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user19161
00:00
@emack DO you use emacs???
@WillHunting his user name is part of his real name
he already explained
:)
user19161
@Charlie Oh, I wasn't here then.
Yes, it is part of my name: Eli Mackenzie
user19161
HAHAHAHA
Don't you just wanna kill people who sleep during lectures?
user19161
00:04
You can sleep as long as you are not the lecturer.
user19161
Also, they might not be sleeping but thinking deeply like Erdos.
it's impolite
user19161
He often closed his eyes to think of the solution to a problem at a talk.
user19161
Often he would find the solution by the end of the talk.
user19161
@Charlie impolite
00:05
@WillHunting but if one is snoring...
user19161
Nah, it's not impolite, just don't distract others.
@WillHunting :)
@WillHunting yes it is
user19161
A lot of courtesy in this world is superficial.
and annoying
user19161
Man has replaced true empathy with superficial acts of courtesy,
00:06
couldn't pay attention with that noise
user19161
FOr example, shaking hands. I don't shake hands.
@WillHunting I like shaking hands
user19161
Firstly I have sweaty palms so I don't do it.
user19161
Secondly I find it quite a silly meaningless act.
@WillHunting i don't think so
you feel the person
look into one's eyes
user19161
00:09
Haha, you know I usually don't look into the person's eyes directly for too long.
user19161
That's because my brain waves are too powerful so I feel overwhelmed when I do that.
@WillHunting ha ha...
user19161
I think argon went for dinner...
probably
user19161
I am hiding in his food.
00:12
hahahaha
you could have a dinner with anon
user19161
HAHAHA, maybe next time when I go there.
user19161
We can both have vanilla ice cream =)))
i like vanilla ice cream
user19161
Speaking of ice cream, I once had a conversation with my best friend about ice cream.
00:16
then?
Hmm - is MSE misbehaving for anyone else>
user19161
We were wondering why there is vanilla strawberry and chocolate flavours.
user19161
@OldJohn Yes, disappears right?
yep - no questions :(
user19161
And I think I said something like well, it just happened that way, those flavours.
00:18
@WillHunting ?
user19161
@Charlie THat's all.
hmm
i like frozen yogurt
user19161
The point is that sometimes things happen in an arbitrary manner and then they become stuck.
again: ?
user19161
HAHA, this is deep stuff man. =)
00:20
LOL
user19161
You know, looking at ice cream you see why the world is the way it is.
are you high while you do this?
user19161
Sometimes people start doing things in a certain way in a society.
user19161
THen after that inertia takes over and then people just keep doing things that way.
user19161
00:23
THat's how cultures form. That's why it is hard for people to change.
hmmm
user19161
So the point is, if somehow it was not strawberry vanilla and chocolate ice cream but something else, then we would have something else as the more common flavours today.
I always think about you when i see these things
user19161
@Charlie No, I think of such things all the time...
@WillHunting ok
i like to try new ice cream flavors
don't you, @will ?
user19161
00:29
@Charlie Well, I don't really eat ice cream nowadays. But I like to stick to things I like.
@WillHunting comfortable zone
user19161
@Charlie Rather, you can call it faithful. Isn't that great?
hmm meh
or accommodated
user19161
For example, before I chose TeXworks, I tried out like 10 editors.
user19161
After that I just stick to it.
00:31
yes, we stick to what we like. fair
user19161
You know, some people can get so drunk that they walk through glass doors!
yes...
user19161
Then the glass breaks and they kind of look a little surprised. My mum saw it before, hahaha
"sae" ?
I lost 96 points to a removed user. Now I wonder whether dear departed downvoted me twice or I him four times.
00:39
@HenningMakholm aah - such imponderables - and it seems we cannot identify the dear departed user at all :(
Bye again boys... sleep is coming..
see you tomorrow
@Charlie bye!
Bye!
@WillHunting Please go to bed.
00:56
Hmm, the user previously known as J.D. seems to have disappeared within the last about 70 days.
@HenningMakholm Jasper Loy?
