Mathematics - 2012-12-07 (page 1 of 3)

robjohn

00:01

@PeterTamaroff I'm missing the reference. I get that I noted someone might have referred to me as the bane of your existence, but does that apply to Mariah Carey's existence? Of course, there might be a connection if Mariah Carey is on MSE...

Peter Sheldrick

hint: popular culture

hint: christopher nolan

user19161

Geezis, my supervisor just became a registered user and just answered some question.

robjohn

@JasperLoy Ooh... cool >8(

Simon Sheehan

00:21

@robjohn of course ;)

robjohn

@SimonSheehan Just trying to interpret...

Simon Sheehan

@robjohn yep haha. Its just the old avatar I used last year when Serverfault users were all going christmas hat avater'd

robjohn

@SimonSheehan Ah, I would have liked to have been $\color{#FF0000}{\widehat{\color{#FFA000}{\boxed{\stackrel{\stackrel{\hskip{1pt} \large\diagdown\hskip{6pt}\diagup} {\huge\bullet\hskip{7pt}\huge\bullet}} {\hskip{-2pt}\huge_\phantom{\tiny }\frown_\phantom{\tiny }}}}}}$

Mean Square Hat

Simon Sheehan

@robjohn that appears to be... a crazy bit of text haha :P

Argon

Hi @peoplepower!

robjohn

00:30

@SimonSheehan Do you have the ChatJax bookmarklet installed?

peoplepower

@Argon Why hello there!

Simon Sheehan

@robjohn I would say nope :p

robjohn

@SimonSheehan Look here

Simon Sheehan

there we go! dandy.

robjohn

@SimonSheehan That makes the text mean something :-)

Simon Sheehan

00:33

@robjohn definitely haha, much better.

robjohn

@SimonSheehan The SE gods opted MSE out of the hat thing this year, so we don't get hats.

Simon Sheehan

@robjohn darn :(

robjohn

@SimonSheehan Evidently, they don't think the math people are fun.

Simon Sheehan

@robjohn math is some very serious business.

robjohn

@SimonSheehan but there are some fun people here (and our share of jerks)

not naming anyone

Simon Sheehan

00:41

@robjohn probably happens everywhere ;)

Peter Tamaroff

00:59

@robjohn "I am the math.SE"

user57925

Hello, let G(n) be the statement that every sufficiently large number is the sum of at most n primes. Can we prove G(n) for some n like 10000 using elementary reasoning from prime number theorem?

sea turtles

I don't feel like PNT is sharp enough for that sort of corollary.

user19161

@seaturtles The great anon!

sea turtles

My intuition says that PNT is powerful enough to create theorems about primes involving the idea of asymptotic density equal to 0 or 1, but not so powerful as to create theorems involving the idea of sets being cofinite in the naturals.

Peter Tamaroff

" it is very clear that the denominator explodes" @Argon dafuq?

Argon

01:06

@PeterTamaroff What, "exploding"?

sea turtles

explosion = rapid growth

robjohn

@sunflower I believe that since the convolution of $\frac1{\log(n)}$ with itself is $>1$ sufficiently far from $0$, we get that probabilistically, G(2) (the binary Goldbach conjecture) is true.

user57925

thanks

sea turtles

a theorem being probabilistically true is good motivation and background for proving it true

@robjohn of course, the sum 1/log(n) is divergent, so we would need to normalize the convolution - does it still approach 1 in the limit?

user57925

what do you do if you want to learn the mathematics from some paper but it's in a language you don't know?

sea turtles

01:10

you learn the subject the paper is about first

robjohn

@seaturtles The convolution does not grow as fast as the sum, but I believe it blows up at infinity

sea turtles

oops, I misread your language question sunflower

@robjohn So $$\displaystyle\sum_{\ell=2}^{n-1}\frac{1}{\log(\ell)\log(n-\ell)}\sim\left(\sum_{\ell=2}^{n-1}\frac{1}{\log \ell}\right)^2~?$$

user19161

Ladies and gentlemen, I have capped today, thanks for your support!

robjohn

@seaturtles I think it is $\frac1n$ times that. $\sim\dfrac{n}{\log(n)^2}$

Argon

Np.

I mean...

