@WillHunting Yummy

@WillHunting Do you have breakfast before you go to sleep? :)

@WillHunting It's late (early?)!

@WillHunting This and next.

@WillHunting Maybe. We will see!

I wouldn't want to disappoint you by not getting the Fields medal w/ Pedro!

@WillHunting Don't forget to mention that you answered one of my trig questions!

@WillHunting Oh right, the $e$ one :)

@WillHunting I'm so close to proving the Riemann Hypothesis. I just need to show that all the non-trivial zeros of the $\zeta$ function have a real part of $\frac{1}{2}$.

Then my proof will be complete.

:)

@WillHunting Come to Canada. Plenty of cold here.

?

@WillHunting Oh :). English?

@WillHunting So?

oooh negative temperatures, zero you still here?

@WillHunting I know.

Oooh i was just wondering about those negative temperatures

He posted about negative kelvin, so i assume he knows something?

@WillHunting I don't see you in the "Bridge."

@WillHunting Maybe it is me?

@WillHunting Hmmm... Maybe I know him :)

it would be really neat if the magnitude of something with negative kelvin temp had a energy distributions like a postive of the same magnitude, but when touching something with a positive temp, heat would flow into it, bringing it to zero kelvin or above

@zero Tell us about negative kelvin!

@WillHunting

@WillHunting I look like this: $\varphi$

@Greg I just posted the question in the Chemistry Stack Exchange Site stay tuned for further news. Didn't you go to the Wikipedia page?

@WillHunting Showing the English chaps how cool we are.

@WillHunting meh

@WillHunting I know. You told me

@WillHunting You are missing out on my awesome Perl status message.

@WillHunting Yup

@WillHunting I made a short JAPH script

for funsies

@zero im reading K&K now

@Greg ltl.tkk.fi/triennial/positive.html

what is the tex editor that was featured in the banner image on MSE a while ago?

There it is negative Kelivin temperature!

Strange

But true.

It's as strange as $i^2 = -1$

@WillHunting 2013

Hmm looks like negative temps have been around since at least 2000

The atoms move so slowly... they have a negative speed.

@WillHunting pourquoi?

@WillHunting It's fine for my purposes.

@WillHunting Hahahahaaa

Remember the laws of Physics are not scale invariant.

@WillHunting Hahahaa :) What about Gandalf?

@WillHunting None?

And you are both pros.

Right here ^^^. Classic Jasper Loy moment.

:)

@WillHunting

when approaching zero from the negative side, T-> -0, eventually only the highest energy level is populated. Since heat is transferred from the warmer to the colder part when two systems are brought into thermal contact, negative temperatures are actually hotter than positive ones. The crystalline lattice and conduction electrons cannot be cooled to a negative temperature because in this case the energy spectrum has no upper bound: at T<0 the energy of the system would be infinite.

«Suppose there are surjective homomorphisms $G\to H$ and $H\to G$. Are $G,H$ isomorphic?» I could have sworn I've read about this problem before, but I don't remember the answer or any references.

@WillHunting Nope. I meant random Bananas in Pajamas references.

@WillHunting Couldn't sleep?

@WillHunting So you are back :)

@WillHunting Alright. Good night, again.

Hey @Argon

@math101 Hey :)

@math101 Did you hit any bikers yet?

hahah I have been showing up late to work these days

Like at around 11

Late :)

The streets are relatively empty

at that point

We used to have late starts on Wednesday where we came to school at 10 AM....

But the stupid teachers union got rid of that right quick.

hahah

They drive me nuts

Maybe parents complained

So what are u gonna do when it starts snowing?

How will u get to school????????

We can't do anything. Its all just the union complaining about the provincial government. And taking out their anger on us (?)

@math101 As I always do :) I bike

wth

Bike in the winter????

You are funny :)

Yup. Did it last year and the year before

It gets a bit slippery when the slush in in excess Hahahaa'

Can someone here answer a question about power sets and the empty set?

@DavidK. Perhaps...

@math101 I used to bike home in the snow holding a bass clarinet!

But not anymore

OMG you play the clarinet

Yup

Bass

Cool

Heavy

lol ya I would say soo

I biked in hail once. Caught me on my way home

Well I feel like its a bit of a stupid question but... I am grading some homework papers and one of the exercises asks the student to prove that $\varnothing\not\in\mathcal{P}(A)\setminus\mathcal{P}(B)$. But is this true? I don't think it is.

Where $\mathcal{P}(A)$ is the power set of the set $A$.

@DavidK. It is true since the empty set is in every power set.

Well, the power set is a set right?