@GarbageCollector No, I don't think he's ever called himself J.D. And he's still here as far as I can see.
@HenningMakholm OK. Thanks. :-)
01:35
Hello. If I want to find lagrange multiplier of f(x,y,z) given the only constraint is -5<x<5 how would one go about setting that up. I know how to do it if the constraint was in a function form... Or how to I turn that interval constraints in to a function form ?
 
1 hour later…
02:41
-105 user was removed.
FML
02:57
i have no idea what these commenters want me to explain math.stackexchange.com/a/233766/1284
i already explained why i downvoted and how i feel about the issue now
it was because of my opinion, contraindicated by best practices, i wouldn't have downvoted had i known what i know now, but i'm not sorry about having done so. what else is there to say?
03:11
well i retorted but now i feel slightly petty.
one of the various reasons i'm not sorry is that i think it's best to hold higher-rep users to a higher standard.
03:56
@DanBrumleve <<<<<<<<<<<<<<<<<<<<<<<<t
The downvotes are not called for.
I think you misinterpreted the question.
i understand that now.
err i understand that they weren't called for.
i don't believe i misinterpreted the question.
although i understand now that others have a different and perhaps valid interpretation of the question.
i only say "perhaps" because OP hasn't chimed in, other than to accept an answer.
I mean, if we know the error is $0.0000000000000000000000XYZ$ then we have those many zeroes accounting for correct decimals.
maybe you aren't understanding my point.
03:59
What is your point?
if many of those trailing 0s correspond to 9s in the partial sum, then we can't use stirling's formula to bound the number of terms that have to be added. i tried to explain my point in different comments.
OP asks "Is it possible to predict how many correct decimal places I get when I stop summing at n terms?"
Well, you need to use a better version of Stirling, that's all.
i am actually reaching a bit when i say "no" but i edited to clarify as probably not.
maybe.
how do you know that the number of consecutive 9s at position n of of the decimal expansion of e doesn't exceed n/2 an infinite number of times?
Huh?
I gotta go
cya check out the thread another time
that's slightly off from what i am saying but maybe close enough.
is the worst case running time of any digit-extraction algorithm for e even known? i am claiming it is not unless one makes assumptions akin to e is normal.
also @Peter i didn't downvote @robjohn's answer, it was somebody else, but i downvoted all the others.
and on the "no-effort-expended" front, the other answers are textbook answers to textbook questions, but the question is not a textbook question. robjohn may be correct about the first common meaning but i didn't know that and i wouldn't expect any undergraduate to.
interpreting the question as an easier version of itself is morally equivalent to a full homework solution, imho.
 
2 hours later…
05:56
and i retorted in the thread concerning "egregious and dangerous".
is any worst case running time of the bbp pi digit-extraction algorithm known?
06:19
hi @anon
07:10
i hope i am right to expect my character not to be questioned when i acknowledge that i was wrong and still refuse to repent. i know there are best practices outlined in the faq or whatever but this isn't a church right?
07:43
nice question math.stackexchange.com/questions/234046/… somebody must have
08:12
what's up @JonahSinick nice to see another user from my town
@GerryMyerson short and succinct and slightly steganographic and surely satisfactory as usual math.stackexchange.com/questions/234056/…
08:53
seriously i hope nobody here is bowing down to ZFC every hour. not trying to start a religious war or anything just saying we should accept all viewpoints right?
should we then accept the viewpoint that not all viewpoints should be accepted?
2
whoa too meta. but i guess mathematicians should be careful to distinguish our rightly held beliefs from what we can actually prove.
and that extends to the fluidity of language.
09:12
dunno why i'm so picky today chat.stackexchange.com/rooms/6387/…
09:25
anyone? anyone? @skullpatrol?
