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00:12
@OldJohn Hi! Old John!
Hey Ted, if you happen to have the will to help me understand the above, I'd be glad :)
@MinaMichael No, unless $A$ is either symmetric or skew-symmetric. In your case, no.
I think I figured it out. The expression turns out to be a scalar. So A^T = A. Therefore A^T+A = 2A. ...should be 2a actually.
So you are assuming that $A$ is symmetric
No, it is not a scalar — it is $n\times n$.
@Astyx: The residues are rational functions of $t$, no?
00:18
@Astyx the conditions ensure that it's regular + rational = algebraic?
f(z,w) is regular so f(ζ,t/ζ) is algebraic in t
(but not in ζ)
@AminIdelhaj A is a scalar.
1x1 matrix.
You are wrong .
Oh... that would've been relevant info
Why are you bothering with treating scalars as 1x1 matrices? Just some weird special case of something?
It is NOT!
Read his silly question carefully. I'm fed up with people who do not read.
@MinaMichael Is there context I'm missing? I assumed he just started adding assumptions after. I'm reading starting from here
00:22
Unless $a$ And $b$ are scalars, in which case why write transposes at all!
$ab^\top$ is not $b^\top a$.
I mean the whole situation is kinda nonsense so when he said "A is a scalar" I assumed it was an assumption he forgot to tell us
He is making a stupid mistake.
Unless these were never vectors and he's wasting our time entirely.
I've actually made another mistake. The expression is (a^Tb)^T+(a^Tb). a and b are in R^n.
They're vectors
@TedShifrin I thought so, but apparently they're not because there is an equivalence "algebraic iff of this form"
a^Tb is a scalar.
A scalar is equal to its transpose.
That's it.
00:27
Why are you using transpose on scalars? Maybe the very original context would be nice to know
You are wrong. That is not what you typed before. Look carefully.
...a and b are vectors.
Because this is a bizarre situation with hidden assumptions
No, Demonark.
I think I didn't state all the required facts. Because I didn't know they would resolve the issue.
00:28
You are not reading what I say. You are wrong and I quit.
2
@Astyx ... Leaky said the next step. The integrand is regular inside, so regular in $t$.
This: (ab^T)^T+(ab^T) is nxn. This: (a^Tb)^T+(a^Tb) is a scalar. Right? I made another mistake in the beginning saying that the expression is (ab^T)^T+(ab^T). It's not. It's (a^Tb)^T+(a^Tb).
I'm working on it
But if we treat the expression as just A^TA where A is a scalar then we reach the conclusion.
Well, gee, great. Type the wrong question and never say you changed the question. Very helpful.
I didn't state the dimensions of a and b in the beginning. What if they were row vectors?
00:32
Row vector is transpose of a column vector
No one writes vectors as rows without saying so explicitly.
Anyway yeah Mina when you're asking questions like this please be completely clear lol, it gets messy
Mathematica does, but I hate that mathematica does
What else is up with you guys?
00:33
@TedShifrin I see. Okay. That might be the source of confusion I guess.
Hey Semi what's up
@AminIdelhaj The proof is large. I tried to state what's relevant. I wouldn't state the whole problem. ...the issue was that I didn't know where to look.
@Ted are you familiar at all with the Selberg trace formula? That's kinda the piece of math I'm hoping to start learning now
Is it obvious that regular + rational => algebraic?
00:48
Demonark, zero.
I would say polynomial. Where can roots come from?
Maybe more context is needed.
what does algebraic mean actually?
There's a polynomial with coefficients in C[z] that cancels f
$P(z,f(z))=0$
01:05
oh i misunderstood then
pardonne je n'ai pas le temps
Pas de soucis
@Astyx, if you want to email me more context, I will think about it later :)
01:44
cookies!
will someone get leslie some cookies?!
@Semiclassical actually, I believe the default is columns, but if you multiply a vector on the left of a matrix, it will take the transpose first.
Of course, entry is as a list, so horizontal
yeah, i'm stretching it a bit
basically {a,b,c} and {{a},{b},{c}} are the same thing to mathematica
whereas {{a,b,c}} is the row vector
Yeah, so {a,b,c} is a column vector. I can sleep undisturbed tonight.
The prosecution rests.
fine, fine
it is sorta funny how column vectors are the default tho
i guess it's just a prejudice of matrices acting from the left
02:00
Why? Precisely. Unless you're Herstein.
Functions act on the left ... unless you're Herstein.
That said, following Chern, I did a lot of moving frames stuff with rows and right actions.
yeah
it is amusing to me how many little binary conventions like that we just take for granted
@TedShifrin Hi
Hi @AminIdelhaj
02:11
@AminIdelhaj How is everything haven't seen you for awhile
I've been doing alright, a bit tired
How about you?
Good I am about to publish my first publication
Ooh nice, what on?
Hodge theory
Complex geometry and Hodge theory
That's cool, congrats! :D
02:13
Thanks still doing edits
I am currently studying from this book and other books
Nice, eventually I'd like to look at Hodge theory a bit so I'll keep that in mind!
Yeah it is great
03:06
How to solve this..
Please tell the technique i words
in*
I am getting 195 as the answer
I calculted it as (5/8)*520
5/8 is greater than 1/2 and 1/2 of 520 is 260
something is amiss
no idea how that relates to the image you posted. I can't read it.
based on the wording of the problem, it's not at all apparent why years 2012-2015 are relevant
ok...
My interpretation may be wrong..
to be clear, what is your interpretation?
your solution could be correct for how you're reading the problem, but not match what the problem intended
that said, i seem to get an answer of 220
@Semiclassical I am unable to frame the equation.Can you assist me with that..
03:16
not until you tell me how -you- framed yours
ok sure I am sending you my solution
though i will say that i'm interpreting their 5:3 condition in a specific way: that the ratio of "people who -only- failed X" to "people who -only- failed XII" was 5:3
Yes correct..then
otherwise the 5:3 ratio doesn't make sense with the "530 passed X and 400 passed XII" assumption
I told in my preious chat what i basically did..
03:19
or does it, hmm. it's possible i'm misinterpreting it as well
I believe that the question implies, though rather poorly, that the same number of people passed each exam.
yeah, that's what i'm assuming too
Yes @robjohn I interpreted that before also
So what do I extract from this...??
sure. so how did you set it up
without that assumption, I don't think the problem can be completed.
03:21
the main conclusion I draw is that trying to solve word problems is hard enough in a language you know
Ok wha do I do after the assumption..
Write out a formula for how many people passed each exam.
it's even harder when trying to solve a translation
@robjohn i really do not know..
you knew enough to come up with an equation
what did you do to come up with that equation? i don't care if it's right or not
03:22
you know the ratio of the number of people who failed each exam. Use that
Yes but I am unable to use that..
Why?
A slight advice is most certainly welcome...
given that you're not saying a word about what -you- think about the problem, i'm not inclined to say more than i already have
If you know the number of people who failed X, then how many people passed X?
same for XII
03:25
@Semiclassic He shows up day after day with this same stuff.
We've turned into an international "do all my exam preparation" website.
I am getting 195 as the answer
I calculted it as (5/8)*520
This is what I did
Okay. -Why- did you do that?
I told you earlier from total I just figured out the fraction..
as I said, 195 is not 5/8 of 520
03:27
because that's not how fractions work???
Sorry 325
Even then it is wrong..
Hmm calculates 520/8 = 65
as a quick verification as to why it's wrong: if 325 passed both exams, how many would have failed each respectively?
Yes certainly not equal...
But ho do I exploit the fact that number of students who passed is equal.
how*
answer my question first. if 325 had passed both exams, how many must have failed X and failed XII?
blah, i need to stop typoing
03:31
195 and 75 respectively..
For X and XII
right. which isn't 5:3. So now: if P had passed both exams, how many must have failed X and failed XII?
What do you mean by P had passed both exams?
P passed X and P passed XII
well, you don't know how many passed, do you?
better follow the practice of ages and introduce an unknown variable for it
No I do not
ok.I will do that..
03:36
so if P passed both exams, how many failed X and how many failed XII respectively?
I really do not understand please tell me if there is catch..
then you're not listening. you correctly inferred that, if 325 passed both exams, then 195 failed X and 75 failed XII
now replace 325 with some unknown P.
there any way to talk about natural numbers as objects that represent finite bijections in some yoneda sense?
@BigSocks so like...some equivalent of Godel numbering for bijections?
03:40
I don't think that is what I had in mind
 
