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00:16
5
Q: Analytic continuation of $\Phi(s)=\sum_{n \ge 1} e^{-n^s}$

geocalc33While discussing theta functions, I thought: $\zeta(s)=\sum n^{-s}=1+2^{-s}+3^{-s}+ \cdot\cdot\cdot$ and $\Phi(s)=\sum e^{-n^s}=e^{-1}+e^{-2^s}+e^{-3^s}+\cdot\cdot\cdot $ What is the analytic continuation of $\Phi(s)?$ User @reuns had an insightful point that maybe, $\sum_n (e^{-n^{-s}}-1)=\sum...

I am pretty sure that this question makes no sense, \textbf{but}:
Do you have any examples of "natural things" that exhibit a homotopy in a "plain" way?
As an example, I imagine a [line segment thingy] getting collapsed to a [point thingy] or vice versa
I would consider an example on the lines of deformation retraction from X x I to X as also plain. But, as a bad follow-up to a bad question, I try to imagine something that visually, mentally feels correct. For (a pretty bad) example, if I asked about a natural thing which exhibit a sphere in a plain way, you can say orange that would be nice, apple is pretty good, banana is in some sense correct but not really what I am trying to feel.
An elastic object (I imagine something like a string that bounce back or some water that takes back it's natural form), at least for me, is a good picture for homeomorphism but I am specifically looking for something not homeomorphic
I don't think you're going to get an answer homie. You need to ask a math question. As it stands it's very unclear what you're looking for.
@KonformistLiberal Does the doughnut-mug example not work for this?
@Fargle but they are homeomorphic, aren't they?
(@MikeMiller just want to try my chance :) I hope it's not polluting the platform)
The images are homeomorphic, but you also have two maps $f,g : S^1 \times S^1 \to \Bbb R^3$ (the embeddings of the torus that give the doughnut and the mug, respectively) that are homotopic
00:28
@Fargle But this is (essentially) an example of three spaces which are homeomorphic and the two homeomorphisms are naturally homotopic, I basically want a stretch/collapse [change in "dimension"] movement
I mean, I don't know that you're going to be able to find any "physical" examples without getting at least a little bit abstract with it.
e.g. remove the stem from an apple and stab straight through the core from top all the way to bottom; then the surface of this apple def rets onto a circumference of the apple.
@Fargle I see, I was imagining an example where we can forget about some details and then it abstractly hit the point - Maybe something like a balloon?
@Fargle More random thoughts:
- Example for a "pure" stretch movement
- Something that naturally collapses to it's minimal cell structure up to homotopy
- Something like building an and/or gate with transistors
01:38
300 point bounty for anyone that knows group theory !!!
9
Q: How to identify the vanishing two-electron integrals by making use of the point group symmetry?

nougakoThe number of all two electron integrals $$ \langle \phi_1 \phi_2|\phi_3\phi_4 \rangle = \int d^3\mathbf r' \int d^3\mathbf r'' \, \phi_1(\mathbf r'') \, \phi_2(\mathbf r') \frac{1}{|\mathbf r' - \mathbf r''|} \, \phi_3(\mathbf r') \, \phi_4(\mathbf r'') $$ for $N$ number of basis functions (I am...

Bob
Bob
01:53
anybody good with trig? can you help with this question:
0
Q: Finding the derivative of a trigonometric function using implicit differentiation

BobProblem: Find $\frac{dy}{dx}$ by implicit differentation for the following: $$ y^2 = \sin^4{2x} + \cos^4{2x} $$ Answer: \begin{align*} 2y \frac{dy}{dx} &= 4(2) \sin^3(2x) \cos(2x) - 4(2) \cos^3(2x) \sin(2x) \\ y \frac{dy}{dx} &= 4 ( \sin^3(2x) \cos(2x) - \cos^3(2x) \sin(2x) ) \\ y \frac{dy}{dx} &...