09:35
@DanBrumleve sorry, I just tried the link
@DanBrumleve my son sent me that link a few days ago.
ha ha
that link covers everything i've been saying on this nitpicky day.
user19161
09:47
@PeterTamaroff HAHAHAHA, sad panda. Clearly this user likes you a lot. I only lost 30.
user19161
@DanBrumleve I remember you downvoted me, yes. =)
just been exploring the power i still have a 2-digit U/D ratio.
user19161
@anon Well said bro, well said.
if my D/U ratio were irrational you'd best be really scared.
user19161
I ain't scared of such things. I have been through hell you know.
user19161
09:54
@robjohn Does he happen to be a user on MSE as well?
@WillHunting not that I know of.
user19161
@robjohn Hehe, I saw a Joe Johnson and thought that might be him. =)
@WillHunting that wouldn't be him.
:) my son is 2 i'm not completely sure either.
user19161
@DanBrumleve Hmm, let me look for "2 year old"...
09:56
he has successfully purchased ipad apps.
i think he got away with it because the authentication state is cached for some time.
@DanBrumleve and a 45 foot yacht...
user19161
Anyway, these SE maintenances are kind of weird. For once a month or so, I can't log in for hours.
user19161
That doesn't happen to gmail or other popular sites.
user19161
Hmm, maybe they have less servers or something like that.
we hope the best for our children whether or not we expect it.
user19161
10:02
Yes, yes. My children are in my underwear.
@WillHunting and you tuck them in before bed each night...
user19161
@robjohn HAHAHAHAHAHA
user19161
How come no one is flagging all this shit?
my baby sleeps. no SE problems here but i have a persistent gmail problem and today i realized that restarting chrome fixes it so i'm embarrassed by having complained to IT.
@Will we are thinking on a higher level.
user19161
Well, I just mean that there are many flags in this room. I think it is second after the gaming room.
user19161
10:05
I am partly the culprit here. I said many things which were flagged. I kind of remember all of them. =)
user19161
I remember I, Jonas, and n3b were each suspended once from chat. =)
user19161
I don't think I will even get married this lifetime, but if I do I don't think I wanna have kids.
i am under control i think. flagged myself once last week. i have taken offense in the past but with some experience i am more chill.
which is essentially why i decline to interdict in math.stackexchange.com/questions/234086/…
i would like to say it is a surreal or an ordinal or something but i don't want to push the issue.
10:20
Hello
hi @robjohn, I have a short question, do you know about Kalwankar-Gangal local fractional derivative? If yes, is it true that it is zero for differentiable functions? (I can't see it directly from definition)
@robjohn it is defined as $\frac{d^{\alpha}}{dx^{\alpha}} f(x)|_{x=y} = \frac{1}{\Gamma(1-\alpha)} \lim\limits_{x \to y} \frac{d}{dx} \int\limits_{y}^{x} \frac{f(t)-f(y)}{(x-t)^{\alpha}} dt$
@Nimza wait, I misread that... let me look more
10:41
the pickiness just won't go away... math.stackexchange.com/a/234101/1284 should i have dared to say f^2(x) = x^2+1?
regressively i invite any corrections to this vague answer. math.stackexchange.com/questions/234103/…
11:04
haha everything changes when i click that link.
what's goin on
@Nimza I was right. It is $0$ for $0<\alpha<1$...
$$
\begin{align}
\frac{1}{\Gamma(1-\alpha)} \lim_{x \to y} \frac{d}{dx} \int_{y}^{x} \frac{f(t)-f(y)}{(x-t)^{\alpha}} dt
&=\frac{f'(y)}{\Gamma(1-\alpha)}\lim_{x \to y} \frac{d}{dx} \int_{y}^{x} \frac{t-y}{(x-t)^{\alpha}} dt\\
&=\frac{f'(y)}{\Gamma(1-\alpha)}\lim_{x \to y} \frac{d}{dx} \int_{0}^{x-y} \frac{t}{(x-y-t)^{\alpha}} dt\\
&=\frac{f'(y)}{\Gamma(1-\alpha)}\lim_{x \to y} \frac{d}{dx} \int_{0}^{1} \frac{(x-y)^{2-\alpha}t}{(1-t)^{\alpha}} dt\\
&=\frac{f'(y)}{\Gamma(1-\alpha)}\lim_{x \to y} \frac{d}{dx} (x-y)^{2-\alpha}\frac{\Gamma(2)\Gamma(1-\alpha)}{\Gamma(3-\alpha)}\\
i try all the time in this institution. i gotta check out but that link was meant for skullpatrol who must be on vacation or something.
