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00:04
@leslietownes When they do that, the system will warn them. And if they do it too many times, it will give them a question ban. Deleting a question that's got a negative score doesn't make the badness go away. It just takes you closer to a ban. This can be counter-intuitive for many people.
00:24
do not get on the wrong side of the System
seek its favour
 
2 hours later…
02:16
Do foreign universities usually test “IQ” on an entrance exam? It sure happened to me.
Although I was exempt from the IQ portion since I had cleared the Mensa Test in high school
@EM4 First position.
I’ve won 5 competitions in total now. 3 math competitions and two e-sports/gaming competitions
02:29
$C$ is nontrivial ideal, and $A \neq B$ nontrivial ideals. if $A+C = B + C$, how come we have $C$ not in $A,B$?
02:42
$C=2\mathbb{Z}$, $A=3\mathbb{Z}$, $B=5\mathbb{Z}$
0
A: Thomas plank is not realcompact

JakobianLet $X$ be the Thomas plank as defined in the body of the question. Let $\mathcal{Z}(X)$ be the set of zero sets of $X$ i.e. sets of zeros of continuous maps $f\in C(X)$. Lemma. If $f\in C(X)$ and $Z(f) = \{x\in X : f(x) = 0\}$, then $Z(f)\cap L_0$ is countable or co-countable in $L_0$. Proof: Ac...

I made a Q&A type of question
at Soumik: $A + C = B + C = \mathbb Z$, and $(5)$ not in $(2), (3)$
shin: what do you mean by C "not in A, B"? C not a subset of A and C not a subset of B? or is "A,B" notation for osme kind of ideal? "in" probably at least means subset?
agh stop saying "in" to mean something that isn't "in"
not a subset of both, sorry
in the language of ideals of Z you're asking, how can we have gcd(a,c) = gcd(b,c), and yet c is neither a multiple of a nor a multiple of b
and the answer i guess in those terms is that when gcd(a,c) = gcd(b,c), it's quite possible for gcd(a,c) = gcd(b,c), which is guaranteed to be a divisor of both a and b, to be a proper divisor of both a and b
02:49
I've actually helped to determine which spaces on pi-base are realcompact with this answer
Z of course is not the only example of a ring, and the intuition you build for Z doesn't always generalize. maybe look at ideals in other examples too
so I see it as a significant contribution
nice, the intuition for Z works. otherwise there's a proof by contradiction (assume it is in both), but i'm wondering if there's a nice direct proof which could offer some intuition for the general case
oh, i thought from the above you were asking for a single example, not a general proof
@冥王Hades Absolutely not.
03:08
While I stumble here less than before, I must occasionally keep the nerdity in check
How are all of you doing? Especially Ted, it's been a while :)
@冥王Hades I have never in my life every heard of such a thing, for oh-so-many reasons.
Learn, adapt, overcome
I feel a bit funny given that I single-handedly resolved the issue of which spaces on pi-base are realcompact by proving which are.
@shintuku the general intuition becomes immediate when you consider addition of ideals as moving back in the lattice of ideals, towards the maximal ideals
hm nvm this works for Z i don't know if it works in general (but it might, find out soon in the next episode of commuting with shintuku)
@XanderHenderson Which is why I asked here. I haven’t heard of any university do this as far as I knew but I wanted to confirm
03:28
yes it works! ideal addition and intersection correspond to join and meet
Howdy, Demonark.
are there more lattice isomorphism theorems for rings other than the correspondence theorem?
by that i mean stuff about modifications of lattice structures induced on ideals by ring homomorphisms
I miss Texas
03:50
Today marks 5 years since I lost my girlfriend to a bus accident
04:11
when do we have that all elements of a ring are contained in a nontrivial ideal?
warning i made a mistake asking the above question, all elements generate an ideal
I am sorry for your loss, @冥王Hades
My new laser just showed up. Yay! It is very good for pointing at stars!
Is it green?
It is.
