people are more likely to get salty when one asks for something to be solved without saying anything about what they've tried or not tried. it's sometimes also helpful to provide context about where it's coming from, for example, so a person doesn't give an answer using methods that you don't 'have access to' in a classroom setting.
if there's some obvious thing to try that doesn't work, it's sometimes helpful to point that out too, so you don't get junk comments/answers from people who haven't thought all the way through
Copper is a chemical element with the symbol Cu (from Latin: cuprum) and the atomic number of 29. It is easily recognisable, due to its distinct red-orange color. Copper also has a range of different organic and inorganic salts, having varying oxidation states ranging from (0,I) to (III). These salts (mostly the (II) salts) are often blue to green in color, rather than the orange color copper is known for. Despite being considered a semi-noble metal, copper is one of the most common salt-forming transition metals, along with iron.
== Copper(0,I) salts ==
== Copper(I) salts ==
== Coppe...
@XanderHenderson my family used to call me tin hat (so the aliens could notread my mind) and i pointed out that copper is a better conductor, hence the name.
I am a physicist trying to calculate the lineshape $f_2(\nu)$ for the oscillations given in a new dark matter model; the entire problem at the end can be reduced to calculating a convolution,
$f_2(\nu) = \int_{-\infty}^{+\infty} f_1(\phi)f_1(\nu + \phi)d\phi$,
where
$f_1(\nu) = \alpha e^{-\beta \...
@Gyromagnetic Well, my guess is that there's no elementary expression. But the problem doesn't make sense. You have $\phi$ ranging over all $\Bbb R$, so square roots won't be defined and integrals won't even converge. Care to revise?
@leslie I agree that I occasionally go back to an old answer and try to improve it, but generally I try to improve the exposition or mathematics if I'm going to disturb it.
he may not be aware that a one-character edit bumps the answer. if you filter what you look at by topic or other things you may miss how often it happens on the main page.
i don't know why i'm playing public defender here. the power washers are on their lunch break. i should be productive.
this reminds me i should edit my linkedin profile to remove my essay about how hollywood is run by the CIA. it didn't get me any likes. the truth hurts i guess.
You can add an essay about how a certain group of politicians is about to make the whole country and economy implode. In addition to my usual complaints.
@TedShifrin would it be different if phi was only positive :)? might've screwed up, in principle because of physics-related arguments one can say that phi cant be negative
Yeah, if $\phi$ is positive (or is bounded below), then the integral converges. But, regardless, I highly doubt an explicit antiderivative can be calculated. And I don't offhand see any obvious complex analysis approach to it.
But, more seriously, you need $\phi\ge\delta$ for the square roots to make sense.
@TedShifrin A decade ago, I had a student tell me that I should invest in bitcoin (this particular student had some integer > 1 number of bitcoins). I said "that looks like a speculative bubble and/or scam" (when 1 bitcoin was on the order of $50).
please, Let P=Dt Q+I with Q=(q_{ji}) is generator matrix, I is an in finite dimensional identity matrix, and $P=(p_{ji})$. I would like to show that P is positive matrix, which means all the entries of P are nonnegative. given that $(1+q_{ii}Dt)>0$ and all the elements $q_{ii}$ are finite. but I m stuck here $p_{ji}=\Delta tq_{ji}+1$
@Mohcine What does "generator matrix" mean? Obviously, you need all the entries of $Q$ to be nonnegative if that's what you mean by positive matrix. For small enough $\Delta t$, it will be positive in other ways, but you need to know your own definitions.
So, I'm grading other graduate students this semester, but some of the attempted arguments I'm seeing are so nonsensical that I'm bewildered. I had someone try to say that $(AB)^T=B^TA^T$ because their domains and codomains matched
No other reason given
It's making me wish that I had hair so that I could pull it out
It's linear algebra (a breadth course, so all grad students end up taking it or a similar course, regardless of focus), and I've seen the same question in undergraduate classes, yeah
Yeah, that's the definition they're supposed to use. Most students are just making the mistake of treating the transpose as if they transformation were a matrix
It would be nice if the homework assignment made such things clear. Oh well. I always had issues with this teaching proof-y courses. What can we assume in homework or on an exam, what can we not assume?
Obviously, if I ask you to regurgitate a proof of something in the book or done in class, you can't just say, "It's in the book" or "we did this in class." But if it's a different result, then it's fair game to use what we've proved in class. Pretty subtle, actually.
Yeah, I get that. I tend to go a little bit overboard when I write proofs, myself, to avoid getting caught on that. But now that I'm grading, when I see a proof that goes a little overboard, there's a voice at the back of my brain saying "Oh no . . ."
far better to just use the fact without proof than offer 'domains and codomains match' as an 'explanation', imvho.
if you're gonna go overboard, style it out with confidence and do not offer explanations. don't make me question whether the understanding is all a house of cards
Which integers m do you think can be written as m = s(n) for some n? (In mathematical language, when is m in the range of the function s?)If m is in the range of s,how many different n have m = s(n)?Is the number finite or infinite?
(From Stopple analytic number theory)
$s(n)$ is the sum of the proper divisors of n
Is this just me or this question is insanely hard? I have that the image is infinite, but nothing else