:)

robjohn

01:18

@seaturtles For most of the sum, the summand is very close to $\frac1{\log(n)^2}$ for large $n$

user57925

terrytao.wordpress.com/2012/02/01/…

user57925

> on the assumption of the GRH, the full odd Goldbach conjecture is known to be true; this is a result of Deshouillers, Effinger, te Riele, and Zinoviev

user19161

01:34

Hey @amwhy busy answering questions? =)

user57925

why does it say quadratic residue is like a random walk?

user19161

Ah 230 with cap and 2 accepts, a very good day...

user19161

Over and out!

Argon

02:03

@Limitless Hi!

Limitless

@Argon Hi! I have no ability for intellectual conversation right now. But you're cool, and I like you. So, hi.

Argon

Hahahaha!

What's up?

Limitless

I just risked social suicide and public ostrasization from my peers.

So there's that.

And

Taco Bell is really good.

Argon

...

sea turtles

so, a typical day

Limitless

02:07

It doesn't matter, though, because my mother and my woman love me.

Argon

"She"

Limitless

Indeed.

All I need are those two things and the actualization of my physical needs.

user972276

hello, I had a question about this form. Would someone be able to help me?

sea turtles

it is generally preferred that users just ask rather than ask to ask first. although empirically you might have better results being uberpolite.

Limitless

@Argon How's your maths and life?

@seaturtles I like you.

Was that an intentional joke on the ubermensch?

Argon

02:11

@Limitless Both are fine. Not particularly good nor bad.

sea turtles

uber means very

Limitless

@seaturtles I know, but I was thinking of Nietzsche.

sea turtles

it is common in English to put in front of arbitrary words for extra effect

Limitless

I thought you were making some sort of clever and witty philosophical joke.

sea turtles

I do not see the connection between the word polite and Nietzsche

Argon

02:12

Daas auto

Limitless

ubermensch; uberpolite. Essentially politeness to the point of transcending politeness just as an ubermensch personifies the transcending of humanity.

user972276

I asked a question the other day and got a prompt response but now I am looking abck over the answer and dont understand part of it or would like clarification. Do I need to "reask" the question or is there some way in contacting the person who answered it?

over* not abck lol

user57925

@user972276, what is the question

Limitless

@user972276 Comment on the answer.

sea turtles

@Limitless along these lines, every single usage of the prefix uber would be an allusion to nietzsche, no?

Limitless

02:13

@seaturtles I never said that I am not crazy. :-)

sea turtles

now that is something the jasps would say

the blue square

Limitless

Jasper and me are very similar. I like him. @JasperLoy I'm talking about you; do you feel your ears burning?

user972276

math.stackexchange.com/questions/251233/… its a norm equivalence problem

Limitless

@user972276 Sorry. Linear Algebra hasn't hit me in the face yet, and I skipped it to study Abstract Algebra.

sea turtles

I wonder: in terms of the multiplicities of irreps as summands in the reps V and W, what is the image of hom(V,W)⊗hom(W,V) in hom(V,V) under the composition map?

@user972276 Of course there is a way to contact the answerer - you comment on the answer!

Limitless

02:16

@seaturtles Sorry, but I have no clue.

sea turtles

If you comment on their answer, they will get a "ping" in their inbox.

Limitless

Why do you sound so much like anon?

user972276

oh ok

sea turtles

@Limitless Huh, I wonder.

user972276

I was wondering if they would

Limitless

02:17

Maybe it's because anon often goes completely over my head.

Argon

Maybe there is another reason too...

Limitless

Representation theory is some extreme stuff.

user972276

I tried that on another question like 30 min after they asked and I got no response back so I didnt know if that worked

Limitless

@Argon IS HE SECERETLTTLY ANON? (Spelling be damned.)

sea turtles

23 hours ago, by anon

user57925

02:18

what's that picture of?

Argon

^^

sea turtles

@sunflower Huh, I wonder.

Argon

Note who is quoted...

Limitless

@seaturtles Why do you have two accounts, if I may ask?

sea turtles

More than two. For fun.

user57925

02:19

amazon.com/Sea-Turtle-Mosaic-Hanging-Spectacular/dp/B003C7EKZY/…

Argon

@Limitless Read any good books lately or anything?

You seems like you would read interesting stuff

Limitless

@Argon SOON: Princeton's Companion to Mathematics.

Gladwell's Outliers is a recent one.