night everyone
11:26
@robjohn thank you! Oh... it's a real nightmare then :( What do mean authors when they say that $\frac{d^{\alpha}}{dx^{\alpha}} x^{\alpha n} = \frac{\Gamma(\alpha n+1)}{\Gamma(\alpha(n-1)+1)} x^{\alpha(n-1)}$ in the sense of local fractional derivative. Ohhhh
@Nimza I don't know much about fractional derivatives. I have never seen much use for them, but there must be some, or there wouldn't be much interest in them.
@robjohn I use them in economical modeling. I've seen guys who used it to model diffusion in liquid crystals
 
3 hours later…
14:05
@Nimza Hello!
14:19
@Nimza Remember that derivatives of arbitrary order are determined up to an additive constant... you are aware of the Riemann-Liouville definition, I presume?
@Nimza I don't have my refs handy, but that looks awfully like Caputo's definition...
@PeterTamaroff I'm so used to losing rep every month, I've gotten numb towards it...
@J.M. I don't remember users being removed as rapidly before August.
@J.M. Of course, I don't understand why they feel they need to remove their account. Why not just stop logging in?
But it sounds weird.... user is removed and people lose rep provenient of its upvotes and accepted answers?
sounds unfair...
@WillHunting You don't let us forget it :)
user55574
14:47
just a short question: $\mathbb{N}\times\mathbb{N} \subset \mathbb{N}\times \mathbb{N}\times\dots\times \mathbb{N}$ is wrong, right? I am a little confused at the moment :D
@robjohn No idea. One would hope there was a record somewhere of "I want my account deleted because yadda-yadda..."
Oh well.
@leonard Why would you think it's wrong?
user55574
@J.M. oh no. it's right. you just can choose any coordinates in the tuple of left sidte -.-
@leonard Think of it as a two-dimensional "slice" of the $n$-dimensional lattice...
user55574
@J.M. yeah that's what I haven't thought... :D
15:08
@leonard I don't know, it could be pedantic but technically $\mathbb{N} \times \mathbb{N} \subset \mathbb{N} \times \mathbb{N} \cdots $ is false.
E.g The element $(0,1)$ is not a member of $\mathbb{N}^3.$
It is often useful to identify the subset of $\mathbb{N}^3$ that has, say, the 3rd coordinate 0, with $\mathbb{N}^2$, but that is not to say that $\mathbb{N}^2$ is a subset of $\mathbb{N}^3.$
@KatieDobbs So, we're asking if zero is a natural number, then? Of course, you're supposed to pick one convention and stick to it in your work...
It'a subspace, but the question of whether it is a subset is debatable.
@J.M. That is not what I meant. Would it help then if I phrased a new example like this: The element $(2,3) \in \mathbb{N}^2$ is not a member of $\mathbb{N}^3$ which is the set of all ordered triples of natural numbers.
I think it would be correct to say that it is, though.
You could define it as a space with the basis $a̱, ḇ, c̱$. In that case, elements of â„•² would be linear combinations of $a̱, ḇ$ and elements of â„•³ would be linear combinations of all three vectors.
@KatieDobbs Well, phrased that way...
15:16
In that case, the elements of â„•² would just be a subset of the elements of â„•³ with the last coefficient 0.
@KatieDobbs I was thinking somewhat geometrically here, but I see where you're pointing.
@GregRos (if you're sticking to the convention that $0 \in \mathbb N$, of course... :) )
Well. Shit.
Just... wow. What I just wrote has so many problems.
Of course, if you are thinking geometrically, and use vector space structure and such, we can naturally identify N^2 with some subset of N^3, but in the purest form, set-theoretically speaking and with no other structure, N^2 is not a subset of N^3.
