JacobBlack How come?
Your teachers would feel sad if they hear it
user19161
@Tim Because I have not touched math for a very long time. I only answer simple questions here.
NBP
NBP
@Tim, still no answer.
@Tim Where?
Oh, no clue on that @TIm
I'm an underdog here.
Tim
Tim
@NBP Did is ..., you know
Relax @tim the oompa loompas of math took the day off
user19161
20:46
@PeterTamaroff You are the boss at Spivak and Apostol!
Tim
Tim
@PeterTamaroff You are a future Field Prize winner
@JacobBlack, why dont you do advanced math now
@Tim I meant I'm no big one. I just googled undergod, it isn't what I meant =P!
user19161
@user58512 Because I am very sick.
Tim
Tim
@Charlie you are a mystery
user19161
20:47
@PeterTamaroff Yeah, I just realised too.
@Tim Why would you say that?
Tim
Tim
@PeterTamaroff well undergod is the next to god
are you going to be ok
user19161
@user58512 I don't know.
Tim
Tim
@PeterTamaroff Because Jasper Loy said so
20:48
Yes I am @tim
user19161
How many of you have pets here?
user19161
I know robjohn and Peter has a dog.
I have
Tim
Tim
have a nice day
@JacobBlack Do you have a paid job now?
user19161
20:52
@Tim No, I am not working.
Tim
Tim
I was wondering how you make a living
user19161
@Tim Well, I have people to take care of me, I have savings and I don't spend much. QED.
Tim
Tim
@JacobBlack Life is difficult for some of us. QEd
user19161
@Tim You mean for you or me?
Tim
Tim
I know it is for me. I know it may or may not be for you
QED
user19161
20:55
@Tim It is very difficult for me, in various ways.
Life is hard for everyone
Tim
Tim
Does "QED" mean "that's all. no more bothering"?
quad erat demonstrandum
user19161
@Tim My QED has no more clear meaning.
what we needed to prove
Tim
Tim
20:56
Mine does
user19161
@Charlie But for some, much more so than others.
Tim
Tim
Life is hard for everyone including mystery
user19161
@Tim Who is mystery?
Tim
Tim
@JacobBlack Whoever claims themselves to be
QED
@Tim In a good proof you know when you are done, than you don't need a QED :D
user19161
20:58
@Tim If you read my blog, you will have a small idea of what is going on, but shh...
Tim
Tim
@DominicMichaelis I like book to signal the end of proofs
So I know it is finished proven
user19161
@Tim Of course, I have deleted my blog, as I told you.
Tim
Tim
@JacobBlack Your secrets
I use tombstone, @dominic
Tim
Tim
I am starving and need to have a meal. bye
20:59
@anon FML I found that with $\{e_1,e_3,e_2 \}$ You actually get $x_1x_2x_3=x_3x_2$,$x_1x_2=x_2x_1$ and $x_1x_3=x_3x_1$
Not what I wanted.
It looks similar but it is not the same.
However $Ae_1Be_3Ce_2=(A,B,C)$ in this "multiplication"
having 2 k repu is good
finally i don'T have to say "improved formatting" everytime
NBP
NBP
@DominicMichaelis still no answer..
@NBP on which question ?
NBP
NBP
1
Q: Problem with coupling (basic probability)

NBPIf I have two probability spaces : $\\\Omega_1=\{w^1_1,w^1_2,w^1_3\}$ with $P_1$ defined to be $P_1(w^1_1)=P_1(w^1_2)=P_1(w^1_3) = 1/3$ and $\Omega_2=\{w^2_1,w^2_2,w^2_3\}$ with $P_2$ defined to be $P_2(w^2_1)=P_2(w^2_2)=1/5$ , $P_2(w^2_3)=3/5.$ I am asked to find the (or a) smallest probabilit...