Paul R. Halmos [sic] Automathiography

(I am completely drained intellectually. Sorry for the misspellings.)

A Mathematical Misclenny (J.E. Littlewood)

user57925

Miscellany

Limitless

@sunflower Thanks.

there's another one

It's on my Ubuntu partition. I can't look it up immediately.

Also Fifty Shades of Grey sometimes.

Argon

Hahaha

Limitless

02:25

I'm a dick when it comes to literature.

At one point, I thought Dante Alighieri was an idiot.

Something you have to read: Dr. Faustus (Christopher Marlowe)

Letters to A Young Mathematician (Ian Stewart)

The Republic is something I still haven't been able to sit down and read. It's one of those books I'd have to write a dissertation on to properly consume.

Argon

Doctor Faustus?

Limitless

@Argon It is a classical philosophical myth about the obsession with knowledge and black magic.

It is much like the Myth of Sisyphus in that it is philosophically . . . I can't explain what I'm thinking. Too tired.

Argon

Long day?

Limitless

@Argon I talked with two people with Masters in Psychiatry and Psychology, a math professor with a Masters in Mathematics, and I had to deal with about five different personal things which involved my social life.

I also had to lead a team of 8 people (including myself).

I don't have a headache right now because there's not enough room in my brain to feel tense. (In retrospect, this makes no sense.)

user57925

what personal social life things?

user57925

02:31

it makes perfect sense

user19161

@limitless Your answer on the equivalence does not make sense to me...

Limitless

@sunflower Admitting my primary flaw as a human being publicly, talking to several women and apologizing for sexually and psychologically using them, removing one woman from my life for the rest of my life, arranging a meeting with my therapist to arrange a meeting with a teacher, elucidating the aforementioned equivalence relation answer (with the help of said Masters in Mathematics), . . . I'm writing a book.

@JasperLoy I am sorry.

user57925

that sounds really tough what did you do that was considered using them?

Limitless

@sunflower Lots of lying. I told them I loved them and I implicated that I cared about them in ways that I did not. I had sexual experiences with some of them and I put them into positions where they would have sexual experiences with me if I wanted them to.

user57925

are you sure you were lying!

Limitless

02:35

@JasperLoy Let's discuss that answer tomorrow afternoon. I will have time to calm down and get things straight.

@sunflower 100%.

user57925

oh well that's good you dealt with it

user19161

@Limitless OK. In the meantime I will continue to ponder on something mysterious, perhaps I might email you to tell you...

Limitless

@JasperLoy Please do! I adore being your friend. You are important to me.

user57925

(although I think this is sort of the normal way that people to act, lying etc. - not taking part in it is quite honourable)

Limitless

Also, since you're not a female, this isn't an attempt to get into your pants! :-)

@sunflower The behavior I exhibited was bordering on psychopathy.

Argon

02:37

Geez :)

user57925

According to who?

user19161

@Limitless Even if it is, it's fine. What's wrong with trying to find a bf/gf online?

Limitless

@sunflower Myself. I study psychology quite extensively and I've applied psychological manipulation to people without even knowing it.

sea turtles

People do that naturally without studying psychology (as the academic subject).

Limitless

@seaturtles Good point.

@JasperLoy I am glad you're morally ambiguous like me.

user19161

02:38

I don't manipulate people, I consciously avoid my subconscious evils. I am different.

user57925

can't you just view everything as "psycopathy" and "manipulation" though? Like dressing smartly is a sociopathical device to manipulate people into believing you are more reliable than you really are

user19161

Yes, I know you will say that is what everyone will say but I am truly different, and most people are in no position to judge me at all.

Limitless

@sunflower No. It isn't that simple.

@JasperLoy I don't question you. I do not judge.

user19161

I have given up on trying to make the world understand me, like I said before, I don't think I belong to this world.

user19161

@Limitless I don't know what you mean by morally ambiguous there.

Argon

02:40

We all judge, whether we mean it or not.

Limitless

@sunflower It is things like . . . Completely turning a woman's view of a man in the completely opposite direction of how she feels in an attempt to take control of her mind and replace the man with yourself.

Argon

@JasperLoy Middle Earth, anybody? Isengard?

user57925

i see

user19161

@Argon Yes, he who says don't judge is a bullshitter. But to put things into context, we should judge people based on careful observation and introspection and not otherwise.