02:13
@robjohn hi sir
any help on this?
03:02
what happened so that the math would be stretched like that
2
If you can't give a good screenshot, please type instead. The question is, how many solutions are there of $2\cos(x/4) = 4^x + 4^{-x}$? And it seems that there are two choices $0$ or $1$. You should check $x=0$.
@Yuvraj: Make the little bit of effort to type the question(s) in MathJaX. Come on.
3
03:49
Hi @Ted
ok $2cos{x/4}=4^{-x}+4^{x}$
i need to find the number of solution for $x$
@TedShifrin
@CalvinKhor indeed 0 is a solution what about other
i i try to use $4^x=t$ so that i can get a quadratic equation
I already completely solved the problem, because the only options are 0 and 1
04:07
options c,d are not in the pic i uploaded @CalvinKhor
@Yuvraj then this makes your picture even worse...
anyone can say that 0 would be one of the solution but i asked what about the other
@Yuvraj if you want people to help you, at the barest of bare minimums put up a bad picture containing the whole question?
Anyone can also say that the RHS is even and uniquely minimised at x=0 while te LHS≤2 so there's nothing left to be said
mathematics is not about the option you have in the answer it is about the question which is in clear picture now
04:43
Howdy, a @Balarka.
@Yuvraj: I suggest you minimize your attitude.
6
@Calvin gave you the correct answer. The largest $2\cos(x/4)$ can be is $2$. The smallest that $4^x+4^{-x}$ can be is $2$. Therefore ...
@TedShifrin sorry if I sound rude or misbehaving
@TedShifrin I have been pondering on the representation variety
Hi yall! It's been a while. I was snooping around in the cPython implementation and found that they use a particular sequence to generate all $2^n$ elements. Could anyone take a look real quick at this puzzle? I have no idea how to approach it :P math.stackexchange.com/questions/3771774/…
05:32
My book says for a problem '1. show that to leading order x goes as 9f^2.' I'm not sure how to parse or interpret 'goes as' and am unsure about what leading order means.
Another problem says 'Calculate h as a function of x and show that to leading order it goes as 21x^2.'
 
1 hour later…
06:55
Hello, I am new to MSE, can someone explain me what happens in a chat room and it's purpose , etc and should I introduce myself ?
@Shubhangi no you don't need to introduce
here we chat about problems
 
1 hour later…
07:58
Hi everyone. Can someone tell me what will be solution of tanx = x. I need only approx solutions in general form. I found somewhere that x = (2n+1)π/2 is its general solution. I can consider it for all values of n but at n = -1, I get π/2. But from graph it does not look like it's solution. Can someone explain me about it ?
Is anyone active in the group currently ?
 
2 hours later…
10:10
@Thorgott @Alessandro you'll be happy to know I finished writing my talk at 10am this morning and am giving it today at 4pm hahahaha
wish me luck
excited to have the lecturer rip me to shreds
10:30
good luck man
timing on point
what is a good measure of fluctuations of a variable $y=f(x)$ I want to show that as I incease x fluctuations increase too. don't know how to quanitfy that
11:37
f(t) measures the total amount of rainfall at time t at the Municipal Airport. Is this function continuous or discontinus?
It seems to me it is discontinus , but I am not able to find ll
Proper mathematical argument
you're gonna have trouble finding a proper mathematical argument for something that is not a proper mathematical question
12:23
@EdwardEvans the Italian way
Good luck!
12:45
Just food for thought
 
2 hours later…
14:40
hey chat
I'm learning "topological notions" in my real analysis course
there are two definitions
if X is your topological space, a point $x \in X$ is called adherent to the set $Y$ if every open set $U \supset \{x\}$ is such that $U \cap Y \ne \emptyset$
moreover, $x \in X$ is called an accumulation point of $Y$ if for every $U \supset \{x\}$ there's an $y\in Y, y \ne x$ s.t. $y \in U$
now, take $X = \mathbb R^2$ with the open ball (usual) topology
 
2 hours later…
16:26
Lucas really left us with this huge cliffhanger
4
@robjohn Can you please help me with latex rendering in Telegram app? I followed the instructions this reddit thread but didn’t get the desired results.
I didn’t get the latex images as it is said in reddit that I ought to get.
17:13
@Alessandro thanks :) think I got a 1
nice!
:D or maybe a 2, the lecturer basically said the mathematical
I mean, "What? Only 1 point? That sucks man"
content was perfect but there were some points where my explanations were weird
So maybe somewhere between 2 and 1 rofl
Press your thumbs for me
@Thorgott lel
Nice, well done
17:17
If you hadn’t wished me good luck I’d have gotten a 5
Obviously
Can someone tell me what is this geometry?
17:30
The convex hull of a collection of n equidistant points in Euclidean space forms a regular (n-1)-simplex
The only way to pick 4 points in R^3 so that they're all 1.5m apart is in the form of a tetrahedron
Of course, they mean >1.5 on all of those arrows, lol
17:45
Is it possible to construct a periodic sequence from Tribonacci numbers?
@Knight I'm not on Reddit. Can you explain some?
A cylinder is like a circle but with height. What is the trapezoid version of that called?
@StanShunpike closed gutter?
I'd just call it an extruded trapezoid.
that's a good name
@StanShunpike If you had a rectangle instead of trapezoid I think it is called a parallell epiped.
17:47
extruded is the right word
thanks!
@MatsGranvik modulo something, it should be periodic.
@MatsGranvik what is the recurrence you are looking at?
@robjohn The kind of Tribonacci numbers from this series expansion:
CoefficientList[Series[1/(1 - x - x^2 - x^3), {x, 0, 12}], x]
@Knight use @inlatexbot
it works inline too
I am interested in Cassinis identity:
https://proofwiki.org/wiki/Cassini%27s_Identity
There is a result in the OEIS that gives an analogous formula, but it does not use a periodic sequence in the numerator.
Not that I know if it is necessary to have it periodic, but the version I read in the OEIS here:
t = 1 - Sum_{k>=1} A057597(k+2)/(T_k*T_(k+1)), where T_n = A000073(n+1). - Vladimir Shevelev, Mar 02 2013