1 hour later…
04:48
@robjohn look who dropped by
6 hours ago, by Old John
Great. I can't stay right now, but I will be back in less than 6 years!
somebody just responded to one of my posts on math.SE from almost five years ago.
coolio; favourably, i hope
they want a generalization.
link please
04:54
thanks
I don't even know what that means.
in april 2016 i lived about two miles from here. i didn't have my cat or my daughter. i wasn't even married! it was a simpler time.
+ no pandemic
was that pre trump?
yes. what a time
ye good olde days
05:03
on balance i like my cat and daughter. it's better now.
So what is that comment even asking?
i don't know.
Fair enough.
i'm guessing that a rational approximant of "type" (m,n) is a quotient of polynomials p/q with p degree m and q degree n. just guessing. what else would it be.
my daughter has a nasty cough.
05:28
@leslietownes that's known as a Padé approximant
(which is about all that i know about them)
did you ever straighten out your students on unit cancellations? @Semiclassical
who knows
05:57
For divisibility what are the golden rules that I should kkep in mind..I know only for 2 and 3.2is even..3 is sum is divisible by three
if anyone can add up to the list it would be extremely kind of you..
If $a$ and $b$ are integers with $b \neq 0$, then there is a unique pair of integers $q$ and $r$ such that $a = qb + r$ and $0 \leq r < |b|$............there is your golden rule
I am asking about the calculated golden rules....That is what I am most worried about.A slight mentorship in the direction will be very helpful..
There aren't really any that you "should" keep in mind and it's not worth worrying about them (unless it's for an exam or something). Also there are plenty of lists online.
06:26
hello SE math chat
Have you seen the guy who is in the math problems?
 