@dominic congrats!
NBP
NBP
21:11
@Charlie, what for?
2122 reputation in 9 days :)
NBP
NBP
What's reputation?
the points you get if others like your questions
or your answers
NBP
NBP
nobody likes my questions appreantly
and nobody answers them ever
sry i don'T know anything about probality
NBP
NBP
21:13
it's the most basic probability concept
you got 72 reputation and someone liked your questoin already
NBP
NBP
I don't believe you haven't taken an introduction to probability theory course
Who liked my question and why
you have a 1 there don't you ?
it says someone voted for the question
NBP
NBP
but it doesn't get an answer, maybe one person liked it. I bet hundred have hated it
nope introduction to probality theory is a 4th semester course and it's my third right now
NBP
NBP
21:16
You're an undergrad?
@DominicMichaelis here it is in the first semester
NBP
NBP
I'm only just done with my first semester and and had to take introduction to probability
oh good @Charlie so you can help me?
well probabily in german probability is not so important :D
@NBP You might want to learn how stackexchange works, how reputation works and in general, how public internet forums work.
NBP
NBP
How do I learn that?
21:18
Okay, I'm sorry to be interrupting with an elementary problem, but how do I begin to integrate 2/(a+by^2) with respect to y? Its 3 am, and my head's a mess.
@NBP I'm not good at it , I read, but no clue
NBP
NBP
@Charlie, I trust you'll figure this out. I'll ask you again in 30 minutes
@MWarsi Want some help?
@mwarsi divide by a substitute and you should get something with arctan
Ah, yes, I do.
Hmm, what substitute?
21:20
@MWarsi Let me write this again
Hmm.
@MWarsi You want to "homogeneize" the equation, right?
i would set u=\frac{\sqrt{b} y}{\sqrt{a}}
Hi ,, can anyone help me with this quick problem
Show that {x} are open sets in X for all points x∈X, then all subsets of X are also open in X.
21:23
So you want $by^2$ to become a $u^2$, then you want a substitution of the form... yes, what @Dominic wrote.
@experimentX union of open sets are open
Wait wait, sorry I seem slow, but what do you mean by homogeneize the equation?
Oh, hmm.
@NBP If you trust that she can work it out in 30 minutes, why can you not in an hour?
@PeterTamaroff I integrated half of the bronstein that helps a lot :D
@DominicMichaelis is it simply saying to prove that the union of {x} is open?
21:24
@experimentX you can't prove it
NBP
NBP
@OrangeHarvester, I'm not as clever
it is the definition of a topological space
@DominicMichaelis does it mean the statement is incorrect?
Oh, wait wait.
@experimentX no it means it is a definition
21:25
Hey, I got it.
Ah, crap
you can't prove that an apple is an apple
NBP
NBP
@OrangeHarvester, what makes you think Charlie is a girl
u=\frac{\sqrt{b} y}{\sqrt{a}} <= Thanks for that.
unions of open sets must be open
@NBP cause she is one (a beatiful version )
@MWarsi i am glad i can help :)
@DominicMichaelis knowing it ... how do i approach this problem?
Show that {x} are open sets in X for all points x∈X, then all subsets of X are also open in X.
can a point itself be open in X?
21:27
@NBP No problem. Charlie can be a guy too. I thought in order to not be sexist, I would call people randomly, some by girls name and some by boys.
any subset is the union of the elements
So, occasionally, I will refer to people as him and occasionally as her.
@DominicMichaelis how do you know that, if you never saw me?
@experimentX yeah in the discret topology all points (and so all subset) are open
@Charlie i don't need to see things to know they are true :)
NBP
NBP
@Charlie, are you from Israel? You got a hebrew letter next to your name
21:28
@DominicMichaelis i see ... thank you very much for you time, could you suggest some article for reading?
@experimentX nope sry i didn't take a topology lecture till now
NBP
NBP
@OrangeHarvester, Yes to what question?
ow ... still thank you very much for your time
@NBP Yes. He is from Israel.
NBP
NBP
21:32
@OrangeHarvester, Charlie is not a common Israeli name so I don't think it's true
@NBP Neither is Orange Harvester a common people name, so may be I am not a person, but actually a fruit picker.
NBP
NBP
@OrangeHarvester, are you trolling me?
@anon OK, $e_3,e_2,e_1$ in that order fulfill the equations.
@NBP No. (I am completely serious, being a mathematician and all, humor is below me.)
NBP
NBP
@OrangeHarvester are you saying that fruit pickers are not persons?
21:36
@NBP Fruit Picker is a mechanical tool used to pick fruits (as shown in my profile photo). They cannot be persons I think.
NBP
NBP
@OrangeHarvester, a person can't pick fruits?
@NBP He can, but then he would not look like my profile pic, which is what I referred to when I said, I am a fruit picker.
NBP
NBP
@OrangeHarvester, then you're trolling me. Or you're insulting me. A Fruit Picker as you describe it would not be sentient and chat with me like this.
@NBP I can if I am clever
NBP
NBP
As afortementioned you don't have intelligence, you're not sentient so you can't be clever (or dumb).
I dislike your trolling. Please cease it
21:46
Point Noted. Now, somethings for you:
1. People can use pseudonames on this site (though some may not). The objective is to protect privacy.
2. This site is a volunteer effort, people live in all over the world, did may be in his REM sleep right now.
3. It is dangerous to give out phone numbers on internet to strangers, do not do it yourself.
4. People answer questions in their own time. (Volunteer work.) They may or may not choose to answer further than they have already done. Trying to ping them multiple times is an invasion of their privacy.
NBP
NBP
@OrangeHarvester, I'm sorry. I guess you're right (except for the phone numbers over the internet, how exactly is that dangerous?)
@OrangeHarvester, it still feels like you're trolling me.
@NBP Now, I am not trolling. I was initially before, after being pissed off at your efforts to get phone numbers. But now I am not.
NBP
NBP
@OrangeHarvester, I believe you. This list seems of more serious nature - however why were you pissed at me for trying to get phone numbers?
@NBP List is not of serious nature. We make jokes around here too.
I was pissed off because you were treating this list like some kind of support center where you expect people to respond to you in real time.
NBP
NBP
@OrangeHarvester, I'm not expecting anything, but my question is pretty basic and I've seen much more complicated question get answered in no time.
21:55
@NBP As I said, your question has to appeal to people. Most of the time, if the question is very easy, people provide only hints in order for the student to work stuff out themselves. By the time you have asked a counter question to the hint, they might have shut down their computer and gone to sleep.
NBP
NBP
@OrangeHarvester you just answered yourself why I would want their phone number.
@OrangeHarvester, how would they know that I still need help if they shut off their machine?
@GitGud what is your picture about? It reminds me on Kentucky fried chicken (i guess it's only the color)
@NBP Have you thought they might not want to help over phone? That for some, the activity is purely an internet activity?
NBP
NBP
@OrangeHarvester, they can just mention it and I'll apologize and hang up
@NBP but why? what if they do not want to be identified by their real credentials on the website? (pseudonyms)
21:58
@DominicMichaelis fried chicken is so damn good

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