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00:00 - 19:0019:00 - 00:00

00:35
that 3b1b link is really cool.
I'd love to learn more about knot theory too.
I've got to dive into this Calculus text at the moment however. I'm sure to have some questions.
01:05
If F:M->N is a smooth map between manifolds and A subset of M, is the restriction of f to A (f|_A) is necessarily a smooth map from A to N?
what does it mean for a map from A to N to be smooth
that I can find a chart (U,i) U open in A (subspace topology) and i:U->R^k (some k) smooth homeomorphism
what does that have to do with the given map?
sorry. You are right I had a mind glitch. For every a-in-A I can find (U,i) smooth chart in A containing a, and (V, j) smooth chart in N containing f(a), such that j∘f∘i^1 has continuous partial derivatives of all order
*each of it's components has partial derivatives of all order..
continuous partial derivatives
01:26
then the answer is no, for the rather contrived reason that there may be points in A for which you won't be able to find any charts at all
if you make the natural assumption that A is a submanifold, everything works out, of course
Usually the notion is that there is a local smooth extension to a neighborhood of any point of $A$ (when $A$ is not a submanifold).
Is isolated points is a case sample for what you have in mind?
What is a smooth chart in $A$ when $A$ is a random subset?
With my definition, the answer is that it's tautologically true. Without my definition, it makes sense only when $A$ is a submanifold.
you can always find a chart around an isolated point, cause the point is homeomorphic to R^0 and an open neighborhood of itself
Is there a simple example where I cannot find such charts?
01:38
take the cross X in R^2
no chart around the origin
Ok I get it. Thank you
02:01
How do I prove that the derivative of a meromorphic function is meromorphic? Let $f(z)$ be meromorphic, and let $z_0$ be a singularity of $f'(z)$. I want to argue that $z_0$ is a pole of $f'(z)$. My thought was to consider the Laurent expansion of $f'(z)$ at $z_0$, and then argue by contradiction. Then either $z_0$ is removable or it is essential.
I thought that if $f'(z)$ had a Laurent expansion at $z_0$, then I could modify it (change the coefficients) to get a Laurent expansion of $f(z)$ at z_0$...But the $(-1)$-th coefficient seems to be giving me trouble...
why not just differentiate the Laurent series of $f$?
 
7 hours later…
08:43
scream boys, scream.
09:20
@AlessandroCodenotti
HoTT lecturer: "you don't need any algebraic topology for this"

HoTT proofs: literal translations of algebraic topology into simplicial sets
09:57
lol
Are you taking another HoTT course?
one can never be too HoTT
:p
10:29
ehllo
you can do a geometric mean of two functions?
nice I never thought of that
because it's usually done with numbers
10:33
functions also give numbers
it's a sort of generalizing the geometric mean
under suitable restrictions
ya
seems weird but the argument of the zeta function can be a function
under suitable restrictions
Li(x)=(h(x)f(x))^1/2
anyone familiar with logarithmic integral?
yes I always work with it
would it be good to express Li(x) like I wrote above?
i.e. as a geometric mean of h(x) and f(x)
10:38
which logarithmic integral do you mean? the logarithmic integral or the offset logarithmic integral?
offset
@geocalc33 I am not sure but I don't think such functions are possible
10:51
I'll ask on main
I doubt it's useful but now I'm curious
0
Q: Express logarithmic integral as geometric mean of two functions

geocalc33The offset logarithmic integral is defined as: $$ Li(x)=\int_2^x \frac{1}{\log(t)} ~dt$$ I want to express $Li(x)$ as the geometric mean of two functions $f(x)$ and $h(x)$ s.t. $h(x)\ne f(x).$ That is, $$ Li(x)=\sqrt{f(x)h(x)}.$$ Can it be done?

