« first day (4080 days earlier)      last day (1239 days later) » 
00:00 - 20:0020:00 - 00:00

20:00
I don't have the appropriate background to work out the example alone
But you can do the rest of the paper?
But it's just an example
Some parts, I don't have the arrogance to say that I'm good in 3-manifolds
when it gets in technicality I agree that I don't have the backround but I was more interested in the algebraic flavour of the paper
Think about $(p,q)$-curves on a standard torus. That's where the slope terminology comes from.
I mean if you have any reference book I will be delighted to stop bothering you
but I only know hatcher from Algebraic Topology and his 3-manifold notes are quite an advanced starting point (at least for my pov) and don't even cover this topic
while Munkres is "too easy"
This is more geometric topology, but regarding the terminology think through what I just said above. As I said, perhaps @Balarka can help you.
20:07
What has Balarka been up to lately anyway?
He's well into graduate work now, plus making presentations as usual. Not clear to me what field he's going to actually settle into completely. But he's certainly more of a geometer than algebraist :)
What have you picked, Demonark?
It's kinda, analytic number theory/dynamical systems?
Ah, cool.
I don't quite have a problem yet, I've been lately learning the work of Lindenstrauss on a problem known as "quantum unique ergodicity"
Ergodicity?
Ha, I nailed it.
20:12
Yeah that was a good call haha
is there any generalization of in-betweeness that doesn't require case work? e.g., in $\mathbb{R}$, $s$ is in-between $x,y$ if (and then we have two cases) if $x<y$, then $x<s<y$, and if $y<x$, then $y<s<x$
I've basically got the outline of that proof up to 4 black boxes. Lindenstrauss showed that if $\Gamma$ is a certain kind of lattice in $SL(2,\mathbb{R})$, and $\mu$ measure on $\Gamma\setminus SL(2,\mathbb{R})$ which is invariant under geodesic flow, satisfies some "Hecke recurrence property" (not entirely sure what this means), and whose ergodic components wrt geodesic flow have positive entropy
Then $\mu$ is just the "Haar measure"
And my advisor said to focus on understanding how he proves the positive entropy hypothesis, and that hey may have other problems along those lines
@shin Why introduce inequalities at all? Think about line segments as you asked earlier.
Demonark, but how many purple boxes?
@TedShifrin i'm trying to find a way to do that, and to prove this implies there exists an analogous 2-case proof with inequalities. i'm guessing there must be such a general proof out there in terms of order properties of the real line
Who knows? Who knows...
20:20
Has anyone heard from Eric(o) in ages?
i'm guessing that somehow, line-segment space has a specific property that makes proofs in it also hold on the real line with negative numbers
Talked to him not too long ago. Math has kinda been slowing down, covid very much didn't help
But now it seems he's trying to get back in the game
Good. I hope so.
@shin it holds in higher dimensions, too. Why are negative numbers relevant?
oh, right, signs aren't relevant here, thanks hehe. I'm trying to get at the idea of direction, somehow. for instance, the proof that $\frac{1}{2}(a+b)$ is in-between $a,b$ requires that we first do a proof supposing $a<b$, and then another supposing $b<a$. but these two proofs are so similar, there has to be a way to do them both in a single shot with a more general notion of direction
Also been toying on and off with whether or not to do an internship this summer. On the one hand I don't want to lose too much research time, but on the other hand I should have some kind of prep for industry there so I don't risk getting caught with my pants down come postdoc apps
20:25
Note that $\frac12(a+b) = a+\frac12(b-a) = b + \frac12(a-b)$. It's the midpoint of the line segment, whichever way you go.
What you want to think about is $\lambda x + (1-\lambda)y$. As $\lambda$ varies you get the entire line. When $0<\lambda<1$, you are in the line segment joining $x$ and $y$.
One of my former students who finished his PhD at UCSD in applied stuff got a job making $200K+$ from a company he had interned with one summer!!!!
Yeah, in particular an undergrad I know here interned at Jane Street and is coming back next year for a job, I applied for there and am currently waiting to be scheduled for a phone interview
oh! right, leslie too had mentioned the formula for convexity
I'm a bit further out and obviously I want to give academia a completely serious shot first since that still feels like what I would want to do
Affine geometry is very cool, @shin. With more points, you get all sorts of interesting things. You can see a little bit of it if you go to my profile and from there to my webpage and click on my MAA lecture. Part of it was on these things.
But part of me hopes that, esp if my undergrad friend is right that the place he interned at is just 9-6 and that's it, you don't bring your work home with you
20:30
I always wonder when people make that claim.