@DavidK. Certainly.

All sets contain the empty set as a subset. So shouldn't it be that the set containing the emptyset is not a subset of that set difference?

That's not what I meant. Hang on here...

Aw. You said a true statement though.

So, the empty set is both an element and a subset of a power set right?

@math101

Yes.

WOW

For any $A$ we have $\varnothing \in\mathcal{P}A$.

Your school is soo diverse @Argon

Which implies $\varnothing\in\mathcal{P}\mathcal{P}A\implies\varnothing\subseteq\mathcal{P}A$.

@math101 Ya

Well, Toronto is!

I see all different kinds coming out of there

hahah I agree

Hahahaaa

Are most of the students from that area?

Most. But lots of kids are in the gifted program or the advanced program

Ok. So the set difference of two power sets does not contain, as an element, the emptyset. But it does contain the emptyset as a subset. Yes?

Correct.

The second statement is true since differences are merely sets.

Damn. That means I have to regrade a bunch of papers. :( sadness

Aww.

So you must be part of the gifted program and the advanced program :)

Well maybe not.

@math101 Not both. The advanced program

You can't be in both

gifted as in mentally challenged or musical?

Ok nevermind. I don't have to regrade. I thought several students had made the same 'mistake' but I was just losing my mind for a moment. @peoplepower

@math101 As in they excel at some stuff but not at other stuff...

Gotcha

Thanks for your help. That was quite confusing for a moment there.

@math101 They have it easy. We need a 75% average in all advanced courses to stay in the program. And they get free TTC tickets

Those gifties :)

Wait why dont you guys get the free TTC tickets?

@DavidK. You're welcome.

@math101 No idea :)

Not as if you need it :P

@math101 Nope hahaa

I gotta get to studying. I have been lazy all week

All right

Good night

Good Night

Maybe I will bump into you tom

I finish work at 3:30

Maybe

I'm out before then

hahah So then I guess our paths wont cross

Good Night

hi @GarbageCollector

@zero: hi zero.

@zero: are you undefiined?

@GarbageCollector Zero is not undefined.

@GarbageCollector In fact zero is a well defined number.

@GarbageCollector are you undefined?

@zero Yes. I am undefined.

@GarbageCollector Why?

@zero: I have to take a bath first. See you later.

@GarbageCollector bye.

@zero Just a humorless joke from me.

np

@anon Schroeder Bernstein?

@zero Because for non-zero a divided by 0 produces b, $$\frac{a}{0}=b$$... wait...

@GarbageCollector Waiting...

$a=0 b$, for any $b$, $a=0$ that is contradictory to the assumption than $a$ is non-zero.

I should rephrase my sentence to be more mathematical style, but I cannot. :D

@zero: Just start with $\frac{a}{c}=b$. Assume $a$ is non-zero, and $b$ and $c$ are any numbers.

Consider the special case for $b=0$ in $a=bc$.

The you got the contradiction as mentioned above. :-)

@GarbageCollector But when you write $\frac{a}{c}=b$ it is because $a=bc$

@zero Is there another meaning?

@GarbageCollector You must start with a=bc to write a/b=c, correct?

@GarbageCollector Where would you normally look to find a meaning?

@GarbageCollector In a dictionary you would look up the definition, right?

The definition in Algebra of division reads: a/b= a*(1/b), b=/=0.

Now every real number except 0 has a reciprocal and can be written as 1/b

@aDangerousIdea Hmm, I don't know :D

@GarbageCollector 0 can not be written as 1/b because 0 times any number is 0, not 1.

@zero Very good reasoning.

@garbagecollector Remember reciprocals are two numbers whose product is 1.

Honestly, @GarbageCollector did that make any sense to you?

I guess not...

@WillHunting hi there

@WillHunting something is very wrong with your setup, I fear :(

@WillHunting last night I posted this chat.stackexchange.com/transcript/message/6824781#6824781

I have some concerns about these 2 guys ...

@WillHunting hmm - maybe stop jumping from high places? :P

@WillHunting I suspect 2 accounts for one person ...

@WillHunting slightly concerned that the rubbish answer got accepted ...

@WillHunting and there are a number of similarities between them that make me think they are the same person

@WillHunting Doesn't really bother me either - I just find it rather silly, but also slightly amusing

@WillHunting they both do!

and they both put dollar signs round individual parts of equations, rather than round the whole equation

Hey look, I have free internet!!

Looks free to me :)

@aDangerousIdea Heh. I am in a different city currently, staying in a hotel right now. The hotel has 200MB free internet usage in its Wi-Fi thing.

