So, if I have understood correctly, in this case it suffices to say that since $f:\mathbb{R}^2\to\mathbb{R},\ f\begin{pmatrix}x\\ y\end{pmatrix}=x^3+y^3,\ Df\begin{pmatrix}x\\ y\end{pmatrix}=\begin{bmatrix}3x^2 & 3y^2\end{bmatrix}$ the equation of the tangent line is
$$
Df(\mathbf{a})(\mathbf{x-a}) =0 \Leftrightarrow \begin{bmatrix} 3 & 12\end{bmatrix}\begin{bmatrix} x-1 \\ y-2\end{bmatrix}=0\Leftrightarrow 3(x-1)+12(y-2)=0\Leftrightarrow x+4y=9
$$, right?