11:14
@AlessandroCodenotti nono, just the topology one, but I already see some analogies
Ahh makes sense
11:44
Hey guys listen
What is the point of functional arrow notation if $f: x \rightarrow x^2$ is same as $f(x) = x^2$? How's using the arrow any better, are there situations where it's more clear?
You'd write $f: x\mapsto x^2$
The notation $f:A\to B$ lets you define abstract functions from A to B without being specific
The first proof of the abel Ruffini theorem was 500 pages but a proof was made later which was only 6 pages long
What are other examples when a very large proof was condensed very much?
proof of the PNT
Should I ask this on main as a soft question?
11:49
oops mistake on my part
Pedantically, in order to write $f(x) = x^2$ you have to define $x$ first, whereas in $f:x\mapsto x^2$ x is a dummy variable
Please tell if there is a duplicate of this on main before I ask this.
@Astyx I'm not sure I get it. Why can't one just as easily assume x is a dummy variable with f(x)?
I mean the correct expression for $x$ to be a dummy variable is $\forall x, f(x) = x^2$
@geocalc33 can you tell how long was the original and the condensed proof?
11:53
what exactly do you mean by dummy variable, that it doesn't matter what set it's coming from? @Astyx
But you could have a function such that $f(x) = x^2$ only for specific $x$
No, I mean that $x$ can take any value in the domain and the statement holds
But it's not a big deal anyway, it's just that you have to be careful what things mean
@epic_math not sure
Is this question on main?
Should I ask this?
I could define $f: \Bbb R\to \Bbb R$, $f: x\mapsto x$ and write f(x) = x^2 for $x\in \{0,1\}$
So a reader that is not too careful could miss the "for $x\in \{0,1\}$" and be confused
The notation $f:x\mapsto x^2$ prevents that
Some people also use $f(x) := x^2$
Okay I am going to ask this. I will link the question.
11:58
Then again, it's not a big deal
0
Q: Examples of very long proofs which were condensed to a very small size

epic_mathWhile reading this article, I learned that the original proof of the Abel Ruffini theorem was about 500 pages, which was later condensed to just 6 pages. Immediately after reading this, a question came to my mind: What are some examples where a very large proof was condensed to a very small size?

I think with that whole thing on prime gaps that Zhang found a couple years back, an independent and better proof was found not too long after
I got an upvote
Lol who did that
It was not a remarkable question but yeah
Hey guys thanks for your support(the upvotes) may it get many answers
I think this is probably already a thing that was asked actually
dunno, I just vaguely remember seeing it, maybe it was on math overflow though
12:28
137
Q: Extremely messy proofs

Qiaochu YuanCurrently in my undergraduate courses I am being taught how to set up various machinery using slick, short proofs and then how to apply that machinery. What I am not being taught, largely, is what came before these slick, short proofs. What did mathematicians do before so-and-so proved such-and...