Thanks for the context :-D

@aDangerousIdea You're welcome. By the way, are you Parth from the chatroom before?

no

Okay.

@GarbageCollector Why can you never divide by 0?

@garbagecollector no scrolling back...

@WillHunting hahahah

@WillHunting Nobody!!!

@WillHunting heheheheh

@WillHunting That's good news!

@WillHunting Jayesh is in mumbai...

@WillHunting That certainly would be awesome!!!!

@WillHunting Hope so! :D

@GarbageCollector So you like to pester other people, but when I do it to you, it is not so much fun any more is it?

@OldJohn I presume you've flagged the relevant bits?

Well @GarbageCollector ?

@WillHunting It's like you aren't used to my modus operandi... :P

@WillHunting It's shorter than "way of doing things", and I'm lazy as hell. :P

bye

@WillHunting hi!

I wanted to ask you something, will ask over mail probably. academic related.

@J.M. Not yet - should I do that?

@OldJohn Well, if you really, truly think there's monkey business going on...

@J.M. I would be pretty staggered if there were not, I think, having looked at style of questions, style of comments, whose answers are accepted, ... so I guess I ought to raise someone's awareness ...

@WillHunting Yes - I assumed that would be the case - and neither of those is likely to be conclusive

@WillHunting Sure, I use Tor every so often...

@WillHunting yep -too easy to use vpn or Tor

@J.M. Me too very rarely

Still, not everybody is careful. At least, those dudes can be caught.

@J.M. I will flag it as possibly suspicious - without being overly aggressive about it, I think

@OldJohn It's all in the phrasing of the flag, sure. :D

@WillHunting I've done knotty things myself...

@WillHunting emails are more conclusive, but most ISPs rotate IP addresses, so IP addresses are not as reliable for determining duplicate accounts.

@WillHunting yes, I was thinking of duplicate emails indicate duplicate accounts, but it is quite easy to get a lot of email addresses.

@robjohn Did you vote in the election?

Hi

hi

@aDangerousIdea I did.

@WillHunting You can call me whatever you want pal.

I have a linear operator $L(f)$, and another operator $G(f)$ which is invariant under $L$ what I mean is $G(L(f)) = G(f)$. The operator $G(f)$ is not linear where as $L(f)$ is. I am kinda not able to figure out what I could do with this structure?

@WillHunting I guess he wants to find $x$ such that the denominator is a factor of the numerator

Hi @rob @Will @Old and dangerousidea

@RajeshD Where does this come from?

@RajeshD hey!

long story @rob

yeah I have been a bit away @Will

@RajeshD hey there...

Hi @rob seeing u on chat after long time

hi honey!

@GarbageCollector hi

@zero hi tooo

@GarbageCollector Why can you never divide by 0?

@zero Can God divide any number by zero? :-)

@GarbageCollector Why don't you ask him?

@zero Because she cannot be asked.

A zillion, in fact.

@WillHunting No - infinity times :)

@Grarbage : Are you skull?

Can she create a rock she can not lift? @GarbageCollector

oops Garbage seems even dangerous

@RajeshD Why?

@RajeshD Will is Jasper

dividing aa number by zero is a dangerous idea, it blows up,

@WillHunting But the God can :-)

@zero No. Only Jasper is my honey!

@WillHunting ;-0

@RajeshD It has been a while. Nice to see you back :-)

@WillHunting :-)

@robjohn Did you know this?

@WillHunting Call him "Dang"...

@WillHunting That^ would be a $\Huge\text{Dangerous Idea.}$

;-)

"zero skull" would be a very interesting name...

@zero I have seen it before.

@J.M. wouldn't you need to call him @adang?

@robjohn I suppose, for @-lerting purposes... :)

Heh... the last 5 of my answers have been accepted, but only two have gotten upvotes.

People find them the best answer, but not useful? :-)

@robjohn voting is certainly capricious ...

@OldJohn indeed ;-)

@WillHunting ah, good point.

@robjohn I posted an answer recently - the OP said it was the one that made most sense, it got most upvotes - and then accepted a different one :)

@OldJohn That is not uncommon. capricious indeed.

@robjohn equally baffling are the 5 upvotes for my latest question :)

@WillHunting yes, and goats are the epitome of capriciousness.

@WillHunting It is a very obscure part of topology that I expected almost nobody to be interested in (although had a faint hope that someone somewhere might give a clue)

@WillHunting Indeed

Dang

@WillHunting true

Must go - photography group - back later

later

hi ... can anyone help with with this short Question.

given f(x) = sin(1/x) ... is |f(0)| <= 1 does intermediate value theorem apply here?