1 hour later…
07:32
I am unable to follow up this approximation a help in this direction is very much welcome..
07:56
How did they round things off..
08:37
@RajorshiKoyal (476,119/780,966) X 100% = (476,119/780,966) X 100 X % = (47,611,900/780,966) X % = (47,611,900/780,966) X % (47,61---1,900---/78--0,966---) X % = (4761/78) X % = (4760/78)%
Why four digits in the numerator and two digits in denominator
the numerator is first multiplied by 100
leave the % as is
100% = 100 X %
because % = 1/100
per cent means per 100
(47,611,900/780,966) X % = (47,61---1,900---/78--0,966---) X % = (4761/78) X % = (4760/78)%
09:05
Ok got you thanks for the help
@user85795
09:38
@user85795 Thanks a lot for responding.
09:51
How to find the general term of this sequence?
$x_{n+1} = x_{n}^2+1/4, x(0) = 0$
This is a recursive definition, I want an explicit formula
What is the symbol for two lines to be collinear ?
if two lines are collinear then they are the same line so you can just use =
@user85795 OMG! I haven't seen him for ages!
jay
jay
10:08
Anyone know where I can find the proof that if I consider the solution to $\partial_t f(t,x) + div(f(t,x)) =0 $ with initial condition $f(0,x)=f_0(x)$ then at time $t$ the solution $f(t,x)$ is the push forward by the flow of the vector field $v$ ?
sorry the continuity equations should read $\partial_t f(t,x) + div(f(t,x)v(t,x)) =0 $
Nov 28 '15 at 22:54, by Old John
@robjohn Will drop by again soon - right now, I have to go, I'm afraid
@user85795 This was his last message to me
so, soon was over 5 years.
Oh god.
My eyes.
10:27
0
Q: Solution of $uu_x+u_y = -\frac{1}{2}u$ and understanding existence and uniqueness theorem for first order PDE

love_sodamI want to solve PDE $uu_x+u_y = -\frac{1}{2}u$ with initial condition $u(x,2x) = x^2$. To solve this, I first tried characteristic method but I found it's hard to change the coordinate back to $(x,y)$ so alternatively, I'll use Lagrange's method. First the initial condition: $x(0,s) = s,y(0,s) =2...

Anyone can answer my pde question?
 
1 hour later…
11:32
@LeakyNun K. Thnx
12:18
1
Q: Approximating $f/|f|$ using compactly supported functions.

JakobianLet $A\subseteq \mathbb{R}^n$ be open and $f:\mathbb{R}^n\to \mathbb{R}^m$ be $\mu$ locally integrable, where $\mu$ is a Radon measure (on $\mathbb{R}^n$). How to construct compactly supported continuous functions $\varphi_k:\mathbb{R}^n\to\mathbb{R}^m$ with $\text{spt}\varphi_k\subseteq A$ and $...

is there anyone knows existence and uniqueness of first order PDE?
12:52
yes but I forgot it after car accident
@love_sodam What does that mean? of solutions of PDEs ?
13:17
ж
д
дддэ
@Astyx Yes existence and uniqueness of solution of first order PDE
How many variables ?
13:35
two $u(x,y)$. PDE is of the form $F(x,y,u,u_x,u_y)=0$ and in my case $a(x,y,u)u_x+b(x,y,u)u_y = c(x,y,u)$
My question in the above statement is if the transversality condition on an interval of $s$ then the solution either does not exists or infinitely many. What is the meaning of 'an interval of $s$?' Does is mean for every $s$ where $s$ is defined? or for some $s$?
You're going to have punctuate that sentence if you want me to understand you
 
2 hours later…
15:46
i see that as saying, if theres some interval (a,b) in the domain of definition, with the property that the transversal condition fails for all s in (a,b), then blah blah
the proof of theorem 2.10 might make this clear. of course, it might not.
my cat was absolutely horrible last night. she likes bothering my wife. she'll jump onto the bed and start pawing at my wife's head, just to have a friend to "play" with.
we should have known. the shelter had sequestered her from the other cats because she would bother them too much during group play sessions.
16:50
Find the number of months which have shown a below average performance from the graph..
A slightly detailed answer is most welcome..
find the average. find the months that are below that average.
In colloquial language, an average is a single number taken as representative of a list of numbers. Different concepts of average are used in different contexts. Often "average" refers to the arithmetic mean, the sum of the numbers divided by how many numbers are being averaged. In statistics, mean, median, and mode are all known as measures of central tendency, and in colloquial usage any of these might be called an average value. == Calculation == === Pythagorean means === The arithmetic mean, the geometric mean and the harmonic mean are known collectively as the Pythagorean means. ...
usually the arithmetic mean is meant
@RajorshiKoyal You have enough information to give a detailed answer.
@RajorshiKoyal You really are overdoing it. You come and post all your questions and tell us to give you detailed answers. We are not here as your servants.

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