≈200 mW, 532 nm
Nice. I'm very close to a flight path, so it's probably not a Good Idea for me to point lasers into the sky here. And being in the middle of the city, the light pollution is terrible, so I can't see many stars. The last place I lived was rural, and I could easily see the Milky Way & the Magellanic Clouds.
04:35
the dispensary nearby just had a sale on Magellanic Clouds
04:54
@PM2Ring I live in one of the darker parts of the US. I can walk half a mile north of my house, and get to an area dark enough for me to resolve the milky way with my naked eyes.
It is one of the perks of living where I do.
There are rings other than. $\Bbb Z$? Nah.
xander: or of taking peyote more or less anywhere
surely $\{0\}$ is a rng?
Nope. Not for me.
i'm a minimal kinda guy
05:05
copper, this is blasphemy
that is a surprise?
that was what the retreat priest said when i pointed out that the mechanics of holy water creation were essentially undefined.
slap
i was a bit surprised at his reaction
@leslietownes Meh. I'm not really into mind altering substances.
Other than a little beer or whisky from time to time.
i do like cabernet sauvignon
@copper.hat Cabs are fine. I prefer pinots.
i like pinot grigios
05:18
Leslie and Munchkin prefer ducks à l’orange
@copper.hat Yup. Those are good, too.
@TedShifrin If I could get duck...
@XanderHenderson I have one about the same specs. Very bright.
@robjohn Yup. It's my new favorite toy.
@XanderHenderson i am sure you could dazzle a duck with your green aviation disruptor?
@copper.hat Dazzle a duck??? I deem that dangerous! Dear oh dear, don't do it!
05:22
Just don’t point it anywhere near any aircraft. They get very annoyed, and will call in authorities.
@robjohn The nearest aircraft are, like 15,000 ft above me. :D
Oh, no... probably more like 28k ft.
it is beyond me why people would think that pointing lasers at aircraft in peacetime might be ok
For teh lulz?
You’d be surprised at how far a 200 mW laser will go
when i was in AZ last august there was a mil base right beside the ranch
05:23
@robjohn 5 to 6 miles, yeah?
You may not see it, but they will
But you might see it
Depends on how good the collimation is
and the atmospheric conditions...
In any event, I should go to bed. It is quite late.
G'night.
listen, your honor. robjohn said i would be surprised at how far a 200 mW laser will go, and hindsight being 20/20 he was very right about that. can i go home now? some guy already took my laser
a red laser is more fun, because you can spook your neighbours
05:28
Xander is not going to bed. He’s just going to test out his new toy on high flying planes.
Note that he said he should go to bed
when i was on LSD i saw beams of light and heard noises that sounded a lot like car horns
he's going out to dazzle ducks
ted apparently 'duck mitigation measures' are on the agenda for the next HOA meeting. very tempted to suddenly take an interest in HOA politics on the side of the ducks
time to get your 'what the duck' t-shirt printed
i will, of course, be dressing as a duck
05:32
geese can poop around 1kg per day. something to share with the hoa
it was part of a homework i gave to my kids in elementary school as part of figuring out how much poop the ocean view school would get every day.
this is why they hate me
we also saw a pair of coyotes on a walk today
and oddly enough some lunatic was driving after them, i think trying to harass them into leaving the neighborhood (the HOA sent around an email about how we were encouraged to do this)
but she was so focused on them that she almost ran us over
so anti-anti-coyote vigilantism is another plank in my platform
i remember reading a rant on nextdoor where someone was complaining about coyotes attacking domestic cats and their argument was that 'we gave them all of tilden'.
copper: you and your minimalism
05:37
@leslietownes I thought the ducks were at the pond?
personally i like wildlife around. if it wears skirts then inside the house if acceptable, otherwise i prefer the garden
but vermin & ants are never welcome
ted most of the ducks are, but we do sometimes have them at the pool
thx for the upvote
there will be no deleting that question
:-)
my response is the much reduced version of my original
05:39
Here's a pop song from almost a century ago. Helen Kane - That's My Weakness Now. I wonder if kids today could appreciate it. Helen was the inspiration behind the cartoon character Betty Boop.
