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08:22
Yoink
Apparently bullet (2) hypothesis of definition of Sheaf only requires basic open families of sets.
Proof:
https://math.stackexchange.com/questions/4990717/can-we-apply-the-hypothesis-of-bullet-2-in-the-definition-of-sheaf-using-mere
@Shaun topology is very interesting, fun, and when you combine it with other fields, you get new theorems rather quickly.
PS. Found major issues with my previous approach (that I emailed you). Now I think I've got it (yet again). It uses a freaking sheaf this approach, who would have thought! I'm new to sheaf theory. But basically you can glue together some stuff with them. I also came up with a new topology which is courser than Furstenberg's, and hasn't been written about AFAIK.
*coarser
That simply means the open sets of the new one are strict subset of the open sets of the larger one (Furstenberg's full topology).
You must study some topology at some point! Topological groups, etc. are right in your area.
09:20
That's great, but given your track record, I suggest waiting a while before announcing you have proven it, next time.
8
 
2 hours later…
10:53
@AlessandroCodenotti If $X$ is totally disconnected compact Hausdorff, $|X|\geq \mathfrak{c}$, does there exists a a connected Hausdorff $Y$, $|Y|\geq 2$, and a continuous surjection $f:X\to Y$?
11:21
Hi
12:20
@Jakobian the answer to this is no
Let $X$ be the one-point compactification of discrete space of size $\mathfrak{c}$ and suppose there exists a surjection $f:X\to Y$ where $Y$ is connected Hausdorff and non-trivial, then there exists surjection $g:Y\to [0, 1]$, so we can assume $Y = [0, 1]$. By taking $\infty\in X$ and considering neighbourhood of $U$ of $f(\infty)$ not including infinitely many points, $f^{-1}(U)$ must be cofinite yet its complement must somehow surject onto an infinite set
And to answer another question of mine, suppose $X$ is the one-point compactification of discrete space, $\alpha > 0$ a non-limit ordinal, then every compactification of $X\times \omega_\alpha$ is zero-dimensional. Indeed, if $Z$ is such compactification that isn't, then there is closed connected non-trivial $Y\subseteq Z\setminus (X\times \omega_\alpha)$ and since $Y$ surjects onto $[0, 1]$, so does $Z\setminus (X\times \omega_\alpha)$ and hence $X\times \{\omega_\alpha\}$, which is impossible
forgot condition: also $|X| < \aleph_\alpha$
This shows that the property "every compactification of $X$ is zero-dimensional" doesn't restrict the cardinality of $\beta X \setminus X$ in any way, it can be as large as we want
I'm losing hope that any nice characterization of such spaces exists
Well, for locally compact spaces at least, this is equivalent to "$\beta X\setminus X$ doesn't surject onto $[0, 1]$" which is something
 
1 hour later…
14:04

 General topology

For any discussions about general topology. For instructions h...
see this channel for summary of my progress
15:02
@Jakobian where is the surjection $Y\to[0,1]$ coming from?
15:18
hi
15:58
hi
16:14
@SineoftheTime Out of curiosity I tried to solve this exercise: $\int_{+{\partial{D}}} \tan(z) \text{dz}$ with $|z| \leq 2$, then I rewrote the integral as $\int_{+{\partial{D}}} \frac{\sin(z)}{\cos(z)} \text{dz}$ singularity $\cos(z) = 0$ when $z = π/2 + nπ$ , then $|π/2 + nπ| ≤ 2$
I found $n = -1$ and $n = 0$, so $z = ± π/2$
The limit Is $\lim_{z \to\ +\frac{π}{2}} \frac{\sin(z) (z - π/2)}{\cos(z)}$
that for both + and - π/2 is -1
$\int_{+{\partial{D}}} \tan(z) \text{dz} = 2πi(-1-1) = -4πi$
I think it's right
Looks good
16:33
I agree with Vladimir @Pizza
@Jakobian motivating
16:53
@VladimirLysikov @SineoftheTime Oh ok, thanks
 