Limitless

@JasperLoy I'm an approximate bullshitter, I guess.

user57925

02:41

are all these women so weak they can't make decisions for themselves? maybe you're just quite attractive and nice

user19161

So that is the real meaning of "don't judge others" ie don't jump to conclusions hastily. QED.

Limitless

@sunflower Things such as that are prolonged, perverse, and extremely damaging to parties involved.

user57925

it just sounds like you're taking all the blame by assigning yourself as some super powerful social engineer

Limitless

@sunflower I know that's how it sounds . . . because that's exactly what it is.

user57925

ok

user19161

02:43

@limit I am disturbed you call yourself a psychopath, I will talk more to you via email to find out. Perhaps it is not what you think it is.

Limitless

@JasperLoy I don't and haven't called myself a psychopath.

I'm not a psychopath.

I am sorry for conveying that. It is just that I mean that my behavior is sometimes psychopathic.

user19161

@Limitless Well, you said "bordering on psychopathy" so roughly the same meaning.

Argon

"Psychopathy is a personality disorder that has been variously described as characterized by shallow emotions (in particular reduced fear), stress tolerance, lacking empathy, coldheartedness, egocentricity, superficial charm, manipulativeness, irresponsibility, impulsivity, criminality, antisocial behaviors such as lacking guilt and living a parasitic lifestyle."

This description doesn't seem to follow what I "know" about you...

Limitless

@JasperLoy Sorry, I must've been exaggerating. I meant that there are some psychopathic traits in my behavior (very few), and that it has potential to become psychopathic behavior. In no way will I become a psychopath.

@Argon Understandably, because it's not who I am. In my life, I have dealt with some of those issues, however. In particular: stress tolerance, shallow emotions, lacking empathy, coldheartedness, egocentricity, superficial charm, manipulativeness, and lacking guilt/remorse.

Argon

@Limitless You just apologized for lying - something very few would do. That knocks off a few of those adjectives right there.

Limitless

02:48

@Argon Yes.

I have, I think, successfully dealt with most of those: shallow emotions, lacking empathy, coldheartedness (eh), egocentricity, superficial charm, and lacking guilt/remorse.

sea turtles

@Argon Or maybe it emphasizes manipulativeness.

user57925

hehe

Argon

@seaturtles Well, why did you do it?

sea turtles

The lulz.

Argon

For a reaction?

user57925

02:50

@seaturtles, that reminds me of youtube.com/watch?v=A6aCir5bu-c

sea turtles

I have no idea what you're asking.

Limitless

@seaturtles I'm not trolling.

Argon

@seaturtles :)

Limitless

Regardless, you're all welcome to judge whether or not I portray the things I've dealt with.

I appreciate the fact you all have the interest in talking to me about this.

sea turtles

the Internet Diagnosis Brigade is everywhere

Limitless

02:51

lololol.

@seaturtles You've been around the interwebs, haven't you?

Argon

sea turtles

no, you're confusing the IDB with the whaaaambulance.

Limitless

Anon has established he or she is a /b/tard in disguise.

sea turtles

Disguise? With the alias "anon"?

Argon

OH NOES!

sea turtles

02:53

Also 4chan =! /b/

Limitless

@seaturtles I have always suspected it.

There is something about you that reeks of interwebz.

@seaturtles You do not approve of my rug sweeping?

sea turtles

My approval rating for it is between "no-no" and "meh."

Limitless

I will accept that.

user57925

4chan has a lot of different boards

Limitless

@seaturtles THE RUG IS SO PRETTY, THOUGH.

I am going to bed.

Or some where.

Argon

03:00

Good night

Limitless

Good night to all, and love to all.

@JasperLoy We will discuss my rug tomorrow. I hope so, anyway.

sea turtles

Your rug, huh.

user19161

03:25

I now have the algebra-precalculus and homework badges. That means I am a rep whore.

user19161

@argon

Argon

@JasperLoy

@JasperLoy Or you are a boss at precalculus.

And homework

user19161

@Argon I am only a banana. I have been thinking about what you said in the email. Well I guess time will tell...

user19161

@rob Did I tell you that I capped already today? =)

Peter Sheldrick

03:47

hmm what is the formula for this number sequence
first 2 terms 6,3
then 3 terms 24, 12, 4
then 4 terms 120, 60, 20, 5

n!/1, n!/2.... gives
6, 3
24, 12, 8
120, 60, 40, 30

anon

n!/k!