a surprising amount of the matrix algebra questions people post fail in the 1x1 case, or 2x2 diagonal matrices
yup, it reveals something about my character that i relish showing 1 dim counterexamples
Helen was from The Bronx. She has a very strong accent (possibly exaggerated). I wonder if that accent still exists today.
was kane the inspiration?
according to blackhistory.com/2018/05/…. she started as African American and was then turned white
@copper.hat if you absolutely must(ard)
05:47
@copper.hat According to the courts, she wasn't. However, from en.m.wikipedia.org/wiki/Helen_Kane
> Margie Hines, Mae Questel, Bonnie Poe, Little Ann Little, and Kate Wright provided the voice for Betty Boop. They had all taken part in a 1929 Paramount contest, which was a search for Helen Kane[citation needed] impersonators
colemans, the only mustard
I was vaguely aware of Helen Kane as "The Boop Boop a Doop Girl". But a couple of months ago I heard a program about her on a community radio station, which played a lot of her songs. And after that, I checked out most of the stuff by her on YouTube.
i mostly hear helen kane on tiktok. just video after video of boop boop a doop. it's all the kids are listening to
06:07
^ A theme song for Munchkin. ;)
 
4 hours later…
10:21
@PM2Ring yeah that really hit me like a train. It wasn’t the first time I experienced such loss but still
 
1 hour later…
11:34
Given a graphical model one can wonder if two nodes/distributions are conditionally independent. I was wondering if one could create a logic expression that is either true/false and dependent on that the two nodes dependent/independent. In his expression every variable would then corresponds to vertex of the graph.
I have yet to see, if this can be made rigorous. E.g. how should edges be modelled or vertexted in the graph that are given
12:31
@XanderHenderson I had a short period when I used to drink whiskey semi-regularly (I like scotch). But I had second thoughts, especially that I've seen how unhealthy alcohol can be.
Now I pretty much don't drink except for at parties
12:46
@leslietownes So glad I live in a place without an HOA. HOAs are pure evil.
13:05
@leslietownes are those countably additive measures?
@冥王Hades Crap, that sucks! I'm sorry that happened.
Mad
Mad
13:26
@TedShifrin nevermind that, but what can we deduce about the eigenvalues?
13:37
@robjohn Yeah. I’m not religious, at all, but I hope she’s in a better place
13:53
Let $X, Y$ be random variables taking values in $(0,\infty)$. Find the expression for $F_{XY}$ in terms of $F_X$ and $F_Y$.
How to do this?
$F_{XY}(x,y)=P(X\leq x,Y\leq y)$. I don't have independence or something like that. How to use the positivity?
They gave a hint: Use the fact that lnX, lnY are r.v.s on Omega.
are you sure they don't mean the product of $X$ and $Y$?
14:12
You are right.
14:37
For a while I thought melancholy was a good feeling
Being reminescent of good memories of the past
That's nostalgia though
Let me ask you guys a question though. In English, is the word melancholy mostly associated with past memories?
It is so in my own language
 
1 hour later…
15:58
Guys, quick question, since the intersection point is arbitrary, I can set it to be the dead center of this decagon right? Which would mean that $\frac{A}{R}=\frac{H}{D}=\frac{N}{O}$ right?
Since the point is arbitrary, does this equality hold no matter where I set it?
@SouravGhosh is $\omega_1\times [0, 1)$ metacompact?
16:59
Suppose $X_1,X_2$ iid to $U[0,1]$.And $X_3=\text{sgn}(X_1-\frac12)X_2$. Find out the regular conditional distribution of $X_3$ given $\sigma(X_1)$.
How to do this?