Then hopefully it'll mean I can make some kind of research progress this summer even with the internship, so that way I'll hedge my bets a little
Yeah it's a surprising claim given the pay of the position. Though I guess if it's trading you can only really do it when the market's open
tidbits of geometry through the ages?
Yes, @shin.
i'll be reading that, thanks for the reference!
One of the sections is about affine geometry and some cool applications.
You can also see how Archimedes would do a very hard calculus volume problem :P
20:32
I don't know if that's the most interesting direction I could go, compared to e.g. data science. But if he's not wrong about the work not creeping home too much, then hopefully it's not disinteresting work, and it gives me free time to have a life out of my job lol.
A heretofore novel concept.
there definitely are jobs where you get fired if you take it home with you. some trading stuff might be like that.
if they take your cell phone, wrap it in tin foil, and lock it in a lead safe every time you show up in the office, you probably are OK if you're out of the office. we should all get jobs like that.
Although sometimes it got tedious, I felt like grading homeworks and exams was an integral part of my effectiveness as a teacher. Of course, I traded off some research productivity for that.
Anyway I'll get back to work so see you around!
Ta ta.
20:45
0
Q: Constructing an $n \times m$ game with only totally mixed equilibria

user76284Recall that a strategy is totally mixed iff it assigns a strictly positive probability to every pure strategy. A profile is totally mixed iff every strategy in it is totally mixed. Hereafter, let game refer to a two-player zero-sum normal-form game. The problem is this: Given $n$ and $m$, constru...

Any ideas?
@leslietownes working at the morgue
the only fun in funeral is the first 3 letters
someone gave me an alternative definition of betweeness that gets rid of casework: $(s-a)(s-b) < 0$
messed up the sign hehe, fixed
shintuku, this casework, how much work have you put into getting rid of it
20:55
must generalize
spoilsport
can't live in particularity
plus i wouldn't believe you if you told me there isn't a space generalizing this notion
but it is also a recurring feature in real analysis
there's always something that generalizes something
this has to be like the third time in real analysis i encounter case work that is so similar, there must be a general notion
some of the arguments in euclid's elements implicitly rely upon notions of betweenness that are not made explicit in the text. you can axiomatize those, hilbert offered one set of examples
for R and stuff based on R, you could see it as arising from the trichotomy property of the order relation
or ordered fields in general i guess
all of this is a special case of the infinity-pushout of the cohomology of cohomologies of a derived co-group
21:04
although i do not know what "infinity-pushout of the cohomology of cohomologies of a derived co-group" means, it looks like the sort of thing of which most things are a special case
another nice definition: $s$ is in-between if $|x-s| + |y-s| = |x-y|$
order theory looks fun, i need to find an application to agricultural economics to justify studying it
Hi, @Amin.
@SMCnotSvenMagnusCarlsen Have you ever seen the picture of a Siefert surface of the trefoil knot?
21:34
Hi, a @Balarka
Hi @Ted
Hi @Alessandro
Long time no see, what are you up nowadays?
Trying to understand Gromov right now
21:45
Oh I just saw your dc
Yeah but that's not the Gromov I'm trying to understand now :)
Although we could try sometime.
Hi demonic
Hi Ted
So what kind of Gromov are you trying to understand now?
This continuous sheaf junk. I'm back to reading Partial Differential Relations.
A student here gave a short talk on the Benjamini-Schramm conjecture recently, do you know about it? It sounded like something you might like to me
21:48
Is that the one about planar percolations
Uhm maybe. I guess that technically that's a percolation. The one about amenability iff the probability of having many infinite connected components or one are distinct
Ah OK.
I remember that one
It's known that amenable graphs have two phase transitions (aka, the forward direction), right?
I remember presenting that proof, unless I am misremembering.
Uhm I forgot which one, but one direction is known
Bet it's amenable => two phase transitions.
Bet all my money
Wait, amenable should mean there is ONE phase transition
Right sorry, nonamenabe iff they are distinct
21:54
Right.
The other direction is known for hyperbolic things iirc
Easiest to think in terms of trees, the easiest nonmenable guys; they obviously have many percolation clusters at criticality.
@AlessandroCodenotti I think that was a major theorem lol
Like, last few years
Yes it's quite recent
I don't know how big that was though, this is all very far from my area
If you have a lot of percolation clusters with positive probability then it has to be amenable, otherwise you'd be able to tube these clusters to a single point with low cost (aka probability)
I need to revisit Lyons-Peres. I need to do infinitely many things.
