Let $f(x)=x^3-1$. To approximate the root $x^{\star}=1$, we consider the sequence $(x_n)$ that we get if we apply Newton's method with $x_0>0$. Show that the sequence converges to $1$.
I used $x_0=0,5$ and applied the method and in that way we see that the sequence converges to $1$.
Is that correct?
An other way could be: From Newton's method we get $x_{n+1}=\frac{1}{3x_n^2}$ and we have to show that this sequence converges to $1$, or not?