I have to find some measure $\mu:\Omega\times \mathcal B([0,1])\to[0,1]$ such that $\mu(\omega,A)=P(X_3^{-1}(A)|\sigma(X_1))(\omega)$.
its not metacompact
Where, $A\subset [0,1]$ is Borel. Now if I start with $A=(a,b]$ then $X_3^{-1}(a,b]=X_1^{-1}((\frac12,1])\cap X_2^{-1}(a,b]$
So I want to define $\mu(\omega,A)=1_B(\omega)P(X_2^{-1}(A))$ where $B=X_1^{-1}((1/2,1])$. Does it look good?
17:19
0
Q: Integral property

MathematicallyInterestedLet $f:X\times X\rightarrow R$ be integrable let $g_1,g_2:X\rightarrow X\times X$ be two measurable functions and $\mu$ a measure on $X$. Define a measure $\eta$ on $X\times X$ by $\eta(A\times B)= \mu(g_1^{-1}(A)\cap g_2^{-1}(B))$ Show that $\int f(x,x') d\eta(x,x')=\int f(g_1(x),g_2(x))d\mu(x)...

@冥王Hades When you do competition math, you assume this. When you do real math, you have to prove it.
@TedShifrin I refuse to assume it. Assumption are for the weak
so turns out I didn't single-handedly establish realcompactness for spaces on pi-base yesterday, because I missed 3 spaces (I've search for metrizable and non-metrizable spaces, but turns out 2 of those don't have established metrizability, and I established non-metrizability for one of them).
however, 2 of those I established realcompactness today, and only open long line is left
turns out they didn't know long line is non-metrizabile, heck, someone wrote it's not countably compact (!)
that's a little shocking for me, since long line is a prime example of a non-metrizable manifold
17:36
@Mad In fact, all you can say is that $P$ preserves the standard symplectic form on $\Bbb R^{2n}$. So, restricted to each of the standard $\Bbb R^2$ subspaces (spanned by $e_i$ and $e_{n+i}$), the map has determinant $1$. Even in the $2\times 2$ case, this tells you only that the product of the eigenvalues is $1$.
I have no reason to believe that the long line is not realcompact though, I'm pretty sure it should be
ah wait. Maybe not
@冥王Hades if you set the point to the center, don’t you get $\frac00$?
@robjohn yeah I know but ignore that equation for now. My actual idea is to set it such that I can prove the equality holds true
I wont actually set it to the center
I get $\sqrt3-1$, but that’s just looking at the image.
I may have miscomputed something, just working in my head.
17:51
After staring at it for half an hour my hunch is that it’s $\sqrt5 +1$
Could be wrong though at first I got 2
Oh, I subtracted where I shouldn’t have
Such an annoying problem
Mad
Mad
@TedShifrin how did you reach that (that the product of the EW =1) ? (from the given equation, i am not familiar with the terms you used)
oh
Because the determinant is 1
(or -1)
long ray is pseudocompact, obviously, so it can't be realcompact
alright, now I can say that I single-handendly established realcomactness of spaces on pi-base
18:15
@冥王Hades I get $2$
and I think that is correct, after looking a bit longer.
@冥王Hades I will write it up in a bit.
I got 2 at first as well but I didn’t think the answer could be that simple so I scrapped it
I hopefully can end this chapter, I was too focused on this single one property and people just kept on asking questions about it
@Mad It actually is $+1$ because $P$ pulls back $dx\wedge dy$ to $+dx\wedge dy$.
You can work out the equations explicitly in the $2\times 2$ case, anyhow.
Mad
Mad
I understand what you wrote, but this was given as a physics assignment, not even the tutor have heard of what a diffretnial is, let alone wedge product
18:34
Well, I am not a mind-reader. You need to tell me all the things you don't know before you ask a question :)
So work out the equation in the $2\times 2$ case. You get $\det = +1$. The general case is a direct sum of those $2\times 2$ cases, as I already indicated.