I don't know how to generalize this:
$F_{k + 2} F_k - F_{k + 1}^2 = \left({-1}\right)^{k + 1}$
@StanShunpike A frustum of a (right circular?) cone.
17:55
To apply it to the Riemann zeta zeros.
@MikeMiller you can also put them on the surface of a very small planet
like in the little prince
@Sophie Sure, but the hull of their points still forms a tetrahedron contained in that planet
nods
Hi @MikeM @Sophie
Hello
btw what's the object on your profile pic?
Ah, it's an interesting shape. Any guesses? Hint: You obtain that shape by rotating some object about an axis.
18:05
hmm I can't see immediately give me more time
Bien sûr.
wait and by rotation, you don't mean continuous rotation like in a solid of rotation right. It has to be making several but a finite number of copies
I mean one three-dimensional object.
oooo I see now
18:09
@TedShifrin hey Ted!
it's a paralelepiped
Heya @Stan
I'm trying to figure out the mass moment of inertia for a trapezoidal prism
not sure where to start
A particular sort, @Sophie.
I have the moment of inertia for a box
18:09
a cube?
Yes @Sophie
ah that's satisfying...for some reason I was seeing it as being longer in the y direction
this is the shape
Oh, I misinterpreted your earlier question, @Stan. Moment of inertia about what axis? I don't know anything easy other than doing the triple integral. (I mean, you can use the parallel axis theorem, but you still have to do a nontrivial integral.)
@Sophie: Note that the hyperboloid in the middle section is doubly ruled, in case you didn't know that.
18:11
@TedShifrin in this picture, my axis of rotation would be parallel to the side with length $l$
I have no words of wisdom. Just set up coordinates and compute.
@TedShifrin the triple integral is fine, the problem is i don't know how to set it up lol
Obviously, put that axis along one of the coordinate axes.
so far i've done, box, cyldiner and sphere
i was thinking of doing it for a trianglular prism
I would put the $l$ side along the $z$-axis and set up a trapezoid in the $xy$-plane. You can set up that double integral.
18:13
ok i'll go try and come back
Are you doing an axis through the center of mass, @Stan? If so, set the trapezoid up symmetric about the $y$-axis, say.
@TedShifrin i was planning to do it through the center of mass and then use the parallel axis theorem to translate it
I'm using this trapezoidal prism to replace the top bar of my 4 bar linkage model
its supposed to be the pelvis of a human
OK, so then you obviously want the center of mass of the trapezoid to be at the origin. So begin by finding the center of mass of a trapezoid. :)
oh i didn't think of that. ok great i'll do that first. :) thanks!
You probably can figure that out knowing rectangles and triangles and do a weighted sum.
18:38
Has anyone here voted for a mod? I have marked first and second choice, but I don't see a place to click to say "Register my votes." In the past, I don't recall having a problem.
Marking your choices does register your votes
Ah, OK. So I guess it's left until the end of the voting period in case one changes one's mind?
Thanks, @Mike.
Yeah I think so
I don't berember being confused in past elections.
I don't have an account anymore, so it's none of my concern.
18:41
Oh, really? You can chat anonymously with your name?
It's an MO account, but no MSE account.
You only need an account somewhere on the network.
Ah, gotcha.
Right.
19:10
Of course, @robjohn, you destroy my mystery with that version.
Knowing that the middle portion is doubly-ruled tells you precisely what the shape has to be.
@robjohn that is so cool
what is that?
19:26
If you have fiddled long enough with a Rubik's cube you'll have noticed this
Pretty cool
20:01
@Stan: That's what my icon (or whatever it's called) is.
I guess when I first adopted that icon 6 or 7 years ago, we had lots of discussion about it.
I realize that very few of today's chatroom denizens were old enough back then :D
20:12
@TedShifrin oh cool! yours looks like its squeezed region around the middle is a bit tighter from the thumbnail so i wasn't sure if they were the same
1
Q: Identification of injective linear maps with image and inclusion