Peter Sheldrick

nice thanks

user19161

The great anon speaks and his words are too important to be hindered by dollars.

Peter Sheldrick

plain text still is easier to type...

user19161

The small banana speaks and his words are too unimportant to be decorated by dollars.

Peter Sheldrick

03:53

wow fuck off

anon

@PeterSheldrick Jasper = banana

not you

Peter Sheldrick

fair enough

inception: youtube.com/watch?v=Z0kGAz6HYM8

user19161

Ooh, I just realised that Peter=dollars!!!

Peter Sheldrick

O_o

anon

¿

user19161

04:05

I wonder where sea turtles went to, must have gone to visit anon.

user19161

Wow, I actually enjoy typing one-line answers to ten-line questions.

user19161

04:26

Haha @amwhy I just saw your logic answer!!! Also, why have you been so quiet?

amWhy

@JasperLoy Hey, Jasper! Yes, I've been quiet...just having a rough time of it...

user19161

@amWhy Oh did you get my email address? Just checking...

amWhy

I got your "secret message" by the way, so I will be in touch!

user19161

@amWhy OK! Now back to rep whoring!

amWhy

@JasperLoy Oh, yeah, I saw TonyK's comment. Jerk!

user19161

04:29

@amWhy Well he and I like to exchange interesting comments. We have a history of amusing each other in our comments!

amWhy

@JasperLoy Ahhh, I see! that makes sense. I get a few off-the-cuff cuts occasionally. Other than that, I sense that at certain times of the day, it seems I ( and my answers) are dismissed. Maybe those just happen to be "slow times."!

user19161

@amWhy Well, you can just leave your answers there. I will take care of them all eventually. =)

amWhy

@JasperLoy hahahaha...! I've got your back, too!

@JasperLoy btw, I recognized your user name when you changed it. I take it the former was short-lived?

user19161

@amWhy Well, I have changed it a few times before for fun. I will try to stick to the current one now.

user19161

@amWhy Also, since you like the steelblue, I will try to stick to it too!

amWhy

04:38

@JasperLoy Yay! ;-)

@JasperLoy I'm thinking of going with A-M-WHY ... small change, but more revealing!

user19161

@amWhy Why not just use Amy? You don't have to add the last name if you want more privacy!

amWhy

@JasperLoy I'll think about it. ;-)

Каднон Мстакуи

04:59

Привет

Ты здесь?

Никто не здесь?

До свидания

robjohn

05:36

@JasperLoy :-p

Martin Sleziak

06:19

@КаднонМстакуи Have you seen my comment related to your suggested edits?

It is better to avoid bumping too may old questions in short timespan.

Peter Sheldrick

06:42

how do i get to the latex sandbox - or how do i deactivate instant rendering (my browser slows down)...

user19161

I am going to take a nap and then go out for a walk tonight.

N3buchadnezzar

08:02

Hey @OldJohn

Old John

@N3buchadnezzar HI

N3buchadnezzar

@OldJohn I am having problems understanding things =/

Old John

@N3buchadnezzar anything I can help with?

N3buchadnezzar

Maybe, no calculations. Just understand some formula..

3D projection

3D projection is any method of mapping three-dimensional points to a two-dimensional plane. As most current methods for displaying graphical data are based on planar two-dimensional media, the use of this type of projection is widespread, especially in computer graphics, engineering and drafting. Orthographic projection When the human eye looks at a scene, objects in the distance appear smaller than objects close by. Orthographic projection ignores this effect to allow the creation of to-scale drawings for construction and engineering. Orthographic projections are a small set of tran...

Say, I want to rotate a 3d unitary cube. Eg vertices (0,0,0), (1,0,0), (0,1,0), (1,1,0), (0,0,1), (1,0,1), (0,1,1), (1,1,1).

Old John

ok ...

N3buchadnezzar

08:07

@OldJohn Easy enough right? The problem, is that I only have support for two dimensions!

Old John

@N3buchadnezzar Hmm - what exactly do you mean by "only have support for ..."?

N3buchadnezzar

@OldJohn Just the xy plane, no z dimension.