Mad
Mad
but how do you figure that out. out of $P^T J P = J$ you only get $(Det P) ^2$= $1$
If you write the $J$ matrix in a different basis, namely writing $e_{2i-1},e_{2i}$ instead of $e_i$ and $e_{n+i}$, then $J$ becomes a block matrix with $\begin{bmatrix} 0 & 1 \\ -1 & 0 \end{bmatrix}$ blocks down the diagonal. You then get $n$ such equations.
You have to write out the equation more explicitly. Don't take determinant.
Do the $2\times 2$ case. Write it out explicitly with $P=\begin{bmatrix} a&b\\c&d\end{bmatrix}$.
Mad
Mad
so you are saying a proof by induction
i dont like induction proofs.
Very tedious.
No, I'm not saying induction. Certainly not for a physics class.
Just do the $2\times 2$ case and then think about what I've said.
Gotta learn Feynman’s technique
18:39
Which one is that?
Mad
Mad
I Aam not sure why you want to write j in a different basis
Oh you flippd the signs
Oh, I didn't mean to flip signs. Sorry.
I wanted to change $J$ to a more convenient $2\times 2$ block form.
It only makes it more intuitive, but it doesn't really matter.
Mad
Mad
Okay
so i just did the 2v2 case
and it is true, that the determinant is 1
not -1
Very cool
Now prove it for n
:D
But actually (dont) i dont want to bother you with this question ,it is not very relevant to me
i was hoping for a (Quick) manipulation solution
Seems not to be the case
No, it is. Just write $\Bbb R^{2n}$ as a bunch of $n$ $\Bbb R^2$'s put together. You get $n$ copies of this equation.
Mad
Mad
VIA what ? the direct sum?
18:57
Each $2\times 2$ block will give you a det = 1 equation.
(The off-diagonal blocks you can check will have to be $0$.)
This is easier to do/see/understand when you first convert $J$ into block form as I've said twice.
Mad
Mad
alright, thanks!
You're welcome. Good question.
I can’t believe it. I didn’t know there was something called the Law of Tangents or Napier’s Analogy. I just learned it.
Let’s prove it
19:16
What is it?
$\frac{a+b}{a-b}=\frac{\tan\frac{\alpha+\beta}{2}}{\tan\frac{\alpha-\beta}{2}}$
Wrote that with one hand on a phone
I've never seen that before. Looks like an updated law of sines.
@TedShifrin Your intuition is correct. I prove it by messing with the law of sines
I've survived an entire mathematical career without knowing or needing it :D
@TedShifrin Reassuring to know even you hadn’t known it. It means I’m not stupid. :P
19:27
Knowledge of esoteric formulas has nothing to do with "smart" or "stupid."
Yeah but I can see it’s usefulness in certain competition problems
This is actually better than the law of cosines if a and b are very close in numerical value
Who cares ....
if knowledge of esoteric formulas meant being smart, high school me would've been one of the smartest people alive
I'm glad to have grown up, though
I hate having to remember stuff. Precisely why I dislike history
Neither math nor history should be about memorizing crap.
19:35
During my physics exam I would actually waste time deriving equations I should’ve just remembered. Still got good scores but boy was I short on time
@TedShifrin you mean I don’t need to remember what Darius the third ate for lunch in 50000 BC?
Someone got caught using ChatGPT during the math competition we just had
@TedShifrin or cupid
ChatGPT can’t even solve the problems we had, I tried it after getting home.
ChatGPT can't even solve a simple topology question, useless
and when it gets corrected, it repeats the same mistakes
Exactly.
It’s actually annoying. I asked it to write me an essay after giving it some guidelines and it couldn’t even follow those properly
I don't like the whole popularity it's getting - it's not smart at all. It's just an advanced monkey
maybe in few years
19:42
It’s a language model.it
it will never be “smart”
of course I'm not talking about being smart as for humans
when I say smart, I'm talking about how prone is ChatGPT to making mistakes or bullshit conclusions
and so, it's not smart at all
you mean hallucinations? Yeah even those won’t go away completely. It’ll just be minimized as it gets trained with more data
hallucinations?