orientablesurfaceSuppose $S$ is an immersed submanifold of $M$. Let $\iota: S\hookrightarrow M$ be the inclusion map. Since it is an immersion, at each $p\in S$, $\iota_{*}:T_pS\rightarrow T_pM$ is injective. Hence we identify $T_pS$ with its image under $\iota_{*}$ . Under this identification, $\iota_{*}$ is the...

@StanShunpike Different perspective, of course.
They're saying that if you think of $T_p S$ as a subspace of $T_p M$, then the differential of $\iota$ is just the map that takes a vector $v \in T_p S$ to the corresponding vector $v \in T_p M$. This makes the most sense (to me) when you think of tangent vectors as velocity vectors, aka, the derivative of a curve living in $S$ (or $M$).
Right, I understand that's what they mean. However, i'm not completely convinced.
Maybe you want to call the image of $S$ a different name, $\bar S$, say. Then $\bar S$ is (at least locally) a submanifold and you definitely have the inclusion map $\bar\iota\colon\bar S\to M$, and the derivative of the inclusion map is the (linear) inclusion map.
I guess we can't guess where your stumbling block is.
20:25
I suppose my question is, is there a rigorous way to show that $\iota_{*}$ is an inclusion map
That's what I just wrote.
By $S$ you mean the tangent space, right?
No.
What is the definition of the inclusion map?
$\iota(v)=v$
(I'm trying to avoid having you write this out in local coordinates, but you can always do that.)
I'm talking about the map of manifolds, so $v$ is a bad letter.
20:27
where $\iota: A\rightarrow B$ and $A\subseteq B$
But, yes, if you restrict to $\bar S$, it is the "identity map" (with the codomain a larger set).
What's a tangent space
So if you apply the derivative to any tangent vector, it's the identity map on that, again with codomain a larger vector space.
not to have too many cooks working on this stew
@MikeMiller space of derivations, where derivations are defined on germs of smooth functions
20:30
in that language, what's the inclusion map $T_p S \to T_p M$ of a submanifold $S \subset M$?
I'm leaving to brave the world and do some shopping, @Mike. I leave you.
I'll be gone soon too. I'll stay for a few minutes though.
it's just a tautology, if $\iota\colon A\rightarrow B$ is injective and you identify $\iota(A)$ with $A$, it's the inclusion map of $\iota(A)\subseteq B$
your mommie tautology
21:23
Greetings everyone, I have a question, given that 4a+3b+2c=40 has solutions such that a,b,c, are whole numbers, how should one proceed. I did it using the multinomial theorem but is there a better way, i read about euclidean but it didnt seem helpful, thanks
21:36
@robjohn is there a name for that surface traced out by the rotating cube?
@TedShifrin: I just updated that image in my answer. I had to do a bunch of code changes to get Mathematica to produce the same output, but get the equatorial line correct.
@geocalc33 on this page the part in the middle is called a hyperboloid of one sheet. The caps are cones.
@robjohn can I use that animation in a question?
@geocalc33 Sure. Attribution would be good.
21:52
@robjohn of course
22:10
@geocalc33 I have added a higher resolution animation if you click on the smaller one.
22:30
@robjohn I put the question in my algebra book back in the 80's, asking what shape one obtains. I don't think I ever saw that 2012 question before, though :P
As I indicated above, I'm very fond of it because of the doubly-ruled central portion (and I proved in the algebra book what such surfaces had to be).
I guess it's sort of interesting that 2 parts are singly ruled (but flat/developable) and the third part is doubly ruled.
Obvious, of course, once you know where the surface came from.
23:01
@TedShifrin The old animation bothered me because it missed part of the equator mesh. When I got a newer version of Mathematica, I was dismayed to see that the color scheme had changed, and that the Export did not produce as nice a result. I figured out today how to overcome both of those problems, and so I updated the image and added a high res image (shown when clicking on the smaller image).

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