« first day (3543 days earlier)      last day (1774 days later) » 

22:00
I'm saying he is sloppy about naming his hypotheses that he uses, at least in the edition I have.
So the proof uses $f$ continuous and $D_1 f$ continuous, even though he doesn't state that.
I quit on that source.
I was surprised to find out Mary Rudin was Moore's student? @TedShifrin
Why surprised? How many "big names" do we know in the point-set world?
I would put Moore in there.
Bing was actually more geometric :P
yeah i was joking
22:04
lol
Now you're making me want cherries.
He only ever needs continuity in one variable at a time, which is guaranteed by differentiability in that variable, no?
I always found it funny how "R. H." in R. H. Bing doesn't stand for anything
srsly?
Yeah look it up
22:08
I trust you, pal
Bing's father was named Rupert Henry, but Bing's mother thought that "Rupert Henry" was too British for Texas. Thus she compromised by abbreviating it to R. H. (Singh 1986)

It is told that once Bing was applying for a visa and was requested not to use initials. He explained that his name was really "R-only H-only Bing", and ended up receiving a visa made out to "Ronly Honly Bing".[4]
Oh, you're probably right, @Thorgott. His screwy notation confused me.
Reminds me of B.J. Honeycut on MASH. :)
They had a whole episode in which Hawkeye was obsessed with what the B.J. stood for.
Yeah, the notation is ugly, but I believe the argument does check out with the hypotheses given.
> His full name remained a mystery throughout the series. He claimed (in the Season 7 episode "Lil") - perhaps in jest - that he was named after his mother Bea and father Jay (hence Bea-Jay = B.J.).
22:19
I have to confess that, in general, worrying about the most general statements possible doesn't interest me that much, since in most cases we have stronger hypotheses. Now somebody(s) can prove me wrong.
@skull: Yes, I know about the parents. I remember the punch-line.
TIL :-)
It can be pretty interesting
I'm still amazed that everywhere differentiability instead of $C^1$ suffices for the Inverse Function Theorem
I worked that out once but promptly forgot about it
I don't think I have ever used these results
@Thorgott Wild. Immoral
That isn't quite right, @Thorgott. I think someone in this chat pointed us to a post by Terry Tao. But the usual counterexample shows you need to assume differentiability PLUS more (one-to-one?).
22:26
iirc you just use Brouwer fixed point theorem to find the fixed point instead of contraction mapping in the usual proof
But something needs to be assumed. Or else the usual $f(x) = x/2 + x^2\sin(1/x)$ gives a counterexample.
You want the derivative to be invertible everywhere
By everywhere I mean on a neighborhood
Oh. That'll do it.
@BalarkaSen I hate it
Yeah, I meant "the usual assumptions with $C^1$ replaced by everywhere differentiable"
22:29
I always have pedagogical issues to raise. Some general results are great, but I don't necessarily think that they're right for students seeing them the first time. That's what bothers me so much about Hubbard & Hubbard in places.
@Thorgott No, the usual inverse function theorem assumes invertibility of the derivative at a single point
@Thorgott The useful assumption is that $Df$ is invertible at a specific point, though
Right.
So that one can compute less :D
@TedShifrin I have never used these things so I concur
I just forget about things I don't use
What's the point
22:31
Oops, I had missed that detail
It's OK, @Thorgott. You're still ahead a point on me :P
match point?
or set point
Let's just write down a concrete theory of multivariable calculus on a topos instead
smacks Balarka
which arithmetic site?
22:33
the Nisnevich site
over a perfectoid space of $\ell$-adic character
Smacking Balarka: A Geometric Approach
8
Geometric Geometry: An Algebraic Approach
no "al"
You guys wouldn't have nearly so much fun without Ted upon whom to pick.
It's not really picking, it's such a good, reusable meme
We love and adore it
I wonder what happened to Hippa, he was easily the best at this
He's an algebraist now
I assume, at least. He was French
22:38
yeah, he was a natural
@Astyx knows Hippa I think
They're both at Polytechnique
oh so he good good
We all met for lunch in Paris a few years ago.
I'm forgetting one other person.
Gabriel?
I can't remember people who quit showing up.
22:39
Maybe I should do that
Pedro?
You did that for a year or more.
No, Pedro I met in the US.
yeah... didn't turn out well for me
He schooled me in math and tennis, but he got some good food out of it (and met Pete Clark).
Well, I did miss you, a @Balarka.
coolio
22:41
I chased him off as best I could but he's persistent
You chased you off, too, Mike, but then ....
what was he persistent about?
$\ell$-adic sheaves
returning
Balarka is like the Poincaré return map and ergodic flow.
22:43
anon never returned
I certainly hope I'm not pseudo-Anosov
You might be, Balarka. Geodesic flow and all.
Ergodicity is fine as long as I'm not mixing with people
If you know what I mean
I wonder what happened to anon. Did he go to grad school? Crazy if not.
LOL, a @Balarka.
Oh btw Garbiel's other name was
Le Grand DODOM
whatever that means
22:45
oh, right, dodo ...
I just realized I
And hippa's younger brother disappeared, too.
oh right he brought his younger brother lmao
good times
I tried to bring my younger brother but he doesn't like math
it took me a while to adjust to this site
I asked a lot of stupid questions lol
God im hungry
its 4 am
what to eat holy shit
22:50
eat a tomato
thats the last thing you should eat if you're hungry
\o @MonaJalal welcome
2
Hi @skul
Hi @skullpatrol
23:16
How's the Covid situation in Iran @MonaJalal?
Hi there, I have a problem that I think is rather simple. Consider to matrices A and B. If i know that $R(A) \subseteq R(B)$, what can I say about the matrices? Here $R(A)$ is the range/image/span of $A$.
23:34
@BalarkaSen I can't tell any of the French people apart
@Martin Very little other than that the rank of $A$ is at most the rank of $B$, it seems to me. For instance, if $\det B$ is nonzero, then $A$ can be any matrix.
@MikeMiller I am going to go read what Henri Villani and Pierre de Poincare has to say about the hyperbolic plane
@MikeMiller Sure, we can't say much "new". But I was thinking about different ways to represent this. I have come to the conclusion that any column of $A$ can be written as $Bx$ for some $x$. I am not entirely sure, do you agree?
$Ae_j$ is the $j$'th column of $A$, so $Ae_j \in R(A)$. We are given that $R(A) \subset R(B)$, and $R(B)$ is the set of vectors of the form $Bx$, so yes, that's right
@MikeMiller Thanks for the sanity check, I think its time to go to bed soon :)

« first day (3543 days earlier)      last day (1774 days later) »