Suppose $S_n=\sum_{i=1}^n X_i$ where $X_i$ i.i.d Ber(1/2). Prove or disprove that T is a stopping time. $T(\omega)=n$ where $S_m(\omega)<100\leq S_n(\omega)$ for any $m<n$ is a stopping time w.r.t. $\mathcal F_n^X$.
I don't even understand the way it is defined.
@Jakobian this:
In the field of artificial intelligence (AI), a hallucination or artificial hallucination (also called confabulation or delusion) is a confident response by an AI that does not seem to be justified by its training data. For example, a hallucinating chatbot might, when asked to generate a financial report for Tesla, falsely state that Tesla's revenue was $13.6 billion (or some other random number apparently "plucked from thin air").Such phenomena are termed "hallucinations", in loose analogy with the phenomenon of hallucination in human psychology. However, one key difference is that human h...
19:48
I guess I mean that, yeah
though not all of those things I saw ChatGPT say seemed to fit as hallucinations
hallucination here seems to just be a false statement
what I'm thinking about are bullshit proofs that lead to wrong conclusions, but they are "justified" by the bullshit proof
so they don't come out (seemingly) out of thin air
Yeah I kinda get it. I asked it to tell me how to construct a regular heptagon with a pencil and a straightedge
it gave me a detailed answer and without reading it I knew it was bullshit
it’s an impossible problem
20:23
Compass and straightedge, you mean.
20:36
Oh yeah
big brain moment
chatgpt knows ted! sort of
> Ted Shifrin is indeed a notable mathematician, specifically a differential geometer. He is a professor of mathematics at Indiana University Bloomington and has made significant contributions to the field of geometry, particularly in the areas of differential geometry and the study of minimal surfaces. His research focuses on topics such as curvature estimates, geometric flows, and the interplay between analysis and geometry.
> Shifrin has also authored several textbooks, including "Differential Geometry: A First Course in Curves and Surfaces."
@冥王Hades On our Australian flag, all the stars are heptagonal. Partly, that's 6 points for each of our states, plus 1 point for our territories. But it's also because we know advanced mathematics, and aren't limited to compass & straight-edge constructions.
@Jakobian ChatGPT isn't trying to be smart. It doesn't attempt to do logic, or create truthful statements. It just produces sequences of tokens that are statistically consistent with its training data and the current prompt. It can't even get parity right:
Here's an example (from a month ago) of ChatGPT getting mixed up with simple numerical facts. From scottaaronson.blog/?p=7094#comment-1947593 It first gives some correct info about Fibonacci numbers, but then it says: "Two consecutive natural numbers that have the same parity are 8 and 9, both of which are odd" — PM 2Ring Apr 18 at 3:41
@冥王Hades Evidently, it is $\phi$
@leslietownes Plenty of garbage there! Wrong univ and totally wrong research,
half or your second value
20:48
LOL @PM2.
So ChatGPT can’t read google?
When doing stuff with pentagons & decagons it's surprising if phi doesn't turn up somewhere.
ted: and it only generated that after i asked who "ted shifrin, differential geometer" was. before that it claimed that it didn't know you.
i'm trying to see if i can get it to describe your career in PDE.
> Ted Shifrin is indeed a notable mathematician, known for his expertise in partial differential equations (PDEs). He is a professor of mathematics at the University of Georgia and has made significant contributions to the field of PDEs, specifically in the areas of geometric analysis and nonlinear equations. Shifrin has published numerous research papers on topics such as the regularity theory of PDEs, harmonic maps, and minimal surfaces.
got the uni right that time. it really wants you to work on minimal surfaces.
@TedShifrin Well, the premium version can use plug-ins to do internet searches, and consult with Wolfram Alpha, etc. But the free version of ChatGPT can't do that. It can't even search the training data that it was fed.
it's sort of interesting. it'll push back if i ask for who "ted shifrin, famous chef" is, or who "barack obama, PDE expert" is. but it will return any ted shifrin fake math history i ask.
from this kind of thing, you sort of get a sense of its 'horizon' for generating text from stuff.