So I thought I could just use the formula given, but I do not understand what to put in for $e_{x,y,z}$ and $a_{x,y,z}$ or $c_{x,y,z}$..

Old John

no - I mean ... what do you mean by "support for"?

for a rotation in 3D, I think you have to do the calculations in 3D and then project into 2D after the rotation

N3buchadnezzar

Yeah, there is a formula there for doing that

I need to visually be able to rotate a cube using jaw, pitch and fork. (along all the axis), but in a 2d environment. Is this clearer?

But like I said, I do not understand what to put into the formula.

Old John

Hmm - you can't rotate a 3-d cube in a 2-d environment ... you have to do it all in 3-d

N3buchadnezzar

08:11

$$ \begin{bmatrix}
\mathbf{d}_x \\
\mathbf{d}_y \\
\mathbf{d}_z \\
\end{bmatrix}=\begin{bmatrix}
1 & 0 & 0 \\
0 & {\cos \mathbf{\theta}_x } & { - \sin \mathbf{\theta}_x } \\
0 & { \sin \mathbf{\theta}_x } & { \cos \mathbf{\theta}_x } \\
\end{bmatrix}\begin{bmatrix}
{ \cos \mathbf{\theta}_y } & 0 & { \sin \mathbf{\theta}_y } \\
0 & 1 & 0 \\
{ - \sin \mathbf{\theta}_y } & 0 & { \cos \mathbf{\theta}_y } \\
\end{bmatrix}\begin{bmatrix}
{ \cos \mathbf{\theta}_z } & { - \sin \mathbf{\theta}_z } & 0 \\

@OldJohn Yes, and than translate that into 2d, I know =)

Each of the matrices, represent a rotation along a single axis. But again, what is $a$, what is $c$, and what is $e$?

Old John

@N3buchadnezzar C is the 3-d position of the camera

N3buchadnezzar

And $a$ is the point to be rotated?

Old John

A is the point that is being projected - you would need to take A to be one of the corners of the cube - and do the calculation 8 times

N3buchadnezzar

Yeah, that is no problem having matlab and maple avaible. I guess $$c = \langle 0,0,1\rangle$$ should be fine.

Old John

not sure that taking the camera at one corner of the cube is the best idea :)

but probably ok

N3buchadnezzar

08:18

Hmm, still do know know the difference between c and e..

Old John

so - then $d_x,d_y,d_z$ gives the position after rotation - and then you calculate the 2-dim projection at he end from the $d_x,d_y,d_z$

Hmm - it says " the viewer's position relative to the display surface."

N3buchadnezzar

Yes, which makes no sense to me :p

Old John

$e$ only comes into the final projection - it is not involved in the rotation

it says "The distance of the viewer from the display surface, $e_z$, directly relates to the field of view,"

so it is a sort of scale factor making things look smaller when you are further away from the projection screen, I think

have to go - kitchen fitters have arrived :(

N3buchadnezzar

@OldJohn Cya! Will show you an image whenever i figure out things

Peter Sheldrick

just made my first double question (posted to both math-stackexchange and overflow - it's my first overflow question!)

anon

08:33

Ill-advised.

Cross-posting is frowned upon at MO unless it isn't done until the question has already received attention but little progress on MSE.

Peter Sheldrick

oh...

anon

I tell you this because I and many others learn this the hard way.

Peter Sheldrick

i read somewhere overflow was more for research stuff

anon

Correct.

Peter Sheldrick

and stackexchange more in direction of homework stuff

on the whole

anon

08:35

Well, homework-level is the norm on MSE, but there is no official policy on what level of questions are preferred here.

(There are various research-level questions here, too, they are just rarer.)

It is a nice question though. I wonder how you came to the proposed formula.

Peter Sheldrick

i took the matrix A from my question here math.stackexchange.com/questions/52039/… that has as roots the roots of those polynomials p, it happens to diagonalize with the vandermonde matrix of the roots (since it is a kind of companion matrix) and used this formula de.wikipedia.org/wiki/Vandermonde-Matrix#Weitere_Eigenschaften to invert the vandermonde matrix

it produces bernoulli polynomail coefficients, but the constant term of a bernoulli polynomial is always a bernoulli number so i threw away everything except that value from the nth power of A

'it produces...' - the powers of the matrix A applied to e=[1 0 0 ...]' produces...