12:49
big scary subscript
from some DFT review paper
wewwwww
DFT meaning Density Functional Theory I'm guessing from the bra and ket?
13:08
Hey I got a weird question in my mind
What is the total area of the black region of the mandelbrot set?
Not an approximation, I want an exact form.
The answer is approximately 1.506484
Does anyone know what this is? ⭕️
@epic_math a
where a is defined to be the total area
yep
it's A=1 unit
exactly
problem solved
What the hell
This answer is trivial.
:'(
13:28
wait 1.506-484-4223
Gimme the exact answer
Yeahh
expanding via binary and exptrapolating Czech cocycle data I think I get...
yep, A=1 unit
And what is the area of the burning ship fractal?
A=1 unit I think
Exactly 1?
13:32
no it depends on the unit you're using
Tell me the unit, man
Okay the exact area of mandelbrot is almost impossible to calculate
So an easier question:
Area of Koch snowflake?
that should be easy to google @epic_math
With the length of the side of the initial equilateral triangle being 1️
The calculators calculate with finite iterations, I want the answer with infinite iterations.
I can myself calculate with finite iterations
The Koch snowflake (also known as the Koch curve, Koch star, or Koch island) is a fractal curve and one of the earliest fractals to have been described. It is based on the Koch curve, which appeared in a 1904 paper titled "On a Continuous Curve Without Tangents, Constructible from Elementary Geometry" by the Swedish mathematician Helge von Koch. The Koch snowflake can be built up iteratively, in a sequence of stages. The first stage is an equilateral triangle, and each successive stage is formed from adding outward bends to each side of the previous stage, making smaller equilateral triangles...
Oh the area is $\frac{4\sqrt{3}}{5}$
Easy to calculate
Very easy
Using limits
Fractals are fun
13:41
exactly
I don't think are techniques are advanced enough to calculate area of mandelbrot
See a mandelbrot zoom and then you will realize
I don't like the Mandelbrot zoom
It's aesthetic
Rather hypnotizing
yeah it's just not my cup of tea
It's my donut of tea
Tohpohlozy
13:44
it's my sphere of tea
my cup handle is broken
Means you can easily decrease the genus
Which field of math you love?
Analysis/geometry/algebra
Considering number theory in analysis
And topology in geometry
exactly
Your profile says you know all of those
Oh shit
I again fell on a mandelbrot set
Oh man
exactly
13:52
I doubt the RH has been solved
it's a pretty thorny problem
'twas but a joke
RH is insane
exactly
exactly
speaking of RH
Enjoy
Task: figure out the mistake in the proof.
13:58
how do the critical zeros differ from $\zeta(s)$ to $2\zeta(s)$
@epic_
And he handles infinity and zero without even thinking about it
Zero and infinity can never be friends.
afternoon
hello ed
hey
Heya @EdwardEvans
14:03
Hello @EdwardEvans
ed is a vip everyone greets him
@epic_math Boring, if you want the good stuff you go to vixra
The formatting of this article is horrific
2 line space is unreadable
terrible
@MikeMiller vixra is even less reliable.
How was it accepted though?
14:10
It's the general math section which has very little review
I think Arxiv articles are not necessarily accepted
@epic_math I mean you're looking at junk, I would think you would want reliably amusing junk
@MikeMiller oic
oh thanks, you found what I like
lol
@Astyx I meant, how was it accepted on Arxiv. I mean articles on Arxiv also go through some review, right?
Apparently not.
14:13
arxiv is where you go when you can't go to researchgate.
No, authors go through some review to get access (and papers are glanced at to make sure they're not gibberish, when they're not in general math)
There might be some light reviewing to check it's not a complete troll, but there isn't any peer review AFAIK
there are more RH proofs on arxiv than sensible articles.
Who cares
This is dork shit
tell about that website to mochizuki. He can publish his work there
14:14
@epic_math how about the MandelBuddha?
Oh okay. I didn't know how Arxiv worked.
@robjohn that one photo isn't real
Benoît B. Mandelbrot
@Astyx =benoit benoit B. mandelbrot mandelbrot
@epic_math pardon? what do you mean it isn't real?
14:17
I mean that isn't the original fractal.
@epic_math the alpha channel is the Manelbrot set
@feynhat does that singer even know what a fractal is?
@feynhat btw this is the same guy who composed many of Portal 2's soundtracks.
songs are shit and we are here to talk mathematik
14:19
I quickly scrolled back to 5 hours and there's still no math
@epic_math that is the Buddhabrot
Why do I even come back here
lmfao.
@BalarkaSen so?
@BalarkaSen "What is the area of the mandelbrot set"-epic_math, ~1 hour ago
balarka left immediately
14:20
It's friday
and tomorrow is diwali
oh I have math (notation)
I came up with a new math letter
can new mathematics notation be even made? Will anyone even accept it?
hey Leibniz notation stuck around
tomorrow is the death date of Leibniz
14:25
Hello everyone. Why is it that for the converse we had to define $\delta_n$ as such? Why is it that this delta in specific makes (5) false?
what are X, Y, E, f and p?
X and Y are metric spaces, E is a subset of X, f is a function from E to Y and p is a limit point of E.
We just needed a positive sequence converging to 0
Oh, so there's nothing special with this delta? I could've chosen another delta_n going to 0 and this would work?
yes
14:33
@Astyx It got me confused because this (delta_n) was somewhat specific, and it runs away from main purpose of the proof, I think. Thanks
there was a question that I couldn't solve I wanna ask it now
how can we prove this:
help please
made an ugly graph
too ugly to be in existence.
lol
what is the equation?
I asked for the equation
btw the graph is not ugly
I can see its beauty
14:50
what do you think of this one? @epic_math
beauuutiful
 