It's "digested" that training data, but it doesn't retain a verbatim copy of that data anywhere. All it can do is construct sequences that are statistically similar to that data.
After the initial training, ChatGPT went through a process called RLHF: Reinforcement learning from human feedback. That modifies the probabilities to make ChatGPT "nicer". It (mostly) stops it from saying evil or nasty stuff. The people involved in that training process say it was very emotionally taxing having to judge all that raw GPT output.
21:10
One paper with PDE in it, but get it to complex algebraic/intrgral geometry :)
I have never even encountered ChatGPT, let alone tangled with it.
@PM2Ring I see. I guess it's more about people interpreting it wrong then.
@Jakobian Mostly. It's a very impressive language processor. Unfortunately, the hype from OpenAI leads many people to believe that ChatGPT is more than just a fancy sentence generator.
21:26
@robjohn yeah I kinda thought that’s what it’ll be
it’s an annoying, annoying problem
@PM2Ring Interesting!
I should go back to being Goku again. I am no Hades the way I act and goof up often
I've never played with ChatGPT directly. But a couple of weeks ago it was available on Stack Overflow, via the Formatting Assistant experiment. meta.stackoverflow.com/q/425162/4014959
> The question formatting assistant will suggest edits to format code and fix grammatical errors, including typos. The intention is to enhance the quality of questions by providing suggestions during the question-asking workflow
As you can see, the experiment was a fiasco. And the people on SO meta were not pleased to have a ChatGPT experiment running in the middle of a strike action over generative AI policy...
21:42
💀
I see now that some prominent MSE folks, like Moishe Kohan, have added “on strike” to their names in solidarity.
Several former SE staff members who are still active on the network have signed the strike letter.
A lot of us peons signed.
SE Inc have proposed a new site, dedicated to prompt engineering for generative AI. Many of us think that they should resolve the strike issues before attempting stuff like that.
"we believe the timing and the subject matter are right" You're announcing a major GenAI initiative in the middle of a strike on GenAI policy. The timing is obnoxiously insensitive. — PM 2Ring Jun 20 at 20:56
I'm still getting upvotes on that comment.
I concur,
I didn’t find your comment, but clearly you have company.
21:54
Just click on the date at the end of my comment. That will take you to the original.
@PM2Ring 💀😂. This is such an obvious attempt at trolling even I’m blushing
I should've expanded that comment into an answer. I probably would've scored a few points. Oh well. ;)
@PM2Ring I done did that.
Ah, got it. I missed the top comment :)
Man what a troll attempt
I’ve only seen stuff like this when I was on discord
It's hilarious. He says "why are you being so harsh? This AI thing has nothing to do with the strike?"
22:01
Like I said, troll attempt. They’re just saying “hey I know you’re mad at us for screwy AI policy…anyway, here’s a website dedicated to improving AI even more”
the 9000 series is the most reliable computer ever made
How do I look?
Contemplative
Elegant aren’t I?
My lecture notes make the following claim about power series:
> if $s(x)=\sum_0^\infty a_nx^n=\sum_0^\infty b_n x^n$ for all small $x$, then $a_n=b_n$ for all $n$.
I'm confused about the "small $x$" remark. I have learnt that the coefficients are given by $a_n=\frac{s^{(n)}(0)}{n!}$, but why "small $x$"?
22:15
well, one way to conclude that two functions have the same derivatives at 0 is to know that they are the same on an interval around 0
i'd interpret "for all small x" here to mean "on some interval containing 0"
ok, so a neighborhood of $0$
which would be enough for you to be able to recover the sequences a_n or b_n by differentiating the resulting function
yeah
22:30
When someone beats me in a math contest^
plot armor
Hades’ death truly was just plot armor. The guy had no reason not to win and destroy Athena and her 5 Saints. He had already killed the strongest Saint, Pegasus Seiya, anyway

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