Jayesh Badwaik

@PeterSheldrick I have a doubt in that question, you say at a place that
The polynomial $p_n$ is defined as follows.

$$t_n(x) = \sum_{k=0}^{n+2} \frac{x^k}{k!} -1$$

is the truncated taylor polynomial of $\exp-1$ to power $n+2$.

Where is $p_n$?

Peter Sheldrick

next line...

hmm that is a confusing way to put it, but i went along with it...

Jayesh Badwaik

okay, on first reading, it looks like that is what you want to prove. (If... then)

hmm

Peter Sheldrick

p is just the reciprocal of that...

the roots stay the same and since only p' appears in the formula maybe that is a thing that is appropriate to simplify

er...

not stay the same they go to 1/z

but that doesn't make the formula more complex

fingers crossed this isn't such a dud as my last question (the response from math stackexchange was positive but the question turned out to be smoke and mirrors)

oh found a mistake

small one

anon

09:06

maple = dumb as bricks

RobinHood

=IF(ISNUMBER(A5),AVERAGE(RANK(A5,$A$3:$A$8,0),RANK(A5,$A$3:$A$8,0)+COUNTIF($A$3:‌$A$8,A5)-1),"")

wanna achieve opposite of ^. means highest values get lowest rank

Chris's sister

Hi

I think that the limit tends to infinity, but not sure how to make this point rigorous $\lim_{n\to\infty} \int_0^{2 \pi} \frac{1}{x+\sin^n x+ \cos^n x} \ dx$.

anon

you might as well cut off all but (0,eps).

actually, there's zeros of the denominator that need to be accounted for I guess

Jayesh Badwaik

Sorry, misread the question.

anon

bounding sin^n+cos^n by constants will not help methinks

Jayesh Badwaik

09:14

@anon yes it won't.... my bad...

Chris's sister

@anon: I think so.

anon

can anybody tell me how to get the eval's working in maple (see pic above)?

Chris's sister

@JayeshBadwaik: I also thought of that point but it doesn't seem to help.

anon

it's taunting me by numerically evaluating sqrt(2) and pi/2 but not the integral.

Jayesh Badwaik

@Chris'ssister it doesn't, i misread the limits in the question.

@anon sorry, no maple experience here....

RobinHood

09:49

I m at right place for my query?

Jayesh Badwaik

you are, but your query was barely understandable...

also I am not sure if it is a programming query or a mathematical one

RobinHood

its xcel formula, for calculating rank correlation coefficient

same like this but I want to assign values in reverse order to D & E column

Jayesh Badwaik

hmm, i don't know much excel unfortunately...
also looks as if you want to ask about the writing the excel formula...
better clarify if that is the case...

I wonder if there is a excel.se

or may be you can ask on stackoverflow.com

user19161

@JayeshBadwaik Super User rather.

Jayesh Badwaik

@JasperLoy superuser is about the software, not programming I guess.

RobinHood

09:58

and stackoverflow too

thats why I bring here, anyway, will dig google

thanks for you time

Jayesh Badwaik

stackoverflow IS for programming.

your question is on-topic there...
though how many excel users roam on the interweb is something I am not sure of

Peter Sheldrick

10:18

excel is great for numerically investigating tabulated data - so actually there is a big overlap with array programming languages such as fortran, matlab or R

much lighter on the user of course

and very immediate

anon

maple must be an AI programmed to be ultra passive aggressive

Peter Sheldrick

well, there are plenty of alternatives to turn to if it isn't playing nice!

anon

no there aren't. my homework must be done in maple, per its rules.

otherwise I wouldn't bother.

Peter Sheldrick

oh...

i used maple a few years back and it was really nice - especially the plotting

i used it on a university computer... that's the problem with such proprietary software - it is so hard to get your hands on... that's not important to them tough probably...

Peter Sheldrick

10:52

unless you pirate it youtube.com/watch?v=GML-Mu1EKvg

Charlie

@JayeshBadwaik Hi

Jayesh Badwaik

@Charlie Hey hi! Wassup?

Charlie

@JayeshBadwaik I'm fine...

@JayeshBadwaik And you?

Jayesh Badwaik

@Charlie I'm good. Best luck for exam. when is it?

or is it already over?

Charlie

@JayeshBadwaik one hour from now

Transcript for

$Mathematics$ Mathematics