I also have a billion things to read, why is there so much interesting math
22:09
It's ridiculous that people are actually able to prove new theorems
It'll take me a lifetime to read everything first
I think there are no new theorems, everything is done by Gromov, one just has to read him correctly to recover the theorem.
@BalarkaSen You don't need to prove new theorems, you can publish papers by filling in the details in Gromov's sketches
lol
apply the gromomorphism as they say
Anyway I'm off to sleep, I've become an old man, can't do math all night long anymore
Good night!
@AlessandroCodenotti As Gromov said, "Ven I vaas yang I could do mathemaatiks for 24 aaours, now I am old, only 18 aaours."
If @Alessandro is an old man, I am dead and buried.
@Balarka What language are you trying to transliterate there? Doesn't seem like either French or Russian to me :D
Chern once told me to stop reading mathematics and just do it. There's merit to that advice :P
22:20
It's a mix for Gromov, isn't it?
Some odd mixture of French and Russian.
Yes.
That's why your pseudo-Dutch perturbed me.
Oh lol I guess it does look Scandinavian
With all the v's and double a's.
nods innocently
i read it in bela lugosi's voice
or the count from sesame street
That is too lugubrious for Gromov.
22:29
lol
tomorrow is the moment of truth at the orthopedist
I hope that goes better than my failed $75 vet visit!
22:47
@TedShifrin Once upon a long time ago, you gave me a lot of trouble for conflating the $k$-fold iterated tangent bundle $T^{(k)} X$ with the $k$-jet bundle $J^k X$. Do you remember what your main distinction between these two was? You and a fellow user pointed out that they fundamentally have different dimensions.
I think this isn't quite it because these are obviously different object. $J^1 X$ is $T^*X \times \Bbb R$.
Trouble? Jets are jets of functions, whereas the iterated tangent bundle is intrinsic to $X$, but I don’t remember our conversation.
Well, here's the question. What's wrong with defining a $k$-jet as a section of $\pi^{(i)}: T^{(i)}(X \times \Bbb R) \to T^{(i)} X$ for each $0 \leq i \leq k$, all compatible under the various projection maps $T^{(i)} X \to T^{(i-1)} X$, $T^{(i)} (X \times \Bbb R) \to T^{(i-1)}(X \times \Bbb R)$.
A function is just a section of $X \times \Bbb R \to X$.
IIRC you said dimensions don't match.
23:05
just googling to learn these words i stumbled across math.stackexchange.com/questions/1383782/… where in the comments there's a link to a paper comparing 2-jets and the 2-iterated tangent bundle in some situation.
there's even a dimension count in the abstract. it's all nonsense to me.
elements of T^(k)M should be called k-sharks.
lool
Iterated tangent bundle is a very bizarre and nonstandard thing to do, I would like as much as possible to avoid thinking in terms of these crazy objects.
I have no recollection.
No problem, thanks though. I will try to get around this stuff.
I have the higher-order tangent bundle and its Chern classes in one paper.
Oh, interesting
23:13
I do think crossing with $\Bbb R$ and taking higher-order bundles will give too high a dimension.
Likely many terms will be repeated, though, because $\partial^2/\partial x \partial y = \partial^2/\partial y \partial x$.
But even if there's an isomorphism somewhere it cannot possibly be natural.
No, those don’t appear separately.
Interesting comments in the link leslie just found.
Why not? $T^{(2)} \Bbb R^2 = T T \Bbb R^2$ to me.
There certainly these terms appear separately.
Oh, your $T^{(k)}M$ is equivalence classes of maps from $(\Bbb R, 0)$ with all the $k$-order derivatives being kept track of at $0$.
That's not the guy I'm thinking of, I'm just doing $T \cdots T M$, dumb man style.
Got to get to bed, see ya.
23:42
Ted do you know where I can find a good worked out computation of the multivariate gaussian integral (Do you do it in your book)?
we're back to the scary strawberry with paws.
@joe: is math.stackexchange.com/questions/126227/… at the level of generality you need?
@JoeShmo You mean why $\int_0^\infty e^{-x^2}\,dx = \sqrt\pi/2$?
It's derived from polar coordinates. Yes, in my book (with rigor, even).
@Balarka: Ah, that's not how I defined higher-order tangent bundles. The original paper, as I recall, was another Chern student, William Pohl. Here you go.
00:00 - 20:0020:00 - 00:00

« first day (4080 days earlier)      last day (1239 days later) »