2 hours later…
19:19
@AlessandroCodenotti see the proof that if $X$ is a $T_4$ connected space with $|X|\geq 2$ points, then $|X|\geq \mathfrak{c}$
Taking two distinct points $x, y$ take function $f:X\to [0, 1]$ with $f(x) = 0$ and $f(y) = 1$, then $f$ has to be surjective
 
1 hour later…
20:46
Anyone know sheaf theory here?
Man, you guys ought to get on that sheaf theory bus.
@Pizza hey
@IThinkHighlyOfEiligh a smidge
@BenSteffan can I link you to my most recent question. It's rather simple. I don't use much properties of sheaves, but need to satisfy some hypotheses using my local sections. Once I can prove that, then the global section must be continuous and unique.
@IThinkHighlyOfEiligh hi
20:51
@Pizza I like your avatar
oh wait, you changed names again
My dad & mom have planted about 20 🍍 plants
in Hawaii
i saw the question, but didn't have anything to say about it, sry
@IThinkHighlyOfEiligh 😃
@BenSteffan it's ok
20:52
@IThinkHighlyOfEiligh Thanks
@IThinkHighlyOfEiligh bro is living life
I changed my name yes. Long story. Very good, then turned very bad
She's in the jailhouse now
I guess my fortune cookie was half-right
@Shaun good idea. I will check my prove 5 times, sleeping on it for 5 days, then announce
But might just try emailing the local professors. Save on gas
Yes!
I'm extra close now.
Basically took the Furstenberg topology and took a coarser one, namely generated by basic open sets $a + s\Bbb{Z}$ where $s$ is square-free.
Not 100% sure yet, but I should know by tomorrow or next day if it's gonna work
probably no
:)
20:58
The integers are still a topological ring under this coarser topology, very easy to prove
@SineoftheTime yep, probablistically speaking
I wonder how many times Gauss had to make mistakes before crushing a theorem
0
Gauss was Gauss
LOL
You only see the best of them (in literature), so we get a skewed perspective
If I can get this proof to work, there's a way to show that if at least two $2k$-separated primes exist, then there must be infinitely many such pairs. But my paper would focus just on twin primes, leaving the other cases open.
$0$-separated primes are the primes themselves!
Zhang won some monetary awards for his work. I at least want to be an honorary professor and travel the world to teach / consult. If the journals shaft me, I'll just self-publish, even write a book on elementary topological NT.
It's great. It's not an official prize problem like the Clay Institute $1M problems, but it's still considered an unofficial one.
I'm no crackpot. However, I'm not in school, so it feels like there's a huge wall in front of me
I would like an MSE alternative website, where prize problem questions don't get deleted. Proofs can be peer-reviewed / checked, and credit automatically attributed to the right person. I gave up on my huge commutative diagram site project. This site idea would be simpler - no logic backend, just user edited content
It's ridiculous how oppressive the site is against anything that isn't a homework problem, yet do my homework is also not allowed. It's a contradiction obviously
It's hampering future mathematicians from doing what they do best. And we're doing it for free. Still they try to control us
Perhaps it's the best policy for high-quality content, but just wish there were something more suitable for mathematicians to actually "do math" / participate / be creative. Rather than just for learning what's already been done in math.
 
2 hours later…
23:24
@Ben turns out the maps in the saturated class generated by the horn inclusions $\Lambda_k^n\rightarrow\Delta^n$ for $n\ge2$ and $0\le k\le n$ are precisely the anodyne maps that are bijective on vertices satisfying the additional condition that the edges of the domain generate all edges in the target under composition and cancellation, which is surprisingly intuitive once you think about it
I will take your word for the "intuitive" part :^)
it's a bit like saying that a $1$-connected map is characterized by inducing an iso on $\pi_0$ and a surjection on $\pi_1$
emphasis on a bit I assume
:)
23:45
everything is a bit like saying that a $1$-connected map is characterized by inducing an iso on $\pi_0$ and a surjection on $\pi_1$

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