As I said, a matter of convention. I stick to "natural numbers are nonnegative integers"; but, there's this clique that works as "natural numbers are positive integers"...
No, it doesn't matter. â„• cannot be a vector space.
No you're right. @Katie Dobbs
15:21
Oh yes I was thinking of something else. But yes the point is, it is usually in some algebraic context that one wants to identity N^2 with some subset of N^3, and in these contexts this is a natural thing to do and no big fuss is made. But if you are talking to a set theorist, then they would object.
@Charlie goood day to you Marilia!
@J.M. Nice day J.M.! Yes! I use Riemann-Liouville definition of nonlocal derivative to define local derivative. As result I obtain Kolwankar-Gangal local fractional derivative :)
Hahaha! Oh, that killed me!
Not Kolwankar-Gangal local fractional derivative! That's hilarious!
@GregRos hm? :)
Just kidding :P
he-he-he)
15:24
@Nimza He doesn't want to tell us the punchline... ;P
Ah, the punchline was using ... to define ... and as a result obtaining ...
@Nimza Okay then; what then is your concern with the differintegrals?
Is normal space a subset of hyperspace?
@J.M. Oops, I can't undersrand what you're asking :(
(Anyway: in general, the differintegral of a constant isn't zero.)
15:27
What about cyberspace?
@J.M. KG derivative of constant is constant :) Because in terms of RL derivative it is $\lim\limits_{x \to y} {}_{y}D_{x}^{\alpha} (f(x)-f(y))$
@Nimza Thanks Alexey!
@Nimza I suppose the constant would depend on your choice of lower limit... :)
@J.M. wait a second... I'll look again for places of $x$ and $y$ :P
@J.M. yes, that's right) We pass to the limit our lower limit. Wow, tautology
SFAICR, the Kolwankar-Gangal definition isn't in the refs I know. Could you point out where these things were discussed?
@Nimza I figured as much. :)
15:30
@GarbageCollector hey, wassup?
@J.M. apmaths.uwo.ca/~mdavison/_library/preprints/lfd2.pdf voila. Look at page 2 for definition :)
@Charlie I have just eaten yakiniku. :-)
I can't log in to Steam without buying something ;_;
@GarbageCollector Nice! even though i don't know what is that :)
@Nimza Ah, quite nice. I note you are able to do "left" and "right" differintegrals with this definition. Very convenient.
@GarbageCollector And is it good?
I really hate numbers in math exercises.
@J.M. Yup! Very nice thing! It was invented in 1994 I think (and first appeared in publication in 1996, as I've seen)
They're so icky.
@Charlie Yes.
15:34
@GregRos Yes!!! Me either
@GarbageCollector :D
I try to substitute a parameter when I can.
@J.M. If they ask in chat or in a comment, there is a record. However, I think some ask by writing the SE staff, and there then no record.
@Nimza Yes, I'm running through the papers I got from Google Scholar now. Thanks for this; I have learned something new today. :)
@robjohn ...and you'd wonder why there's no coordination with math.SE mods. Ah well.
@J.M. Heh :) But I don't like it since derivative of differentiable function is zero :(
@J.M. there is another definition of local fractional derivative by Gao-Yang-Kang. As I've seen it doesn't hold for it. So we have an ordinary rule of differentiation of function $x^{\beta}$, for example. But I can't find it's definition in papers :(
@J.M. we ask that they confer, but they are busy, and since it often takes time to contact a moderator, it gets done without conference.
15:39
@Nimza OTOH, do you really need all the additional fuss? It seems all this is really useful only if you're dealing with "rough" functions...
...otherwise, you could fall back on RL or Caputo or Weyl.
@J.M. in my case I need it because I work with functions, depending of $(x^{\alpha}+\ldots)^{\frac{1}{\alpha}}$. They are so called constant elasticity of substition-like functions in economics
...and these have a lot of discontinuities?