1 hour later…
16:16
Let Mn be the square matrices on R, let Gln be the non-singular matrices, a let O(n)\subset Gln be the orthogonal matrices. I am using the map F:Mn->Mn F(A)=AA^T to build smooth atlas, using the constant rank theorem, on O(n). So far I know that F has constant rank on Gln and proved that O(n) is a regular surface using the regular value theorem (restricting F to Gln and using the identity matrix as the regular value). I am stuck with building a smooth chart on O(n) with the constant rank.
1 message moved from Basic Mathematics
If someone has an idea, it will be super helpful
@MikeMiller what's the equation called that relates the Riemann curvature tensor to the shape operator?
I think it was something like $R(X,Y)Z = g(S(Y),Z)S(X) - g(S(X),Z)S(Y)$?
16:34
I dunno this stuff, sorry.
That's fine. Maybe Ted knows.
@TedShifrin is there a name for the equation that relates the Riemann curvature tensor to the shape operator? I think it was something like $R(X,Y)Z = g(S(Y),Z)S(X) - g(S(X),Z)S(Y)$?
17:33
how does one motivate hyperbolic geometry?
good question lol.
@anakhro Codazzi equations?
18:02
This is from a book in mathematical statistics, the first chapter on inference theory where estimators are explained. One would like to estimate the unknown parameter $\theta$ of a known distribution $F$. In the example, why is it that when $F$ is unknown, $\theta=F$? $F$ can be seen as a function of $\theta$ (and vice versa), but if $F$ is unknown, shouldn’t this “rule” (function) not exist, i.e. $F=F$ and $\theta=\theta$?
well your distribution has to be $F=\theta$ if you have no other knowledge of the distribution
@Thorgott Failure of the parallel postulate
Clearly there are two ways it can fail
@geocalc33 Intuitively it makes sense, but it seems that with $F=\theta$, $F$ is actually known, namely $F(x)=x$, or?
It is interesting to investigate both
What can we say if the Gaussian curvature is zero at some point?
Hmm seems locally plane
18:19
No, that would be if the Gaussian curvature was zero everywhere in a little neighborhood around the point
A torus has many points of curvature 0
(It has maximal curvature along the circle encircling the whole donut, and minimal --- negative --- curvature on the circle encircling the donut hole)
ok, my question was too imprecise
(So it must cross 0 at some point --- at the top and bottom of the circle)
how does one motivate the Poincaré distance?
Radial lines through the origin should be isometric to R
Similarly circles meeting the boundary perpendicularly should also be geodesics and isometric to R
I think that determines the distance up to a constant maybe
@love_sodam think of it in terms of the principal curvatures.
If you have a normal vector at the point with zero Gaussian curvature, then at least one of the principal curvatures is zero, and in the corresponding principal direction, the surface looks "flat" relative to this normal vector.
But the other principal curvature does not have to be zero.
18:24
@schn it says in the example, $F_{\theta}$ is completely unspecified. Say, $\theta$ is the true parameter of the distribution. How could you know anything about the distribution if you don't know anything about the parameters? I think it's basically saying that you need more data, more samples, to gain information about the parameter and hence about the distribution
maybe someone else can help better
@geocalc33 Thanks, helped clarify it a bit.
So the dimension should be dropped
@anakhro: I'm not sure what your context is. If you're talking about the shape operator, you have a submanifold and a normal-bundle valued second fundamental form. It's the Gauss equation that relates curvature tensor of submanifold, curvature tensor of ambient manifolds, and second fundamental form.
@love_sodam No, not planar points. Think of a cylinder. As anakhro said, you have only one principal curvature $0$; planar points they're both $0$.
18:40
Ok then what does it suggest?
hmm, interesting
What does what suggest?
but is there, say, a "geometric" interpretation of the hyperbolic length of a curve?
There's a cross-ratio interpretation, @Thor.
See Section 3.2 of my diff geo notes.
I have the dumbest question
how do you write f(x,y)=(2x,3y) as a function
18:45
oh, that sounds nice, I'll take a look
Oh, sorry, @Thor: That's for the distance between two points (i.e., length of geodesic). For a random curve, I have no answer.
I mean, if you have a Riemannian metric, length of curve is length of curve.
that suffices, I'm just trying to get a minimal understanding of what Schwarz-Pick says geometrically
Schwarz-Pick says that holomorphic maps are distance-decreasing.
Infinitesimally, the pullback of the metric is less than or equal to the metric.
You can reduce that to a statement about geodesic lengths, so my original comment probably does apply.
so it's fine as f(x,y) but I want it in an explicit form
That's as explicit as it gets, @geocalc.
18:49
like f(x,y)=2x+3y
You're talking nonsense.
I want to prove that a map is Lipschitz though
So? Can't be any simpler than a linear transformation.
what about the nonlinear cases? for example $f(x,y)=(2^x,3^y)$ or something
Any $C^1$ function is Lipschitz on a compact set. Otherwise, not true.
18:59
Consider the log-likelihood function of a normal distribution, which is optimized to find maximum likelihood estimators. It is a function of $\mu$ and $\sigma$. As a function of $x$, it is of course positive definite and a maximum exists. However, as a function of the other two, it seems less obvious. What are some arguments for a maximum to exist?
yeah, I just have to understand how the distance works in the first place for the statement "distance-decreasing" to become meaningful
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