Okay. Seems like I got something:
$x^2y+y^3=z^2x \rightarrow y(x^2+y^2)=z^2x \rightarrow x^2+y^2 = \dfrac{z^2x}{y} \rightarrow \dfrac{z^4x^2}{y^2} +z^4 = a^3z \rightarrow z^3=\dfrac{a^3y^2}{x^2+y^2}$, so I took $x=\cos t, y= \sin t \ \rightarrow z=a\cdot (\sin t)^{2/3}$. Therefore, we get the integral $2a/3 \int_{1}^{\pi/2} \cos t (\cos^2 t - \sin^2 t)/\sin^{1/3} t dt$. Is that right?