@J.M. they're smooth! Here is another problem: for $x^{\alpha n}$ RL derivative gives a nice differentiation rule! But if we try to compute $(x+a)^{\alpha n}$ RL derivative it will give us a monster because of nonlocality:( monster depends on $a$ on nonmultiplicative manner
@Nimza Ah yes; that little inconvenience is touched upon in Spanier/Oldham. So, the "local" versions do not have this inconvenience; is that what you're saying?
@J.M. aha :) And I don't know still any convinient definition of local fractional derivative. I hope it is GYK derivative, but I don't know it's definition
15:48
It would seem that obtaining one convenience would come at the cost of another. "No free lunch", you know...
@J.M. aha, but I have a reason to think so. I've speaked with Yang Xiao Jun (Chinese specialist on local fractional derivatives), he sent me a file on this theme. I can send you it by mail if you want. He uses GYK derivative but without definition. And it satisfies all my conditions!
He seems to have a lot of things posted in arXiv...
(You've seen this I presume?)
@J.M. aha
@J.M. he briefly defines GYK derivative as $\lim\limits_{x \to x_0}\frac{\Delta^{\alpha}(f(x)-f(x_0))}{(x-x_0)^{\alpha}}$, here the problem is with $\Delta^{\alpha}$
@Nimza Yes, the use of $\Delta$ is nothing like the uses I am used to...
16:03
@J.M. so if you're interested, I can resend you his document. It it a review of GYK properties plus computation of GYK derivative of $E_{\alpha}((x+a)^{\alpha})$ (~ Mittag-Leffler function). $E_{\alpha}(x^{\alpha})$ is a fixed point for RL derivative. So he shows that $E_{\alpha}((x+a)^{\alpha})$ is a fixed point for GYK
@Nimza (i.e., the shifted Mittag-Leffler is an eigenfunction of the GYK operator ;) )
@J.M. aha! And a set of it's fixed points contains fixed points of RL!
(You could upload the doc somewhere, of course.)
@Jdoe Hi!
hello!
16:10
@J.M. ok?
@jdoe wassup?
@Nimza Got it, thanks.
I have to go, tho. See y'all later.
Bye!
bye bye!
just got home
16:16
hmm
whats up
@jdoe ... so so... a little bit slow...
I got a new number theory book to try
good!
:)
16:31
Welcome @only_gad !
Oh yeah and I did p-adic topology!
this is pretty weird
we have open balls $B_a(r) = \{x||x-a|<r\}$
and closed balls $B^+_a(r) = \{x||x-a|\le r\}$
but if you define the circle $C_a(r) = \{x||x-a|=r\}$
then it turns out every point in the circle is contained in an open ball (let $c \in C_a(r)$ then for all $x \in B_a(r)$ we have $|x-c| \le \max(|x-a|,|a-c|) = r$)
that's not right :/
Let $x \in C_a(r)$ then if $d \in B_x(r)$ then $|d-a| = \max(|d-x|,|x-a|) = r$ :/
oh that's perfect that proves d (any point in the open ball) lies on the circle
16:48
hello does anybody understand to logical square? http://en.wikipedia.org/w/index.php?title=File:Square_of_opposition,_set_diagrams.svg&page=1
I'll be probably some stupid easy rule
I need to just say for example: SaP is true
so SeP is a)true b) false c)we can't say
same for SiP and SoP
$$B^+_a(r) = \bigcup_{c \le r} C_a(c) $$
I tryed to read some articles about it but theres a lot of trash abou filosophy and Aristoteles and similar shits but from picture it seems its just some operations with the sets
3
so every closed ball is open (as a union of open sets)
and the open ball is closed too, so the space is totally disconnected
hi guys ... and charlie
@Charlie hi
@Nimza hi
@jdoe hi
@mick helllo!
16:56
@mick, see my proof that p-adic topology is totally disconnected
lol nimza , you tagged my hi to jdoe instead :)
@jdoe did you post it on main ?
@Nimza
@Charlie guess what ..
I just said it before you got here
@mick Hello, mick!
@mick what?
good for you :) @jdoe
@Charlie
I posted a new question :)
did you find it
16:59
i hope its not too vague considered , and i doubt about the title ...

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